Problem 38
Question
A particle starts at \(A(6,0)\) and its coordinates change by increments \(\Delta x=-6, \Delta y=0 .\) Find its new position.
Step-by-Step Solution
Verified Answer
The particle's new position is \((0,0)\).
1Step 1: Understand the Given Coordinates
The particle initially starts at point \(A(6,0)\). This means the starting \(x\)-coordinate is 6 and the starting \(y\)-coordinate is 0.
2Step 2: Identify the Changes in Coordinates
The increment for the \(x\)-coordinate is given as \(\Delta x = -6\), which means that 6 will be subtracted from the \(x\)-coordinate. The increment for the \(y\)-coordinate is \(\Delta y = 0\), indicating there is no change in the \(y\)-coordinate.
3Step 3: Apply the Changes to the Coordinates
Subtract \(\Delta x\) from the initial \(x\)-coordinate: \(6 - 6 = 0\). Keep the \(y\)-coordinate unchanged since \(\Delta y = 0\). Therefore, the new \(y\)-coordinate remains 0.
4Step 4: Determine the New Position
Combine the results from the previous step to determine the new position of the particle. The new coordinates are \((0,0)\).
Key Concepts
Particle MotionCoordinate ChangesPosition Calculation
Particle Motion
In coordinate geometry, understanding particle motion involves tracking how a point, or particle, moves on a plane following specified changes. This concept is fundamental in various fields such as physics, engineering, and computer graphics.
At the start, a particle's position is represented by coordinates, such as the point \(A(6,0)\) in our example. As it moves, the coordinates change based on given increments or decrements. These changes can be expressed as \(\Delta x\) for the horizontal shift and \(\Delta y\) for the vertical shift.
When studying particle motion, it's crucial to grasp how these incremental changes affect the overall position, providing insights into directionality and path taken by the particle. For instance, a negative \(\Delta x\) indicates a move leftward, while a \(\Delta y\) of zero reflects no vertical shift.
At the start, a particle's position is represented by coordinates, such as the point \(A(6,0)\) in our example. As it moves, the coordinates change based on given increments or decrements. These changes can be expressed as \(\Delta x\) for the horizontal shift and \(\Delta y\) for the vertical shift.
When studying particle motion, it's crucial to grasp how these incremental changes affect the overall position, providing insights into directionality and path taken by the particle. For instance, a negative \(\Delta x\) indicates a move leftward, while a \(\Delta y\) of zero reflects no vertical shift.
Coordinate Changes
In the context of coordinate geometry, coordinate changes refer to the adjustments made to a point's position based on specific increments or decrements.
These changes are denoted by \(\Delta x\) and \(\Delta y\), which indicate alterations in the x-axis and y-axis respectively.
These changes are denoted by \(\Delta x\) and \(\Delta y\), which indicate alterations in the x-axis and y-axis respectively.
- Positive \(\Delta x\) values imply a move to the right.
- Negative \(\Delta x\) values imply a move to the left, as seen in our example with \(\Delta x = -6\).
- Positive \(\Delta y\) values imply a move upward.
- Negative \(\Delta y\) values imply a move downward.
Position Calculation
Position calculation is the process of determining the new position of a particle after specified coordinate changes.
To calculate this, simply apply the changes using the formulas:
To calculate this, simply apply the changes using the formulas:
- New \(x\)-coordinate: \(x_{new} = x_{initial} + \Delta x\)
- New \(y\)-coordinate: \(y_{new} = y_{initial} + \Delta y\)
- New \(x\)-coordinate: \(6 - 6 = 0\)
- New \(y\)-coordinate: \(0 + 0 = 0\)
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