Problem 37
Question
Why do molecules of methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) form hydrogen bonds, but molecules of methane (CH, ) do not?
Step-by-Step Solution
Verified Answer
Question: Explain why methanol (CH3OH) molecules form hydrogen bonds, while methane (CH4) molecules do not.
Answer: Methanol (CH3OH) molecules form hydrogen bonds because they have a polar O-H bond that creates partial charges necessary for hydrogen bonding. In contrast, methane (CH4) molecules have nonpolar C-H bonds without the necessary partial charges, preventing them from forming hydrogen bonds.
1Step 1: Understanding hydrogen bonding
Hydrogen bonding is a type of intermolecular force that occurs between molecules with a hydrogen atom bonded to a highly electronegative element (such as oxygen, nitrogen, or fluorine). These elements have a strong attraction for electron density, which leads to an unequal sharing of electrons and the formation of a polar bond with a partial positive charge on the hydrogen atom and a partial negative charge on the electronegative element.
2Step 2: Analyzing the structure of methanol (CH3OH)
Methanol (CH3OH) is composed of a methyl group (CH3) and a hydroxyl group (OH). The oxygen atom in the hydroxyl group is highly electronegative and is bonded to a hydrogen atom. This creates a polar bond, with a partial positive charge on the hydrogen and a partial negative charge on the oxygen.
3Step 3: Analyzing the structure of methane (CH4)
Methane (CH4) consists of a carbon atom with four hydrogen atoms attached to it. Carbon and hydrogen have similar electronegativities, meaning that the electrons are shared equally between them in the carbon-hydrogen bonds. Therefore, these bonds are non-polar, and no partial charges are created.
4Step 4: Comparing hydrogen bonding capabilities
Methanol, with its polar O-H bond, has the necessary conditions to form hydrogen bonds with other polar molecules. The partially positive hydrogen atom in one methanol molecule can form a hydrogen bond with the partially negative oxygen atom in another methanol molecule. On the other hand, methane, with its nonpolar C-H bonds, cannot form hydrogen bonds due to the lack of partial charges. This lack of hydrogen bonding capabilities is what distinguishes methane from methanol.
5Step 5: Conclusion
In conclusion, methanol (CH3OH) molecules form hydrogen bonds because they have a polar O-H bond that creates partial charges, making it possible for hydrogen bonding to occur. In contrast, methane (CH4) molecules cannot form hydrogen bonds because they have nonpolar C-H bonds without the necessary partial charges for hydrogen bonding.
Key Concepts
Methanol StructureMethane StructureIntermolecular Forces
Methanol Structure
Methanol is a simple alcohol with the chemical formula \(\text{CH}_3\text{OH}\). It consists of a methyl group \(\text{(CH}_3\text{)}\) attached to a hydroxyl group \(\text{(OH)}\). This structure is what gives methanol its unique properties.
In methanol, the oxygen atom in the hydroxyl group is highly electronegative. This means it has a strong pull on electrons, creating a polar environment. The result is an uneven distribution of charges:
They occur because of the attraction between the partially positive hydrogen atom and a similarly partially negative element in a nearby molecule.
This hydrogen bonding capability plays a significant role in the physical properties of methanol, such as its boiling point and solubility in water.
In methanol, the oxygen atom in the hydroxyl group is highly electronegative. This means it has a strong pull on electrons, creating a polar environment. The result is an uneven distribution of charges:
- The oxygen carries a partial negative charge.
- The hydrogen attached to it holds a partial positive charge.
They occur because of the attraction between the partially positive hydrogen atom and a similarly partially negative element in a nearby molecule.
This hydrogen bonding capability plays a significant role in the physical properties of methanol, such as its boiling point and solubility in water.
Methane Structure
Methane is a simple hydrocarbon with the formula \(\text{CH}_4\). It consists of one carbon atom bonded to four hydrogen atoms. This structure forms a tetrahedral shape, which is perfectly symmetrical.
The key aspect of methane's structure is that the carbon-hydrogen (C-H) bonds are non-polar.
The key aspect of methane's structure is that the carbon-hydrogen (C-H) bonds are non-polar.
- Carbon and hydrogen atoms have similar electronegativities, meaning they share electrons fairly equally.
- No significant dipole moment is created, as there is no unequal sharing of charges.
Intermolecular Forces
Intermolecular forces are the forces of attraction or repulsion between molecules.
They are crucial in determining the physical properties of substances, such as boiling and melting points, solubility, and viscosity.
There are several types of intermolecular forces, including:
In contrast, the only intermolecular force present in methane is the London dispersion force, due to its non-polar nature, resulting in weaker interactions and a lower boiling point.
There are several types of intermolecular forces, including:
- Hydrogen bonding: The strongest type among the common intermolecular forces, this occurs in polar molecules where hydrogen is directly bonded to fluorine, oxygen, or nitrogen.
- Dipole-dipole interactions: These are attractions between the positive end of one polar molecule and the negative end of another.
- London dispersion forces: The weakest kind, these are temporary attractions that occur in all molecules due to electron movement, but are primarily significant in non-polar molecules like methane.
In contrast, the only intermolecular force present in methane is the London dispersion force, due to its non-polar nature, resulting in weaker interactions and a lower boiling point.
Other exercises in this chapter
Problem 35
Suggest two reasons why the boiling point of methyl Auoride, \(\mathrm{CH}_{3} \mathrm{F}\), is higher than the boiling point of methane, \(\mathrm{CH}_{4}.\)
View solution Problem 36
Why is the boiling point of \(\mathrm{Br}_{2}\) lower than that of iodine mono chloride, ICl, even though they have nearly the same molar mass?
View solution Problem 38
The boiling point of \(\mathrm{H}_{2} \mathrm{S}\) is lower than that of \(\mathrm{H}_{2} \mathrm{O}\) even though \(\mathrm{H}_{2} \mathrm{S}\) has twice the m
View solution Problem 39
In which of the following compounds do the molecules experience dipole-dipole interactions? (a) \(\mathrm{CF}_{4} ;\) (b) \(\mathrm{CF}_{2} \mathrm{Cl}_{2}\) (c
View solution