Problem 37
Question
Write the conjugate of each expression. $$ 5-\sqrt{a} $$
Step-by-Step Solution
Verified Answer
The conjugate is \( 5 + \sqrt{a} \).
1Step 1: Understanding the Concept
The conjugate of a binomial expression in the form of \( a - \sqrt{b} \) is \( a + \sqrt{b} \). The conjugate involves simply changing the sign between the two terms of the binomial.
2Step 2: Identifying Components
Identify the components of the given expression \( 5 - \sqrt{a} \). Here, \( a = 5 \) and \( b = a \) in the binomial expression form \( a - \sqrt{b} \).
3Step 3: Applying the Conjugate Rule
Using the concept from Step 1, apply the conjugate rule to change the sign in the expression \( 5 - \sqrt{a} \). This results in the expression \( 5 + \sqrt{a} \).
Key Concepts
Binomial ExpressionSquare RootsAlgebraic Manipulation
Binomial Expression
A binomial expression is an algebraic expression containing exactly two terms. These terms are typically joined by either a plus or a minus sign. In algebra,
- The structure of a binomial expression can be represented as \( a + b \) or \( a - b \).
- Such expressions are common in problems involving conjugates, particularly those dealing with square roots.
Square Roots
Square roots appear often in algebraic expressions, especially when dealing with binomials. A square root is the value that, when multiplied by itself, gives the original number. For example:
- If \( x^2 = a \), then \( x = \sqrt{a} \).
- In expressions like \( \sqrt{a} \), \( a \) is under the square root symbol, which indicates the operation of finding a number which squared equals \( a \).
Algebraic Manipulation
Algebraic manipulation is the process of rearranging and simplifying algebraic expressions through various operations. When working with binomials and square roots, such as in the context of finding a conjugate, this manipulation often involves changing signs and rearranging terms.To find the conjugate:
- Identify your binomial expression, which in our example is \( 5 - \sqrt{a} \).
- The conjugate is formed by switching the sign between the terms, resulting in \( 5 + \sqrt{a} \).
Other exercises in this chapter
Problem 37
Write with positive exponents. Simplify if possible. $$ \frac{1}{a^{-2 / 3}} $$
View solution Problem 37
Solve. \(\sqrt{x+4}=\sqrt{2 x-5}\)
View solution Problem 37
Simplify. See Examples 3 and 4 $$ \sqrt{24} $$
View solution Problem 37
Add or subtract. $$ \frac{\sqrt[3]{8 x^{4}}}{7}+\frac{3 x \sqrt[3]{x}}{7} $$
View solution