Problem 37
Question
The Henry's law constant for hydrogen gas \(\left(\mathrm{H}_{2}\right)\) in water at \(25^{\circ} \mathrm{C}\) is \(7.7 \times 10^{-6} \mathrm{M} / \mathrm{kPa}\) and the constant for argon (Ar) at \(25^{\circ} \mathrm{C}\) is \(1.4 \times 10^{-5} \mathrm{M} / \mathrm{kPa}\). If the two gases are each present at \(253 \mathrm{kPa}\) pressure, calculate the solubility of each gas.
Step-by-Step Solution
Verified Answer
The solubilities of hydrogen gas and argon at 25°C and 253 kPa are approximately \(1.95 \times 10^{-3} M\) and \(3.54 \times 10^{-3} M\), respectively.
1Step 1: Write down the given information
We are given the following:
- Henry's law constant for hydrogen gas (H₂) = \(7.7 \times 10^{-6} M/kPa\)
- Henry's law constant for argon (Ar) = \(1.4 \times 10^{-5} M/kPa\)
- Pressure of hydrogen and argon = 253 kPa
2Step 2: Apply Henry's law formula for hydrogen gas
Using the Henry's law formula, we can calculate the solubility of hydrogen in water:
\(C_{H_{2}} = k_{H_{2}} \cdot P_{H_{2}}\)
Plugging in the values:
\(C_{H_{2}} = (7.7 \times 10^{-6} M/kPa) \cdot (253 kPa)\)
3Step 3: Calculate the solubility of hydrogen gas
By performing the calculation:
\(C_{H_{2}} \approx 1.95 \times 10^{-3} M\)
So, the solubility of hydrogen gas is approximately \(1.95 \times 10^{-3} M\).
4Step 4: Apply Henry's law formula for argon
Similarly, we can calculate the solubility of argon in water:
\(C_{Ar} = k_{Ar} \cdot P_{Ar}\)
Plugging in the values:
\(C_{Ar} = (1.4 \times 10^{-5} M/kPa) \cdot (253 kPa)\)
5Step 5: Calculate the solubility of argon
By performing the calculation:
\(C_{Ar} \approx 3.54 \times 10^{-3} M\)
So, the solubility of argon is approximately \(3.54 \times 10^{-3} M\).
Therefore, the solubilities of hydrogen gas and argon at 25°C and 253 kPa are approximately \(1.95 \times 10^{-3} M\) and \(3.54 \times 10^{-3} M\), respectively.
Key Concepts
Gas SolubilityChemical EquilibriumSolution Concentration
Gas Solubility
The solubility of gases in liquids is an important topic in chemistry, especially when studying Henry's Law. When a gas dissolves in a liquid, it spreads evenly throughout the solution. This characteristic is influenced by several factors, such as temperature and pressure.
To quantify how well a gas dissolves in a liquid, often pressure-dependent, Henry's Law is used. It states that the concentration of a dissolved gas in a liquid is directly proportional to the partial pressure of that gas above the liquid. This relationship serves as a guiding principle to understand gas solubility. The formula for Henry's Law is:
To quantify how well a gas dissolves in a liquid, often pressure-dependent, Henry's Law is used. It states that the concentration of a dissolved gas in a liquid is directly proportional to the partial pressure of that gas above the liquid. This relationship serves as a guiding principle to understand gas solubility. The formula for Henry's Law is:
- \[ C = k_H \cdot P \]
- Where \( C \) is the concentration (or solubility) of the gas, \( k_H \) is Henry's Law constant specific to the gas and solvent, and \( P \) is the pressure of the gas.
Chemical Equilibrium
Chemical equilibrium refers to the state in a chemical reaction where the forward and reverse reactions occur at the same rate. This balance point is established when there is no net change in the concentration of reactants and products over time. While Henry's Law specifically deals with gas-liquid systems at equilibrium under constant conditions, understanding chemical equilibrium more broadly helps clarify how gases dissolve in and come out of solution.
In the context of Henry’s Law, equilibrium is achieved when the rate at which gas molecules enter the solution equals the rate at which they escape back into the gas phase. Thus, equilibrium plays a vital role in determining how and when solubility levels are maintained. Understanding this equilibrium is crucial for industries like environmental engineering, where careful balance of gas concentration is required to manage pollution levels.
In the context of Henry’s Law, equilibrium is achieved when the rate at which gas molecules enter the solution equals the rate at which they escape back into the gas phase. Thus, equilibrium plays a vital role in determining how and when solubility levels are maintained. Understanding this equilibrium is crucial for industries like environmental engineering, where careful balance of gas concentration is required to manage pollution levels.
Solution Concentration
Solution concentration is a measure of the amount of solute present in a given volume or mass of solvent. In the context of Henry's Law and gas solubility, it represents the concentration of dissolved gas in the liquid. Concentration is typically expressed in molarity (M), which is moles of solute per liter of solution.
The calculations for hydrogen and argon solubility in the exercise utilized concentration as the end result, expressed in molarity. High concentration implies a large amount of gas is dissolved in the solution. Multiple factors, including solute interactions, temperature, and pressure, affect concentration.
In practical terms, understanding solution concentration is key when considering the gas content in beverages, the behavior of gases in biological systems, and even in quantifying pollutants in water bodies. It is an essential concept in both everyday applications and advanced scientific research.
The calculations for hydrogen and argon solubility in the exercise utilized concentration as the end result, expressed in molarity. High concentration implies a large amount of gas is dissolved in the solution. Multiple factors, including solute interactions, temperature, and pressure, affect concentration.
In practical terms, understanding solution concentration is key when considering the gas content in beverages, the behavior of gases in biological systems, and even in quantifying pollutants in water bodies. It is an essential concept in both everyday applications and advanced scientific research.
Other exercises in this chapter
Problem 35
Indicate whether each statement is true or false: (a) The higher the temperature, the more soluble most gases are in water. (b) The higher the temperature, the
View solution Problem 36
Indicate whether each statement is true or false: (a) If you compare the solubility of a gas in water at two different temperatures, you find the gas is more so
View solution Problem 39
(a) Calculate the mass percentage of \(\mathrm{NaNO}_{3}\) in a solution containing \(13.6 \mathrm{~g}\) of \(\mathrm{NaNO}_{3}\) in \(834 \mathrm{~g}\) of wate
View solution Problem 40
(a) What is the mass percentage of iodine in a solution containing \(0.035 \mathrm{~mol} \mathrm{I}_{2}\) in \(125 \mathrm{~g}\) of \(\mathrm{CCl}_{4} ?\) (b) S
View solution