Problem 37
Question
Write each of the following in terms of \(i\) and simplify. For example, $$ \sqrt{-20}=i \sqrt{20}=i \sqrt{4} \sqrt{5}=2 i \sqrt{5} $$ $$3 \sqrt{-28}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(6i\sqrt{7}\).
1Step 1: Identify the Negative Inside the Square Root
The expression given is \(3 \sqrt{-28}\). To express the square root of a negative number, we identify the negative sign and note that \( \sqrt{-1} = i \). Therefore, \( \sqrt{-28} = \sqrt{28} \cdot \sqrt{-1} = i \sqrt{28} \).
2Step 2: Factor the Number Inside the Square Root
We factor \( 28 \) into its prime components: \( 28 = 4 \times 7 \). So \( \sqrt{28} = \sqrt{4 \cdot 7} \).
3Step 3: Simplify the Square Root
Use the property of square roots: \( \sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b} \). Thus, \( \sqrt{4 \cdot 7} = \sqrt{4} \cdot \sqrt{7} = 2 \sqrt{7} \), since \( \sqrt{4} = 2 \).
4Step 4: Combine and Simplify with the Multiplier
Now substitute back into the original expression: \( 3 \sqrt{-28} = 3 \cdot i \cdot 2 \sqrt{7} \). Calculate the product: \( 3 \cdot 2 \cdot i \cdot \sqrt{7} = 6i \sqrt{7} \). This is the simplified expression.
Key Concepts
Imaginary UnitSimplifying Square RootsPrime Factorization
Imaginary Unit
When dealing with the square root of a negative number, you encounter the concept of the imaginary unit, denoted as \( i \). This is a fundamental building block in complex numbers, used to make sense of these challenging math situations.
- The imaginary unit \( i \) is defined by the equation \( i^2 = -1 \). This means that \( i \) is the square root of \(-1\).
- Using \( i \) allows us to represent any square root of a negative number as \( i \) times the square root of the corresponding positive number.
- For example, \( \sqrt{-28} = i \sqrt{28} \).
Simplifying Square Roots
Simplifying square roots is an essential skill in mathematics that involves breaking down a root to its simplest form. To do this effectively, you need to recognize and factor the number inside the root.
- The process starts with factoring the number inside the square root into its prime factors.
- If you can form any perfect squares from these factors, you can simplify the square root further.
- For example, with the number 28 inside the root, you can factor it as \( 28 = 4 \times 7 \) and then simplify \( \sqrt{28} = \sqrt{4 \times 7} = \sqrt{4} \cdot \sqrt{7} = 2\sqrt{7} \).
Prime Factorization
Prime factorization is the process of breaking down a number into its smallest divisible components, known as prime numbers. This technique is incredibly useful for simplifying square roots and understanding the structure of numbers.
- A prime number is a natural number greater than 1 that cannot be divided by any number other than 1 and itself. Examples include 2, 3, 5, and 7.
- To factor a number like 28, you divide it by the smallest possible prime numbers. For instance, \( 28 \div 2 = 14 \), and \( 14 \div 2 = 7 \), leaving us with the factors \( 2, 2, \) and \( 7 \).
- This leads to the expression \( 28 = 2^2 \times 7 \).
Other exercises in this chapter
Problem 37
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$5 x^{2}-13 x=0$$
View solution Problem 37
Use the method of completing the square to solve each quadratic equation. $$3 x^{2}+5 x-1=0$$
View solution Problem 38
Solve each inequality. $$2 x^{2}-18 \geq 0$$
View solution Problem 38
Solve each equation. $$4 x^{4}+11 x^{2}-45=0$$
View solution