Problem 37
Question
Write the given iterated integral as an iterated integral with the order of integration interchanged. Hint: Begin by sketching a region \(S\) and representing it in two ways, as in Example \(5 .\) $$ \int_{0}^{1} \int_{-y}^{y} f(x, y) d x d y $$
Step-by-Step Solution
Verified Answer
The reordered integral is \( \int_{-1}^{1} \int_{0}^{|x|} f(x, y) \ dy \ dx \).
1Step 1: Identify the given order of integration limits
The given iterated integral is \( \int_{0}^{1} \int_{-y}^{y} f(x, y) \ dx \ dy \). The limits for \(x\) are from \(-y\) to \(y\), and the limits for \(y\) are from \(0\) to \(1\).
2Step 2: Sketch the region of integration
To identify the region \(S\), sketch the lines \(x = -y\), \(x = y\), \(y = 0\), and \(y = 1\). The intersection of these boundaries forms a triangular region in the xy-plane.
3Step 3: Describe the region as a type II region
In the xy-plane, the region is bounded by \(y \geq 0\), \(y \leq 1\), \(x \geq -y\), and \(x \leq y\). This region is described in terms of \(y\) as a function of \(x\) for changing the order of integration.
4Step 4: Rearrange the bounds for new order of integration
To integrate first with respect to \(y\), determine the limits based on the region. \(y\) ranges from \(-x\) to \(x\), while \(x\) ranges from \(0\) to \(1\).
5Step 5: Write the iterated integral with interchanged order
The iterated integral with interchanged order is \( \int_{-1}^{1} \int_{0}^{|x|} f(x, y) \ dy \ dx \). The region is now defined with respect to \(x\).
Key Concepts
Order of IntegrationRegion of IntegrationSketching RegionsIntegration Limits
Order of Integration
In iterated integrals, the order of integration refers to the sequence in which the integral is taken with respect to each variable. For a double integral in the form \( \int \int f(x, y) \, dx \, dy \), it means integrating with respect to \(x\) first, followed by \(y\). Sometimes, it might be necessary to change the order of integration. This can simplify the problem or make the integration possible.
The original problem starts with integrating \(x\) from \(-y\) to \(y\), and then \(y\) from 0 to 1. After swapping, we integrate \(y\) first over \([-x, x]\) and then \(x\) from 0 to 1.
The original problem starts with integrating \(x\) from \(-y\) to \(y\), and then \(y\) from 0 to 1. After swapping, we integrate \(y\) first over \([-x, x]\) and then \(x\) from 0 to 1.
Region of Integration
The region of integration is the area over which the function is being integrated. It is crucial to first identify this region in the xy-plane, which helps us determine the limits for integration.
In the example, the specified region \(S\) is defined by:
In the example, the specified region \(S\) is defined by:
- \(y \geq 0\)
- \(y \leq 1\)
- \(x \geq -y\)
- \(x \leq y\)
Sketching Regions
Sketching the region of integration is a helpful visual tool that makes it easier to rearrange the bounds for integration. By plotting the boundaries \(x = -y\), \(x = y\), \(y = 0\), and \(y = 1\), you can clearly see the triangular region in the xy-plane. Sketching is essential because:
- It visually verifies the boundaries and their intersections.
- Helps determine new bounds when changing the order of integration.
- Ensures the region of integration is correctly represented.
Integration Limits
Integration limits are the values that define the start and end points for the integral. These limits must be carefully analyzed, especially when the order of integration changes.
For the initial integral \(\int_{0}^{1} \int_{-y}^{y} f(x,y) \, dx \, dy\), the limits depend on the variables \(x\) and \(y\). After changing the order, the limits are identified as \( \int_{-1}^{1} \int_{0}^{|x|} f(x,y) \, dy \, dx\). Here:
For the initial integral \(\int_{0}^{1} \int_{-y}^{y} f(x,y) \, dx \, dy\), the limits depend on the variables \(x\) and \(y\). After changing the order, the limits are identified as \( \int_{-1}^{1} \int_{0}^{|x|} f(x,y) \, dy \, dx\). Here:
- \(y\) is bounded by \([-x, x]\) when changing the integration order.
- \(x\) ranges from 0 to 1.
Other exercises in this chapter
Problem 37
Show that $$ \int_{0}^{\infty} \int_{0}^{\infty} \frac{1}{\left(1+x^{2}+y^{2}\right)^{2}} d y d x=\frac{\pi}{4} $$
View solution Problem 37
Evaluate each iterated integral. $$ \int_{-2}^{2} \int_{-1}^{1}\left|x^{2} y^{3}\right| d y d x $$
View solution Problem 38
Recall the formula \(A=\frac{1}{2} r^{2} \theta\) for the area of the sector of a circle of radius \(r\) and central angle \(\theta\) radians (Section \(10.7) .
View solution Problem 38
Write the given iterated integral as an iterated integral with the order of integration interchanged. Hint: Begin by sketching a region \(S\) and representing i
View solution