Problem 37
Question
Which of the following pairs of groups are isomorphic? Why or (d) \(\mathbb{Z}_{2} \times \mathbb{Z}\) and \(\mathbb{Z},(\mathrm{e})\) why not? (a) \(\mathbb{Z}_{2} \times \mathbb{Z}_{2}\) and \(\mathbb{Z}_{4},\) (b) \(\mathbb{Z}_{12}^{*}\) and \(\mathbb{Z}_{8}^{*},\) (c) \(\mathbb{Z}_{5}^{*}\) and \(\mathbb{Z}_{4}\), \(\mathbb{Q}\) and \(\mathbb{Z},\) (f) \(\mathbb{Z} \times \mathbb{Z}\) and \(\mathbb{Z}\)
Step-by-Step Solution
Verified Answer
Question: Determine if the given pairs of groups are isomorphic or not:
(a) \(\mathbb{Z}_{2} \times \mathbb{Z}_{2}\) and \(\mathbb{Z}_{4}\)
(b) \(\mathbb{Z}_{12}^{*}\) and \(\mathbb{Z}_{8}^{*}\)
(c) \(\mathbb{Z}_{5}^{*}\) and \(\mathbb{Z}_{4}\)
(d) \(\mathbb{Z}_{2} \times \mathbb{Z}\) and \(\mathbb{Z}\)
(e) \(\mathbb{Z} \times \mathbb{Z}\) and \(\mathbb{Z}\)
(f) \(\mathbb{Q}\) and \(\mathbb{Z}\)
Answer:
(a) Isomorphic
(b) Not isomorphic
(c) Not isomorphic
(d) Not isomorphic
(e) Not isomorphic
(f) Not isomorphic
1Step 1: Determine the orders of the given groups
For each pair of groups, compute the order of each group.
(a) \(|\mathbb{Z}_{2} \times \mathbb{Z}_{2}| = 2 \cdot 2 = 4\), and \(|\mathbb{Z}_{4}| = 4\)
(b) \(|\mathbb{Z}_{12}^{*}| = 4\), and \(|\mathbb{Z}_{8}^{*}| = 4\) (counting the numbers relatively prime to 12 and 8)
(c) \(|\mathbb{Z}_{5}^{*}| = 4\), and \(|\mathbb{Z}_{4}| = 4\)
(d) \(|\mathbb{Z}_{2} \times \mathbb{Z}| = 2 \cdot \infty = \infty\), and \(|\mathbb{Z}| = \infty\)
(e) \(|\mathbb{Z} \times \mathbb{Z}| = \infty \cdot \infty = \infty\), and \(|\mathbb{Z}| = \infty\)
(f) \(|\mathbb{Q}| = \infty\), and \(|\mathbb{Z}| = \infty\)
2Step 2: Check if the orders match
If the orders of the two groups are different, they cannot be isomorphic. In this case, all pairs of groups have the same orders.
3Step 3: Provide an explanation
(a) The groups \(\mathbb{Z}_{2} \times \mathbb{Z}_{2}\) and \(\mathbb{Z}_{4}\) are isomorphic because they have the same order, and their respective elements exhibit the same cyclic behavior.
(b) The groups \(\mathbb{Z}_{12}^{*}\) and \(\mathbb{Z}_{8}^{*}\) are not isomorphic because the group operation in \(\mathbb{Z}_{12}^{*}\) is multiplication modulo 12, while in \(\mathbb{Z}_{8}^{*}\) it is multiplication modulo 8. So, their respective elements do not exhibit the same behavior.
(c) The groups \(\mathbb{Z}_{5}^{*}\) and \(\mathbb{Z}_{4}\) are not isomorphic. \(\mathbb{Z}_{5}^{*}\) is a multiplicative group modulo 5, while \(\mathbb{Z}_{4}\) is an additive group modulo 4. So, their respective elements do not exhibit the same behavior.
(d) The groups \(\mathbb{Z}_{2} \times \mathbb{Z}\) and \(\mathbb{Z}\) are not isomorphic. \(\mathbb{Z}_{2} \times \mathbb{Z}\) contains elements of order 2, while \(\mathbb{Z}\) does not have any elements of order 2 (except for the identity element).
(e) The groups \(\mathbb{Z} \times \mathbb{Z}\) and \(\mathbb{Z}\) are not isomorphic. \(\mathbb{Z} \times \mathbb{Z}\) is not cyclic, while \(\mathbb{Z}\) is cyclic.
(f) The groups \(\mathbb{Q}\) and \(\mathbb{Z}\) are not isomorphic because \(\mathbb{Q}\) is a field and contains inverses for all non-zero elements under multiplication, while \(\mathbb{Z}\) does not have multiplicative inverses for all non-zero elements.
Key Concepts
Group TheoryCyclic GroupsMultiplicative Groups
Group Theory
In mathematics, group theory is the study of algebraic structures known as groups. A group is a set combined with an operation that satisfies four key properties: closure, associativity, identity, and invertibility.
- **Closure**: If you perform the group operation on any two elements in the group, you must get another element that is also in the group.
- **Associativity**: Changing the grouping of elements does not change the result of their operation (i.e., (\((a \cdot b) \cdot c = a \cdot (b \cdot c)\)).
- **Identity**: There must be an element in the group such that any element combined with it, under the group operation, returns that element itself.
- **Invertibility**: Every element must have an inverse within the group that, when combined with it under the group operation, yields the identity element.
Cyclic Groups
Cyclic groups are a special type of group where all elements can be generated by repeatedly applying the group operation to a single element, known as a generator.
These groups can be thought of as "spinning" around a central element. If you consider the set of integers under addition, the generator might be 1 or -1 because you can create any integer by adding or subtracting 1 repeatedly.
These groups can be thought of as "spinning" around a central element. If you consider the set of integers under addition, the generator might be 1 or -1 because you can create any integer by adding or subtracting 1 repeatedly.
- A cyclic group with a finite number of elements is isomorphic to the integers modulo some positive integer \( n \).
- All elements in a cyclic group exhibit a repeating pattern.
- This property is crucial when considering whether two groups, such as \(\mathbb{Z}_{4}\) and \(\mathbb{Z}_{2} \times \mathbb{Z}_{2}\), are isomorphic. Both are cyclic and thus exhibit the same cyclical behavior.
Multiplicative Groups
Multiplicative groups are those in which the group operation is multiplication. These groups are essential in understanding number theory and cryptography.
- One example is \(\mathbb{Z}_{n}^{*}\), the multiplicative group of integers modulo \( n \). This group consists of integers that are coprime to \( n \) with multiplication being the operation.
- These groups are infinite if based on complex numbers but can be finite when considering fields or certain sets of integers.
- The structure of multiplicative groups can be somewhat different from additive groups (like \( \mathbb{Z}_{4} \)), so two groups with similar orders might still not be isomorphic due to different group operations.
Other exercises in this chapter
Problem 35
Let \(\mathbb{Z}^{+}\) denote the set of positive integers, and let \(\mathbb{Q}^{*}\) be the multiplicative group of non-zero rational numbers. Consider the ab
View solution Problem 36
Let \(n\) be an odd, positive integer whose factorization into primes is \(n=p_{1}^{e_{1}} \cdots p_{r}^{e_{r}} .\) Show that: (a) we have a group isomorphism \
View solution Problem 39
Show that \(\mathbb{Q}^{*}\) is not finitely generated.
View solution Problem 40
Let \(G\) be an abelian group, \(a \in G,\) and \(m \in \mathbb{Z},\) such that \(m>0\) and \(m a=0_{G} .\) Let \(m=p_{1}^{e_{1}} \cdots p_{r}^{e_{r}}\) be the
View solution