Problem 37
Question
The heat of fusion of mercury is \(2.72 \mathrm{cal} / \mathrm{g} .\) Calculate the quantity of energy transferred when 4.37 mol Hg freezes at a temperature of \(-39^{\circ} \mathrm{C}\).
Step-by-Step Solution
Verified Answer
The energy transferred is 2384.29 cal.
1Step 1: Convert Moles to Grams
First, we need to know the molar mass of mercury (Hg) to convert moles into grams. The molar mass of Hg is 200.59 g/mol. Multiply the number of moles by the molar mass:\[\text{Mass of } \text{Hg } = 4.37 \text{ mol} \times 200.59 \frac{\text{g}}{\text{mol}} = 876.58 \text{ g}\]
2Step 2: Calculate Energy Transferred
Use the heat of fusion to find the total energy transferred. The heat of fusion for mercury is given as 2.72 cal/g. Multiply the mass from Step 1 by this value to get the energy:\[\text{Energy transferred} = 876.58 \text{ g} \times 2.72 \frac{\text{cal}}{\text{g}} = 2384.29 \text{ cal}\]
Key Concepts
Energy TransferMolar Mass ConversionPhase Change Calculations
Energy Transfer
Understanding energy transfer is key when dealing with phase changes like freezing or melting. During such phase changes, energy is transferred from one phase to another. This energy does not change the temperature but instead facilitates the transformation of the state of matter. For example, when mercury freezes, it releases energy into its surroundings. This release of energy corresponds to the heat of fusion—the amount of energy needed to change mercury from a liquid to a solid at its freezing point without changing its temperature.
In our exercise, knowing that the heat of fusion for mercury is 2.72 cal/g, the focus is on calculating how much energy is released when all of the mercury turns from liquid to solid. Energy transfer calculations are an integral part of understanding thermal processes and thermodynamics. This concept is applied by multiplying the mass of mercury by its heat of fusion to find the total energy involved in the phase change.
In our exercise, knowing that the heat of fusion for mercury is 2.72 cal/g, the focus is on calculating how much energy is released when all of the mercury turns from liquid to solid. Energy transfer calculations are an integral part of understanding thermal processes and thermodynamics. This concept is applied by multiplying the mass of mercury by its heat of fusion to find the total energy involved in the phase change.
Molar Mass Conversion
Converting moles to grams is a straightforward yet vital step in many calculations involving chemical reactions or phase changes. The molar mass is a conversion factor that bridges moles, which are ideal for stoichiometric calculations, with grams, which are practical for laboratory measurements and calculations.
For mercury (Hg), the molar mass is provided as 200.59 g/mol. This value means that one mole of mercury, which contains Avogadro's number of atoms, has a mass of 200.59 grams. In the step-by-step solution, we multiplied the number of moles (4.37 mol for mercury) by the molar mass to find the total mass in grams:
For mercury (Hg), the molar mass is provided as 200.59 g/mol. This value means that one mole of mercury, which contains Avogadro's number of atoms, has a mass of 200.59 grams. In the step-by-step solution, we multiplied the number of moles (4.37 mol for mercury) by the molar mass to find the total mass in grams:
- Calculate mass: 4.37 mol × 200.59 g/mol
- Resulting in 876.58 grams of mercury
Phase Change Calculations
Phase change calculations involve using specific heat values that apply directly to the amount of matter experiencing a state transformation. In our scenario, we are addressing the freezing of mercury, a process where the physical state changes, thus requiring specific energy calculations.
The simple formula used for phase change is:
With the mass of mercury calculated to be 876.58 grams and the heat of fusion known (2.72 cal/g), we calculate the total energy released by multiplying these two values:
The simple formula used for phase change is:
- Energy = Mass × Heat of Fusion
With the mass of mercury calculated to be 876.58 grams and the heat of fusion known (2.72 cal/g), we calculate the total energy released by multiplying these two values:
- Energy = 876.58 grams × 2.72 cal/g = 2384.29 calories
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