Problem 38
Question
A cylinder of compressed gas is labeled "Composition (mole \(\%): 4.5 \% \mathrm{H}_{2} \mathrm{S}, 3.0 \% \mathrm{CO}_{2},\) balance \(\mathrm{N}_{2} .^{\prime \prime}\) The pres- sure gauge attached to the cylinder reads 46 atm. Calculate the partial pressure of each gas, in atmospheres, in the cylinder.
Step-by-Step Solution
Verified Answer
Partial pressures: H2S = 2.07 atm, CO2 = 1.38 atm, N2 = 42.55 atm.
1Step 1: Understanding Partial Pressures
To find the partial pressure of each gas in a mixture, we use the formula \( P_i = y_i \cdot P_{total} \), where \( P_i \) is the partial pressure of the component, \( y_i \) is the mole fraction, and \( P_{total} \) is the total pressure.
2Step 2: Calculate Total Mole Percentage of Nitrogen
Given that the total mole percentage of gases in the mixture is 100%, and the sum of the mole percentages of \( \mathrm{H}_2\mathrm{S} \) and \( \mathrm{CO}_2 \) are given as 4.5% and 3.0%, the remaining must be \( \mathrm{N}_2 \).Therefore, \( \% \mathrm{N}_2 = 100\% - 4.5\% - 3.0\% = 92.5\% \).
3Step 3: Convert Mole Percentages to Mole Fractions
Mole percentages are converted to mole fractions by dividing by 100%.\( y_{\mathrm{H}_2\mathrm{S}} = \frac{4.5}{100} = 0.045 \) \( y_{\mathrm{CO}_2} = \frac{3.0}{100} = 0.030 \) \( y_{\mathrm{N}_2} = \frac{92.5}{100} = 0.925 \)
4Step 4: Calculate Partial Pressure of H2S
Using the formula for partial pressure: \( P_{\mathrm{H}_2\mathrm{S}} = y_{\mathrm{H}_2\mathrm{S}} \times P_{total} \)\( P_{\mathrm{H}_2\mathrm{S}} = 0.045 \times 46 \text{ atm} = 2.07 \text{ atm} \).
5Step 5: Calculate Partial Pressure of CO2
Using the formula for partial pressure:\( P_{\mathrm{CO}_2} = y_{\mathrm{CO}_2} \times P_{total} \)\( P_{\mathrm{CO}_2} = 0.030 \times 46 \text{ atm} = 1.38 \text{ atm} \).
6Step 6: Calculate Partial Pressure of N2
Using the formula for partial pressure:\( P_{\mathrm{N}_2} = y_{\mathrm{N}_2} \times P_{total} \)\( P_{\mathrm{N}_2} = 0.925 \times 46 \text{ atm} = 42.55 \text{ atm} \).
Key Concepts
Dalton's Law of Partial PressuresMole FractionGas Mixture Composition
Dalton's Law of Partial Pressures
When dealing with gas mixtures, Dalton's Law of Partial Pressures is an essential concept. It explains how the total pressure of a gas mixture is the sum of the pressures that each gas in the mixture would exert if it occupied the entire volume by itself. The formula for the partial pressure of an individual gas component is:
Using Dalton’s Law helps to understand gas behaviors in mixed systems without needing to separate the gases physically.
- \( P_i = y_i \cdot P_{\text{total}} \)
- \( P_i \) is the partial pressure of a specific gas.
- \( y_i \) is the mole fraction of that gas in the mixture.
- \( P_{\text{total}} \) is the total pressure of the gas mixture.
Using Dalton’s Law helps to understand gas behaviors in mixed systems without needing to separate the gases physically.
Mole Fraction
The mole fraction is a way of expressing the concentration of a component in a mixture. It is defined as the ratio of the moles of one component to the total moles of all components in the mixture. Mole fraction has no units, as it is a simple ratio, making it convenient to use in various calculations.
- For a given gas, the mole fraction \( y_i \) is calculated as: \( y_i = \frac{\text{moles of gas } i}{\text{total moles of all gases}} \).
- Mole percentage can be converted to mole fraction by dividing by 100.
- For instance, if the mole percentage of \( \text{H}_2\text{S} \) is 4.5%, its mole fraction is \( \frac{4.5}{100} = 0.045 \).
Gas Mixture Composition
Understanding the composition of a gas mixture involves knowing what gases are present and in what proportions. In the context of the cylinder problem, the labels indicate the composition in mole percentages. To work through problems involving gases, it's crucial to be able to convert these percentages into more useful formats like mole fraction.
- In the original exercise, the gas mixture is comprised of \( \text{H}_2\text{S} \), \( \text{CO}_2 \), and \( \text{N}_2 \).
- Each percentage represents how much each gas contributes to the whole in terms of moles.
- \( \text{H}_2\text{S} \) makes up 4.5 mole%, \( \text{CO}_2 \) makes up 3.0 mole%, and the rest is \( \text{N}_2 \) at 92.5 mole%.
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