Problem 38
Question
Calculate the derivative of the given xpression with respect to \(x\). $$ \sin \left(\pi^{x}\right) $$
Step-by-Step Solution
Verified Answer
The derivative is \( \pi^x \ln(\pi) \cos(\pi^x) \).
1Step 1: Identify the Composition
The given expression is \( \sin \left( \pi^x \right) \). It is composed of the sine function and the exponential function. We can identify it as a composition of the outer function \( f(u) = \sin(u) \) and the inner function \( u(x) = \pi^x \).
2Step 2: Differentiate the Outer Function
Differentiate the outer function \( f(u) = \sin(u) \) with respect to \( u \). The derivative of \( \sin(u) \) is \( \cos(u) \). So we have \( f'(u) = \cos(u) \).
3Step 3: Differentiate the Inner Function
Differentiate the inner function \( u(x) = \pi^x \) with respect to \( x \). The derivative is obtained using the exponential differentiation formula: \( \frac{d}{dx}(a^x) = a^x \ln(a) \). Thus, \( \frac{d}{dx}(\pi^x) = \pi^x \ln(\pi) \).
4Step 4: Apply the Chain Rule
Combine the results using the chain rule. The derivative of the composite function \( \sin(\pi^x) \) is \( f'(u) \cdot u'(x) \). Therefore, we have \( \frac{d}{dx}(\sin(\pi^x)) = \cos(\pi^x) \cdot (\pi^x \ln(\pi)) \).
5Step 5: Express in Simplified Form
Multiply the expressions from Step 4 to get the final derivative. Thus, the derivative is \( \pi^x \ln(\pi) \cos(\pi^x) \).
Key Concepts
Chain RuleExponential FunctionsTrigonometric Derivatives
Chain Rule
The chain rule is an essential technique in calculus used to find the derivative of composite functions. A composite function is one where one function is nested inside another, like the \(\sin(\pi^x)\) in our exercise. The chain rule allows us to differentiate such functions efficiently.
To use the chain rule, follow these steps:
To use the chain rule, follow these steps:
- Identify the inner and the outer functions. In our expression, the inner function is \(u(x) = \pi^x\) and the outer function is \(f(u) = \sin(u)\).
- Differentiate the outer function with respect to its variable. This means calculating \(f'(u)\) which for \(\sin(u)\) is \(\cos(u)\).
- Next, differentiate the inner function with respect to \(x\). Thus, the derivative of \(u(x) = \pi^x\) is \(\pi^x \ln(\pi)\).
- Finally, combine these derivatives using the chain rule formula: \(f'(u) \cdot u'(x)\). This means multiplying \(\cos(\pi^x)\) by \(\pi^x \ln(\pi)\).
Exponential Functions
Exponential functions are a class of functions where a constant base is raised to a variable exponent, usually expressed as \(a^x\). In our problem, the base is \(\pi\) and the exponent is \(x\), giving us the function \(\pi^x\).
Exponential functions have unique properties:
Exponential functions have unique properties:
- They grow (or decay) very quickly, depending on whether the base is greater or less than one.
- Their derivatives record this rapid rate of change.
- For derivative purposes, the formula \(\frac{d}{dx}(a^x) = a^x \ln(a)\) is paramount. This expression captures the essence of how exponential functions change.
- In our specific exercise, the derivative of \(\pi^x\) involves \(\ln(\pi)\), which accounts for the base \(\pi\). This natural logarithm of the base scales the rate of change of the original function.
Trigonometric Derivatives
Trigonometric functions, like sine and cosine, are foundational in calculus for modeling periodic phenomena. In our expression \(\sin(\pi^x)\), we deal with the sine function. The sine, being a smooth periodic function, has a well-known derivative:
- The derivative of \(\sin(u)\) with respect to \(u\) is \(\cos(u)\). This relationship reflects how the slope of the sine wave changes as it cycles around.
- When paired with the chain rule, this particular derivative helps us manage complex expressions like \(\sin(\pi^x)\).
Other exercises in this chapter
Problem 38
Find the tangent line to the parametric curve \(x=\varphi_{1}(t), y=\varphi_{2}(t)\) at the point corresponding to the given value \(t_{0}\) of the parameter. $
View solution Problem 38
A velocity \(v(t)\) is given. Calculate the acceleration (in \(\mathrm{m} / \mathrm{s}^{2}\) ). \(v(t)=t^{2}-5 t \mathrm{~m} / \mathrm{s}\)
View solution Problem 38
A function \(f\) and a point \(P\) are given. Find the slope-intercept form of the equation of the normal line to the graph of \(f\) at \(P\). $$ f(x)=x^{3} / 2
View solution Problem 38
Use the Quotient Rule to compute the derivative of the given expression with respect to \(x .\) $$ (x+\sin (x)) /(x+\cos (x)) $$
View solution