Problem 38
Question
A cylinder of compressed gas is labeled "Composition (mole \%): \(4.5 \% \mathrm{H}_{2} \mathrm{S}, 3.0 \% \mathrm{CO}_{2},\) balance \(\mathrm{N}_{2} .\) The pressure gauge attached to the cylinder reads 46 atm. Calculate the partial pressure of each gas, in atmospheres, in the cylinder.
Step-by-Step Solution
Verified Answer
\(\mathrm{H}_2\mathrm{S}: 2.07\ \text{atm}, \mathrm{CO}_2: 1.38\ \text{atm}, \mathrm{N}_2: 42.55\ \text{atm}.\)
1Step 1: Identify given information
The total pressure of the gas mixture in the cylinder is 46 atm. The gas composition is given as 4.5% \(\mathrm{H}_2\mathrm{S}\), 3.0% \(\mathrm{CO}_2\), and the balance is \(\mathrm{N}_2\). Mole percentages can be considered as volume percentages for gases.
2Step 2: Determine partial pressure formula
Partial pressure can be calculated using the formula: \( P_i = X_i \cdot P_{\text{total}}\), where \(P_i\) is the partial pressure for each gas, \(X_i\) is the mole fraction of the gas, and \(P_{\text{total}}\) is the total pressure.
3Step 3: Convert mole percentages to mole fractions
Since percentages can be directly used as mole fractions for gases in standard conditions, convert each gas's mole percentage to a mole fraction: - \( \mathrm{H}_2\mathrm{S}: \frac{4.5}{100} = 0.045 \) - \( \mathrm{CO}_2: \frac{3.0}{100} = 0.030 \) - \( \mathrm{N}_2: 1 - (0.045 + 0.030) = 0.925 \)
4Step 4: Calculate partial pressures of each gas
Using the formula from Step 2, calculate the partial pressure for each gas:- \( \mathrm{H}_2\mathrm{S}: P_{\mathrm{H}_2\mathrm{S}} = 0.045 \times 46 = 2.07 \text{ atm} \) - \( \mathrm{CO}_2: P_{\mathrm{CO}_2} = 0.030 \times 46 = 1.38 \text{ atm} \) - \( \mathrm{N}_2: P_{\mathrm{N}_2} = 0.925 \times 46 = 42.55 \text{ atm} \)
Key Concepts
Partial PressureMole FractionDalton's Law of Partial Pressures
Partial Pressure
The concept of partial pressure is a foundational topic in gas laws. It represents the pressure exerted by a particular gas in a mixture if it alone occupied the entire volume filled by the mixture.
Partial pressure is crucial because it allows us to understand how each gas behaves in a mixture. It's calculated using the formula \( P_i = X_i \times P_{\text{total}} \), where \( P_i \) is the partial pressure of the gas, \( X_i \) is its mole fraction, and \( P_{\text{total}} \) is the total pressure of the gas mixture.
Partial pressure is crucial because it allows us to understand how each gas behaves in a mixture. It's calculated using the formula \( P_i = X_i \times P_{\text{total}} \), where \( P_i \) is the partial pressure of the gas, \( X_i \) is its mole fraction, and \( P_{\text{total}} \) is the total pressure of the gas mixture.
- For hydrogen sulfide (\( \mathrm{H}_2\mathrm{S} \)), if its mole fraction is 0.045 and total pressure is 46 atm, its partial pressure is \( P_{\mathrm{H}_2\mathrm{S}} = 0.045 \times 46 = 2.07 \text{ atm} \).
- Similarly, for carbon dioxide (\( \mathrm{CO}_2 \)), with a mole fraction of 0.030, its partial pressure is \( P_{\mathrm{CO}_2} = 0.030 \times 46 = 1.38 \text{ atm} \).
- Nitrogen (\( \mathrm{N}_2 \)), with the largest mole fraction of 0.925, has a partial pressure of \( P_{\mathrm{N}_2} = 0.925 \times 46 = 42.55 \text{ atm} \).
Mole Fraction
Mole fraction is a way to express the concentration or proportion of a component in a mixture. It is defined as the ratio of the number of moles of a specific component to the total number of moles of all components in the mixture.
Mole fractions are dimensionless numbers that indicate the relative amount of each gas in the mixture. For a gas mixture under standard conditions, mole fractions can often be directly derived from percentage composition data.
Mole fractions are dimensionless numbers that indicate the relative amount of each gas in the mixture. For a gas mixture under standard conditions, mole fractions can often be directly derived from percentage composition data.
- In the given exercise, \( \mathrm{H}_2\mathrm{S} \) has a mole fraction of \( 0.045 \), calculated as \( \frac{4.5}{100} \).
- \( \mathrm{CO}_2 \) has a mole fraction of \( 0.030 \), which equals \( \frac{3.0}{100} \).
- The balance gas, \( \mathrm{N}_2 \), has a mole fraction calculated by subtracting the sums of \( \mathrm{H}_2\mathrm{S} \) and \( \mathrm{CO}_2 \) mole fractions from 1, resulting in \( 0.925 \).
Dalton's Law of Partial Pressures
Dalton's Law of Partial Pressures is a key principle in understanding gas behavior in mixtures. It states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of its component gases.
This law springs from the idea that gas molecules act independently, each contributing to the total pressure, as if it were alone in the entire volume. Therefore, the equation representing Dalton's Law is: \[ P_{\text{total}} = P_{1} + P_{2} + P_{3} + \ldots \]
In the exercise, this concept is used to determine the total pressure from the calculated partial pressures:
This law springs from the idea that gas molecules act independently, each contributing to the total pressure, as if it were alone in the entire volume. Therefore, the equation representing Dalton's Law is: \[ P_{\text{total}} = P_{1} + P_{2} + P_{3} + \ldots \]
In the exercise, this concept is used to determine the total pressure from the calculated partial pressures:
- The partial pressure of \( \mathrm{H}_2\mathrm{S} = 2.07 \text{ atm} \).
- The partial pressure of \( \mathrm{CO}_2 = 1.38 \text{ atm} \).
- The partial pressure of \( \mathrm{N}_2 = 42.55 \text{ atm} \).
Other exercises in this chapter
Problem 36
5\. A self-contained underwater breathing apparatus (SCUBA) uses canisters containing potassium superoxide. The superoxide consumes the \(\mathrm{CO}_{2}\) exha
View solution Problem 37
What is the total pressure in atmospheres of a gas mixture that contains \(1.0 \mathrm{g}\) of \(\mathrm{H}_{2}\) and \(8.0 \mathrm{g}\) of \(\mathrm{Ar}\) in a
View solution Problem 39
A halothane-oxygen mixture \(\left(\mathrm{C}_{2} \mathrm{HBrClF}_{3}+\mathrm{O}_{2}\right)\) can be used as an anesthetic. A tank containing such a mixture has
View solution Problem 40
A collapsed balloon is filled with He to a volume of \(12.5 \mathrm{L}\) at a pressure of 1.00 atm. Oxygen, \(\mathrm{O}_{2}\) is then added so that the final v
View solution