Problem 372
Question
Velocity field \(\quad \mathbf{v}=\left\langle 0,1-x^{2}, 0\right\rangle, \quad\) for \(|x| \leq 1\) and \(|z| \leq 1,\) represents a horizontal flow in the \(y\) -direction. Compute the curl of \(\mathbf{v}\) in a clockwise rotation.
Step-by-Step Solution
Verified Answer
The curl of \(\mathbf{v}\) is \(\left\langle 0, 0, -2x \right\rangle\).
1Step 1: Understanding Curl Definition
The curl of a vector field \( \mathbf{F} = \left\langle P, Q, R \right\rangle \) is given by the formula \( abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \). We need to identify \(P, Q,\) and \(R\) from the vector \( \mathbf{v} = \left\langle 0, 1-x^{2}, 0 \right\rangle \).
2Step 2: Identifying Components of \(\mathbf{v}\)
For the given vector field \( \mathbf{v} = \left\langle 0, 1-x^{2}, 0 \right\rangle \), we identify \( P = 0 \), \( Q = 1-x^{2} \), and \( R = 0 \).
3Step 3: Calculating Partial Derivatives
We calculate the required partial derivatives: \( \frac{\partial Q}{\partial x} = \frac{\partial}{\partial x}(1-x^2) = -2x \), \( \frac{\partial P}{\partial y} = \frac{\partial}{\partial y}(0) = 0 \), \( \frac{\partial R}{\partial y} = \frac{\partial}{\partial y}(0) = 0 \), \( \frac{\partial Q}{\partial z} = \frac{\partial}{\partial z}(1-x^2) = 0 \), \( \frac{\partial P}{\partial z} = \frac{\partial}{\partial z}(0) = 0 \), \( \frac{\partial R}{\partial x} = \frac{\partial}{\partial x}(0) = 0 \).
4Step 4: Applying Curl Formula
Substitute the partial derivatives into the curl formula: \( abla \times \mathbf{v} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) = \left( 0 - 0, 0 - 0, -2x - 0 \right) = \left\langle 0, 0, -2x \right\rangle \).
5Step 5: Interpreting the Result
The resulting vector \( \left\langle 0, 0, -2x \right\rangle \) indicates the direction and magnitude of the curl. A negative \( z \)-component signifies a clockwise rotation in the \( xy \)-plane. Therefore, the curl of \( \mathbf{v} \) is consistent with a clockwise rotation around the \( z \)-axis.
Key Concepts
Curl of a Vector FieldPartial DerivativesVelocity Field Analysis
Curl of a Vector Field
In vector calculus, recognizing the curl of a vector field is an important task when exploring the rotation of fluid flows or electromagnetic fields. The curl is essentially a measure of the twisting or angular momentum at a point in the field. For the vector field \( \mathbf{v} = \left\langle 0, 1-x^2, 0 \right\rangle \), it represents a flow moving primarily in the \( y \)-direction. The formula for the curl \( abla \times \mathbf{F} \) is:
\[abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right)\]This tool helps to identify the local spinning effect of the vector field around a point. By understanding how each components \( P \), \( Q \), and \( R \) contribute to this rotation, we can determine the twisting behavior of the vector field.
This can be especially useful in applications such as fluid dynamics to determine the rotational forces present at various points.
\[abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}, \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}, \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right)\]This tool helps to identify the local spinning effect of the vector field around a point. By understanding how each components \( P \), \( Q \), and \( R \) contribute to this rotation, we can determine the twisting behavior of the vector field.
This can be especially useful in applications such as fluid dynamics to determine the rotational forces present at various points.
Partial Derivatives
Partial derivatives serve as the backbone in calculating changes in multi-dimensional functions, which include vector fields. These derivatives give us the rate of change of a function with respect to one variable while keeping the other variables constant. For our velocity field \( \mathbf{v} = \left\langle 0, 1-x^2, 0 \right\rangle \), it's important to identify:
In general, partial derivatives are crucial in a wide array of calculus applications from physics to engineering, providing foundational insight into how functions behave in a multi-variable environment.
- \( \frac{\partial Q}{\partial x} = -2x \)
- \( \frac{\partial P}{\partial y} = 0 \)
- \( \frac{\partial R}{\partial y} = 0 \)
- \( \frac{\partial Q}{\partial z} = 0 \)
- \( \frac{\partial P}{\partial z} = 0 \)
- \( \frac{\partial R}{\partial x} = 0 \)
In general, partial derivatives are crucial in a wide array of calculus applications from physics to engineering, providing foundational insight into how functions behave in a multi-variable environment.
Velocity Field Analysis
Velocity field analysis is all about examining how objects move through a space, which is crucial in fields like fluid dynamics, meteorology, and aerodynamics. In this exercise, analyzing the velocity field \( \mathbf{v} = \left\langle 0, 1-x^2, 0 \right\rangle \) simplifies to assessing the behavior of a horizontal flow in the \( y \)-direction.
The velocity field illustrates that all flow happens along \( y \) and is dependent only on \( x \).
Specifically:
The velocity field illustrates that all flow happens along \( y \) and is dependent only on \( x \).
Specifically:
- The flow is strongest where \( x = 0 \), and dies out as \( |x| \) approaches 1.
- The value inside the vector signifies that flow rate diminishes with increasing \( x \) magnitude.
- The absence of \( z \)-component means no flow or change happens in the \( z \)-direction.
Other exercises in this chapter
Problem 368
For the following exercises, let \(S\) be the disk enclosed by curve \(C: \mathbf{r}(t)=\langle\cos \varphi \cos t, \sin t, \sin \varphi \cos t\rangle\) for \(0
View solution Problem 371
Circle \(C\) in plane \(x+y+z=8\) has radius 4 and center \((2,3,3) .\) Evaluate \(\oint_{C} \mathbf{F} \cdot d \mathbf{r} \quad\) for \(F=\langle 0,-z, 2 y\ran
View solution Problem 373
Evaluate integral \(\iint_{S}(\nabla \times \mathbf{F}) \cdot \mathbf{n} d S, \quad\) where \(\mathbf{F}=-x z \mathbf{i}+y z \mathbf{j}+x y e^{z} \mathbf{k}\) a
View solution Problem 374
For the following exercises, use Stokes' theorem to find the circulation of the following vector fields around any smooth, simple closed curve C. $$ \mathbf{F}=
View solution