Problem 37
Question
Transform the second-order differential equation $$ \frac{d^{2} x}{d t^{2}}-2 \frac{d x}{d t}=\frac{x}{2} $$ into a system of first-order differential equations.
Step-by-Step Solution
Verified Answer
The system is: \( \frac{dx}{dt} = v \) and \( \frac{dv}{dt} = \frac{x}{2} + 2v \).
1Step 1: Identify the original second-order differential equation
Given the original second-order differential equation: \( \frac{d^{2} x}{d t^{2}} - 2 \frac{d x}{d t} = \frac{x}{2} \). It involves the second derivative of \( x \) with respect to \( t \). To transform it into a system of first-order equations, we need to define new variables.
2Step 2: Define new variables
Let \( v(t) = \frac{dx}{dt} \) represent the first derivative of \( x \) with respect to \( t \). This substitution reduces the second-order differential equation to a system involving \( v(t) \). So, we now have two variables: \( x(t) \) and \( v(t) = \frac{dx}{dt} \).
3Step 3: Express second derivative using new variables
The second derivative \( \frac{d^{2} x}{d t^{2}} \) can now be expressed in terms of the derivative of \( v(t) \): \( \frac{d^{2} x}{d t^{2}} = \frac{d}{dt} \left( \frac{dx}{dt} \right) = \frac{dv}{dt} \).
4Step 4: Create a system of first-order differential equations
Substitute \( v(t) = \frac{dx}{dt} \) and \( \frac{d^{2} x}{d t^{2}} = \frac{dv}{dt} \) into the original equation:\( \frac{dv}{dt} - 2v = \frac{x}{2} \).Now we have the system of first-order differential equations:1. \( \frac{dx}{dt} = v \)2. \( \frac{dv}{dt} = \frac{x}{2} + 2v \).
Key Concepts
Understanding Second-Order Differential Equations
Understanding Second-Order Differential Equations
Differential equations are mathematical expressions that relate a function with its derivatives. A second-order differential equation specifically involves the second derivative.\\
A typical form of a second-order differential equation is \( \frac{d^2x}{dt^2} + a\frac{dx}{dt} + bx = f(t) \), where \( a \) and \( b \) are constants, and \( f(t) \) is a function of \( t \). The presence of \( \frac{d^2x}{dt^2} \) is what makes it second-order.\\
Second-order differential equations are widely used in physics, engineering, and other sciences to model real-world behaviors. They are essential in situations where acceleration (the second derivative of position) must be considered, like in mechanics or wave propagation.\
For differential equations, converting a higher-order equation into a system of first-order equations can simplify the process of solving them. This approach is particularly useful with numerical methods since many numerical algorithms are naturally expressed using first-order equations.
Converting a single second-order differential equation into two first-order equations, as seen in the exercise, helps in applying various solution techniques like matrix methods or software tools.
In our example, the original equation \( \frac{d^{2} x}{d t^{2}} - 2 \frac{dx}{dt} = \frac{x}{2} \) involves the second derivative. To convert it into a system of first-order equations, follow these steps:
A typical form of a second-order differential equation is \( \frac{d^2x}{dt^2} + a\frac{dx}{dt} + bx = f(t) \), where \( a \) and \( b \) are constants, and \( f(t) \) is a function of \( t \). The presence of \( \frac{d^2x}{dt^2} \) is what makes it second-order.\\
Second-order differential equations are widely used in physics, engineering, and other sciences to model real-world behaviors. They are essential in situations where acceleration (the second derivative of position) must be considered, like in mechanics or wave propagation.\
- \
- For example, the motion of a pendulum can imply a second-order differential equation, integrating variables of acceleration and velocity. \
- Other practical examples include electronic circuits and spring-mass-damper systems. \
For differential equations, converting a higher-order equation into a system of first-order equations can simplify the process of solving them. This approach is particularly useful with numerical methods since many numerical algorithms are naturally expressed using first-order equations.
Converting a single second-order differential equation into two first-order equations, as seen in the exercise, helps in applying various solution techniques like matrix methods or software tools.
- In our exercise, the second-order equation is expressed as a system using two variables: \( x(t) \) and \( v(t) \).
- The resulting system is better suited for computational solving, enhancing conceptual understanding and numerical analysis.
In our example, the original equation \( \frac{d^{2} x}{d t^{2}} - 2 \frac{dx}{dt} = \frac{x}{2} \) involves the second derivative. To convert it into a system of first-order equations, follow these steps:
- **Define a new variable:** We introduce \( v(t) = \frac{dx}{dt} \), representing the first derivative of \( x \).
- **Express the second derivative:** Replace \( \frac{d^{2} x}{d t^{2}} \) with the derivative of \( v \), giving us \( \frac{dv}{dt} \).
- **Form the system:** Substitute \( v(t) \) and \( \frac{dv}{dt} \) in the original equation to form:
1. \( \frac{dx}{dt} = v \)
2. \( \frac{dv}{dt} = \frac{x}{2} + 2v \)
Other exercises in this chapter
Problem 36
Transform the second-order differential equation $$ \frac{d^{2} x}{d t^{2}}+\frac{d x}{d t}=2 x $$ into a system of first-order differential equations.
View solution Problem 37
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Some diseases are lethal; not every individual infected by the disease will recover; some will die. Assume that in one unit of time a fraction \(m\) of infected
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We consider differential equations of the form \(\frac{d \mathbf{x}}{d t}=A \mathbf{x}(t)\) where $$ A=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22
View solution