Problem 38
Question
Differentiate $$ g(N)=r N\left(1-\frac{N}{K}\right) $$
Step-by-Step Solution
Verified Answer
The derivative is \( g'(N) = r - \frac{2rN}{K} \).
1Step 1: Identify the Derivative Rules
The function is given as \( g(N) = rN(1 - \frac{N}{K}) \). Here, \( r \) and \( K \) are constants. You'll be using the product rule for differentiation, which in general for two functions \( u(N) \) and \( v(N) \) is given by \( (uv)' = u'v + uv' \). Here, let \( u(N) = rN \) and \( v(N) = (1 - \frac{N}{K}) \).
2Step 2: Differentiate Using the Product Rule
Differentiate \( u(N) \): \( u(N) = rN \Rightarrow u'(N) = r \). Next, differentiate \( v(N) \): \( v(N) = 1 - \frac{N}{K} \Rightarrow v'(N) = -\frac{1}{K} \). Apply the product rule: \( g'(N) = u'(N)v(N) + u(N)v'(N) = r(1 - \frac{N}{K}) + rN(-\frac{1}{K}) \).
3Step 3: Simplify the Derivative
Simplify the expression: \( g'(N) = r(1 - \frac{N}{K}) - \frac{rN}{K} = r - \frac{rN}{K} - \frac{rN}{K} \). Combine terms: \( g'(N) = r - 2\frac{rN}{K} \).
4Step 4: Finalize the Derivative Expression
The derivative of the given function is \( g'(N) = r - \frac{2rN}{K} \). This represents the rate of change of the function with respect to \( N \).
Key Concepts
Understanding the Product RuleExploring CalculusMastering Derivative Rules
Understanding the Product Rule
In calculus, the product rule is an essential technique used to differentiate functions that are the product of two or more differentiable functions. The rule states that if you have two functions, say \( u(N) \) and \( v(N) \), their derivative can be obtained using the formula:
This strategy is instrumental because many real-world functions are the result of multiplying different factors that vary with the same variable.
The product rule helps break down these complex relationships into simpler parts, making analysis easier.
- \((uv)' = u'v + uv'\)
This strategy is instrumental because many real-world functions are the result of multiplying different factors that vary with the same variable.
The product rule helps break down these complex relationships into simpler parts, making analysis easier.
Exploring Calculus
Calculus is a powerful branch of mathematics that focuses on studying change. It is divided into two main parts:
Mastering calculus concepts like differentiation is key to understanding and solving real-world problems involving rates of change and dynamic systems.
- **Differential Calculus**: Concerned with finding the rate at which variables change. It deals primarily with derivatives and their applications.
- **Integral Calculus**: Concerned with the accumulation of quantities, such as areas under curves or total accumulated change, using integrals.
Mastering calculus concepts like differentiation is key to understanding and solving real-world problems involving rates of change and dynamic systems.
Mastering Derivative Rules
Derivative rules are fundamental tools in calculus used to compute the derivative at any given point of a function. These rules streamline the differentiation process. Some of the core derivative rules include:
- **Power Rule**: Used for functions raised to a power, \( \frac{d}{dN} [N^n] = nN^{n-1} \).
- **Constant Rule**: If \( c \) is a constant, then \( \frac{d}{dN} [c] = 0 \).
- **Sum Rule**: The derivative of a sum is the sum of the derivatives, \( (f+g)' = f' + g' \).
- **Product Rule**: As seen, applied to products of two functions.
- **Quotient Rule**: Used for functions divided by another, \( \frac{d}{dN} \left[ \frac{f}{g} \right] = \frac{f'g - fg'}{g^2} \).
Other exercises in this chapter
Problem 38
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