Problem 37
Question
Write each expression as a single logarithm. $$3 \log _{b} x+5 \log _{b} y$$
Step-by-Step Solution
Verified Answer
\( \log_{b} (x^3 y^5) \)
1Step 1: Understand the Properties of Logarithms
To combine the expression into a single logarithm, we will use the power rule of logarithms, which states that \( a \log_b M = \log_b M^a \). This means we can change the expression's coefficients into exponents within the logarithmic function.
2Step 2: Apply the Power Rule
Using the power rule for both terms, we rewrite them as \( \log_{b} x^3 \) and \( \log_{b} y^5 \). This transforms the original expression into \( \log_{b} x^3 + \log_{b} y^5 \).
3Step 3: Combine Using the Product Rule
According to the product rule for logarithms, \( \log_b M + \log_b N = \log_b (MN) \). Apply this rule to the expression \( \log_{b} x^3 + \log_{b} y^5 \) to combine the logarithms: \( \log_{b} (x^3 \, y^5) \).
4Step 4: Finalize the Expression
The expression can now be written as a single logarithm: \( \log_{b} (x^3 y^5) \). This is the expression in its simplest, single logarithmic form.
Key Concepts
Power Rule of LogarithmsProduct Rule of LogarithmsCombining Logarithms
Power Rule of Logarithms
When dealing with logarithmic expressions, one of the key rules is the power rule. This fundamental rule is akin to turning multiplication into addition within logarithmic functions.
It states that you can move a multiplier in front of a logarithm to become an exponent inside the logarithmic argument.
Without applying this rule, we would have to deal with separated coefficients, which can be cumbersome.
It states that you can move a multiplier in front of a logarithm to become an exponent inside the logarithmic argument.
- Formula: \( a \log_b M = \log_b M^a \)
- Example: If you have \( 3\log_b x \), using the power rule, it becomes \( \log_b x^3 \)
Without applying this rule, we would have to deal with separated coefficients, which can be cumbersome.
Product Rule of Logarithms
The product rule of logarithms is another essential tool in the world of logarithms. It allows us to combine two logarithms with the same base into a single logarithm.
This rule changes the sum of logarithms into the logarithm of a product.
This rule changes the sum of logarithms into the logarithm of a product.
- Formula: \( \log_b M + \log_b N = \log_b (MN) \)
- Example: \( \log_b x^3 + \log_b y^5 \) becomes \( \log_b (x^3 y^5) \)
Combining Logarithms
When you know the rules of logarithms, combining them into a single expression becomes systematic and straightforward.
In exercises like the one given, we bring together multiple elements into a neat form. Using both the power rule and product rule, we can turn what initially seems complex into a single expression.
Start with the power rule to turn coefficients into exponents, then use the product rule to merge the terms into one.
In exercises like the one given, we bring together multiple elements into a neat form. Using both the power rule and product rule, we can turn what initially seems complex into a single expression.
Start with the power rule to turn coefficients into exponents, then use the product rule to merge the terms into one.
- First, rewrite coefficients as exponents: \( 3\log_b x + 5\log_b y \) transforms to \( \log_b x^3 + \log_b y^5 \)
- Then, use the product rule to simplify: \( \log_b x^3 + \log_b y^5 \) becomes \( \log_b (x^3 y^5) \)
Other exercises in this chapter
Problem 37
The intensity of a laser beam is given by the ratio of power to area. A particular laser beam has an intensity function given by \(I=e^{-r^{2}} \mathrm{mW} / \m
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Solve the exponential equations. Make sure to isolate the base to a power first. Round our answers to three decimal places. $$\frac{20}{6-e^{2 x}}=4$$
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Graph the exponential function using transformations. State the \(y\) -intercept, two additional points, the domain, the range, and the horizontal asymptote. $$
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Evaluate the logarithms exactly (if possible). $$\log _{5} 3125$$
View solution