Problem 37
Question
Write the first three terms in each binomial expansion, expressing the result in simplified form. $$ \left(y^{3}-1\right)^{20} $$
Step-by-Step Solution
Verified Answer
The first three terms of the binomial expansion for \( \left(y^{3}-1\right)^{20} \) are \( y^{60}, -20y^{57}, 190y^{54} \).
1Step 1: Understand the binomial theorem
The binomial theorem is \( (a+b)^n = ∑_{k=0}^{n} {n \choose k} a^{n-k} b^k \) where \({n \choose k}\) is a binomial coefficient. The binomial coefficient can be calculated using the formula: \({n \choose k} = \frac{n!}{k!(n-k)!}\), where '!' denotes the factorial of a number. Here, a is \(y^3\), b is -1, and n is 20.
2Step 2: Find the first term
Substitute k = 0 into the binomial theorem to find the first term. So, the first term is \( {20 \choose 0}(y^{3})^{20-0}(-1)^0 = y^{60} \).
3Step 3: Find the second term
Substitute k = 1 into the binomial theorem to find the second term. So, the second term is \( {20 \choose 1}(y^{3})^{20-1}(-1)^1 = -20(y^3)^{19} = -20y^{57} \).
4Step 4: Find the third term
Substitute k = 2 into the binomial theorem to find the third term. So, the third term is \( {20 \choose 2}(y^{3})^{20-2}(-1)^2 = {20 \choose 2} y^{54} = 190y^{54} \).
5Step 5: Combine the first three terms
Combine the three calculated terms to gain the first three terms of the expansion. Therefore, the first three terms of the binomial expansion are \( y^{60} - 20y^{57} + 190y^{54} \).
Key Concepts
Binomial TheoremBinomial CoefficientFactorial
Binomial Theorem
The binomial theorem is a fundamental tool in algebra used for expanding expressions that are raised to a power. This theorem provides a way to express these expressions, written as
In our exercise, for the expression \( (y^3 - 1)^{20} \), the theorem is used to determine the first few terms by setting
- \( (a+b)^n \)
- \( {n \choose k} a^{n-k} b^k \), where \( k \) denotes a particular term in the expansion
In our exercise, for the expression \( (y^3 - 1)^{20} \), the theorem is used to determine the first few terms by setting
- \( a = y^3 \)
- \( b = -1 \)
- \( n = 20 \)
Binomial Coefficient
The binomial coefficient is a central part of the binomial theorem. Represented by \( {n \choose k} \), it tells you how many ways you can choose \( k \) items from \( n \) items, without regard to order. The formula for calculating it is given by:
In the example \( (y^3 - 1)^{20} \), each coefficient is calculated by plugging \( n = 20 \) into the formula and varying \( k \) to figure out the coefficients for each expanding term.
- \( {n \choose k} = \frac{n!}{k!(n-k)!} \)
In the example \( (y^3 - 1)^{20} \), each coefficient is calculated by plugging \( n = 20 \) into the formula and varying \( k \) to figure out the coefficients for each expanding term.
- For \( k = 0 \), \( {20 \choose 0} = 1 \)
- For \( k = 1 \), \( {20 \choose 1} = 20 \)
- For \( k = 2 \), \( {20 \choose 2} = 190 \)
Factorial
Factorials are a mathematical concept that are crucial for calculating binomial coefficients. Notated as \( n! \), the factorial of a number \( n \) is defined as the product of all positive integers up to \( n \). For example,
In our example of \( (y^3 - 1)^{20} \), factorials were used to calculate the coefficients:
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
In our example of \( (y^3 - 1)^{20} \), factorials were used to calculate the coefficients:
- \( {20 \choose 1} = \frac{20!}{1! \times 19!} = 20 \)
- \( {20 \choose 2} = \frac{20!}{2! \times 18!} = 190 \)
Other exercises in this chapter
Problem 36
Write a formula for the general term (the nth term) of each arithmetic sequence. Do not use a recursion formula. Then use the formula for \(a_{n}\) to find \(a_
View solution Problem 36
Find each indicated sum. $$\sum_{i=2}^{4}\left(-\frac{1}{3}\right)^{i}$$
View solution Problem 37
A single die is rolled. Find the probability of rolling: an even number or a number less than 5 .
View solution Problem 37
Fermat's most notorious theorem baffled the greatest minds for more than three centuries. In \(1994,\) after ten years of work, Princeton University's Andrew Wi
View solution