Problem 38
Question
An ideal gas is expanded from \(\left(P_{1}, V_{1}, T_{1}\right)\) to \(\left(P_{2}, V_{2}, T_{2}\right)\) under different conditions. The correct statement(s) among the following is (are) (a) The work done on the gas is maximum when it is compressed irreversibly from \(\left(P_{2}, V_{2}\right)\) to \(\left(P_{1}, V_{1}\right)\) against constant pressure \(P_{1}\) (b) If the expansion is carried out freely, it is simultaneously both isothermal as well as adiabatic (c) The work done by the gas is less when it is expanded reversibly from \(V_{1}\) to \(V_{2}\) under adiabatic conditions as compared to that when expanded reversibly from \(V_{1}\) to \(V_{2}\) under isothermal conditions (d) The change in internal energy of the gas is (i) zero, if it is expanded reversibly with \(T_{1}=T_{2}\), and (ii) positive, if it is expanded reversibly under adiabatic conditions with \(T_{1} \neq T_{2}\)
Step-by-Step Solution
VerifiedKey Concepts
Ideal Gas Law
- P is the pressure of the gas
- V is the volume of the gas
- n is the number of moles
- R is the ideal gas constant
- T is the temperature in Kelvin
It assumes that the gas particles do not interact with each other and occupy no volume, which is a useful approximation for many gases under normal conditions.
Adiabatic Process
In contexts like reversible adiabatic expansion:
- The system's temperature changes as a result of energy being used or work being done internally.
- The work done by or on the gas results in a change in temperature, as seen in the statement about energy use for adiabatic conditions.
Isothermal Process
- In an isothermal expansion, the gas absorbs heat from the surroundings.
- In an isothermal compression, heat is expelled to the surroundings.
Internal Energy
- In an isothermal process, the temperature, and hence the internal energy, remains constant. That means no change occurs in internal energy unless the temperature changes.
- In adiabatic processes, if temperature changes, the internal energy changes accordingly, often decreasing due to work done by the system without heat exchange.
Work Done
For an isothermal process, work done is calculated using:\[W = nRT \ln\left(\frac{V_f}{V_i}\right)\]This formula assumes constant temperature (isothermal), considering the reversible nature of the expansion.
In adiabatic processes, since there is no heat exchange, the work done results in a change in internal energy rather than a simple transfer of heat:\[W = \frac{P_iV_i - P_fV_f}{\gamma - 1}\]
- Isothermal expansion involves more work as energy is continuously transferred to maintain temperature.
- Adiabatic conditions, however, have less work done due to the energy being partitioned into changing the system's temperature, which is noticed in process comparisons mentioned in statement evaluations.