Problem 37
Question
Use Cramer's rule to solve the system $$ \begin{aligned} &X=x \cos \theta+y \sin \theta \\ &Y=-x \sin \theta+y \cos \theta \end{aligned} $$ for \(x\) and \(y\).
Step-by-Step Solution
Verified Answer
x = X\cos\theta - Y\sin\theta, y = Y\cos\theta + X\sin\theta.
1Step 1: Identifying the Matrices
First, we identify the coefficients in the given equations. Rewrite the system:\[X = x\cos\theta + y\sin\theta\]\[Y = -x\sin\theta + y\cos\theta\]The coefficient matrix \( A \) is:\[ A = \begin{pmatrix} \cos\theta & \sin\theta \ -\sin\theta & \cos\theta \end{pmatrix} \] and the constants matrix is \( \begin{pmatrix} X \ Y \end{pmatrix} \). The variables matrix is \( \begin{pmatrix} x \ y \end{pmatrix} \).
2Step 2: Calculate the Determinant of the Coefficient Matrix
To use Cramer's rule, compute the determinant of matrix \( A \):\[ \text{det}(A) = \cos\theta \cdot \cos\theta - (-\sin\theta) \cdot \sin\theta = \cos^2\theta + \sin^2\theta \]Using the Pythagorean identity, \( \cos^2\theta + \sin^2\theta = 1 \). So, \( \text{det}(A) = 1 \).
3Step 3: Calculate Determinants for x and y
Calculate the determinants by replacing the columns of the coefficient matrix with the constants vector. For \( x \), replace the first column:\[ A_x = \begin{pmatrix} X & \sin\theta \ Y & \cos\theta \end{pmatrix} \]\[ \text{det}(A_x) = X\cos\theta - Y\sin\theta \]For \( y \), replace the second column:\[ A_y = \begin{pmatrix} \cos\theta & X \ -\sin\theta & Y \end{pmatrix} \]\[ \text{det}(A_y) = Y\cos\theta + X\sin\theta \].
4Step 4: Use Cramer's Rule to Solve for x and y
Cramer's Rule gives:\[ x = \frac{\text{det}(A_x)}{\text{det}(A)} = X\cos\theta - Y\sin\theta \]\[ y = \frac{\text{det}(A_y)}{\text{det}(A)} = Y\cos\theta + X\sin\theta \].
Key Concepts
Matrix DeterminantsLinear SystemsTrigonometric Identities
Matrix Determinants
A matrix determinant is a special number that can be calculated from a square matrix, and it plays a crucial role in solving systems of linear equations. It's like a DNA fingerprint for matrices, giving you vital information about whether a matrix is invertible, which means its inverse matrix exists.
For a 2x2 matrix like \( A \), the determinant is determined by the formula:
In our example exercise, you calculated the determinant of the coefficient matrix to be 1. This confirms the matrix is invertible, allowing us to solve for the variables \( x \) and \( y \).
For a 2x2 matrix like \( A \), the determinant is determined by the formula:
- \( \text{det}(A) = ad - bc \)
- where \( a, b, c, \text{ and } d \) are elements of the matrix \( A = \begin{pmatrix} a & b \ c & d \end{pmatrix} \).
In our example exercise, you calculated the determinant of the coefficient matrix to be 1. This confirms the matrix is invertible, allowing us to solve for the variables \( x \) and \( y \).
Linear Systems
Linear systems are collections of linear equations involving the same set of variables. These equations can be solved to find values for these variables that satisfy all the equations in the system simultaneously. For example, the set of equations given in the original exercise represents a linear system.
Solving linear systems can involve various methods, including substitution, elimination, and matrix-related techniques such as Cramer's Rule.
Cramer's Rule is particularly useful because:
Solving linear systems can involve various methods, including substitution, elimination, and matrix-related techniques such as Cramer's Rule.
Cramer's Rule is particularly useful because:
- It uses determinants to find the solution.
- It's applied to systems with the same number of equations as variables (i.e., square systems).
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are true for all values of the occurring variables. They are incredibly helpful for simplifying expressions and solving equations involving angles.
The Pythagorean identity is one fundamental trigonometric identity:
In our problem, the trigonometric functions \( \cos \theta \) and \( \sin \theta \) represent the rotation of a vector in the plane by an angle \( \theta \). These functions help transform the original system's variables, \( x \) and \( y \), through rotation, expressed via the equations given.
Understanding these identities is key to simplifying complex expressions involving angles and making problems more manageable.
The Pythagorean identity is one fundamental trigonometric identity:
- \( \cos^2\theta + \sin^2\theta = 1 \)
In our problem, the trigonometric functions \( \cos \theta \) and \( \sin \theta \) represent the rotation of a vector in the plane by an angle \( \theta \). These functions help transform the original system's variables, \( x \) and \( y \), through rotation, expressed via the equations given.
Understanding these identities is key to simplifying complex expressions involving angles and making problems more manageable.
Other exercises in this chapter
Problem 37
Let \(\mathbf{A}=\left(\begin{array}{rr}3 & -4 \\ 1 & 2\end{array}\right)\) and \(\mathbf{B}=\left(\begin{array}{rr}7 & 4 \\ -1 & -5\end{array}\right)\). Verify
View solution Problem 37
If a matrix \(\mathbf{A}\) is premultiplied by an elementary matrix \(\mathbf{E}\), the product EA will be that matrix obtained from A by performing the element
View solution Problem 37
$$ \text { Show that if } \mathbf{A} \text { is a nonsingular matrix, then } \operatorname{det} \mathbf{A}^{-1}=1 / \operatorname{det} \mathbf{A} \text {. } $$
View solution Problem 38
The \(m\) th power of a diagonal matrix is $$ \begin{gathered} \mathbf{D}=\left(\begin{array}{cccc} a_{11} & 0 & \cdots & 0 \\ 0 & a_{22} & \cdots & 0 \\ \vdots
View solution