Problem 37
Question
Write equivalent equations by multiplying both sides of each given equation by the given nonzero number. $$ 3 x+2 y=6 \text { by }-2 $$
Step-by-Step Solution
Verified Answer
The equivalent equation is \(-6x - 4y = -12\).
1Step 1: Identify the Given Equation and Number
The given equation is \(3x + 2y = 6\) and the nonzero number to multiply by is \(-2\). Our first task is to understand that we need to apply this number to every term in the equation.
2Step 2: Apply Multiplication to the Left Side of the Equation
Multiply each term on the left side of the equation by \(-2\):\(-2 \times 3x + (-2) \times 2y\). This simplifies to \(-6x - 4y\).
3Step 3: Apply Multiplication to the Right Side of the Equation
Multiply the right side of the equation, \(6\), by \(-2\):\(-2 \times 6\). This simplifies to \(-12\).
4Step 4: Write the Equivalent Equation
Combine the results from Steps 2 and 3 to form the new equation. This results in \(-6x - 4y = -12\).
Key Concepts
Multiplication of EquationsEquivalent EquationsAlgebraic Manipulation
Multiplication of Equations
When we talk about multiplication of equations, we're referring to multiplying every term in an equation by the same nonzero number. This process is crucial to maintaining the equality between both sides of the equation. Suppose you have an equation like \(3x + 2y = 6\). Here, multiplying each term by a number, say \(-2\), means you need to multiply both the left side terms (i.e., \(3x\) and \(2y\)) and the right side term (i.e., \(6\)) by \(-2\). This is done step by step:
- First, multiply the term \(3x\) by \(-2\) to get \(-6x\).
- Then, multiply the term \(2y\) by \(-2\) to get \(-4y\).
- Finally, multiply \(6\) by \(-2\) to get \(-12\).
Equivalent Equations
Equivalent equations are equations that have the same solution set. They may look different on the outside, but under the hood, they produce the same results when solved. When you multiply every term of an equation by the same nonzero number, you are creating an equivalent equation.
For example, transforming \(3x + 2y = 6\) into \(-6x - 4y = -12\) by multiplying everything by \(-2\) is a classic way of obtaining an equivalent equation. Here's why this works:
For example, transforming \(3x + 2y = 6\) into \(-6x - 4y = -12\) by multiplying everything by \(-2\) is a classic way of obtaining an equivalent equation. Here's why this works:
- Both original and new equations would yield the same values for \(x\) and \(y\) when solved.
- This method is often used to simplify equations for easier handling, especially in solving systems of equations.
- It allows us to manipulate equations without changing their inherent characteristics.
Algebraic Manipulation
Algebraic manipulation is the art of changing the form of an equation to make it easier to work with. It includes operations such as addition, subtraction, multiplication, and division applied to both sides of an equation to simplify or rearrange it.
In the context of our exercise, multiplying the equation by \(-2\) is a form of algebraic manipulation. This step involves altering both sides of \(3x + 2y = 6\) consistently:
In the context of our exercise, multiplying the equation by \(-2\) is a form of algebraic manipulation. This step involves altering both sides of \(3x + 2y = 6\) consistently:
- By multiplying \(3x\) and \(2y\) by \(-2\), you transform the left-hand side to \(-6x - 4y\).
- Similarly, multiply \(6\) to get \(-12\) on the right-hand side.
Other exercises in this chapter
Problem 36
Recall that two angles are supplementary if the sum of their measures is \(180^{\circ} .\) Find the measures of two supplementary angles if one angle is \(20^{\
View solution Problem 37
Solve each system of equations by the addition method. If a system contains fractions or decimals, you may want to first clear each equation of fractions or dec
View solution Problem 37
Solve each system of linear equations by graphing. See Examples 3 through \(6 .\) \(\left\\{\begin{array}{l}6 x-y=4 \\ \frac{1}{2} y=-2+3 x\end{array}\right.\)
View solution Problem 37
Find the measures of two complementary angles if one angle is \(10^{\circ}\) more than three times the other.
View solution