Problem 37
Question
The given equation is either linear or equivalent to a linear equation. Solve the equation. \(\frac{2}{x}-5=\frac{6}{x}+4\)
Step-by-Step Solution
Verified Answer
The solution is \(x = -\frac{4}{9}\).
1Step 1: Identify the Linear Form
The given equation is \(\frac{2}{x} - 5 = \frac{6}{x} + 4\). We see that the terms \(\frac{2}{x}\) and \(\frac{6}{x}\) need to be grouped together to identify its linear form. This can be done by keeping all terms involving \(x\) on one side.
2Step 2: Simplify the Equation
Subtract \(\frac{6}{x}\) from both sides of the equation to isolate the terms involving \(x\): \[ \frac{2}{x} - \frac{6}{x} = 4 + 5 \] Simplify the equation by combining similar terms: \[ \frac{2}{x} - \frac{6}{x} = 9 \]
3Step 3: Combine the Fractions
Combine the fractions on the left side: \[ \frac{2-6}{x} = 9 \] which simplifies to: \[ \frac{-4}{x} = 9 \]
4Step 4: Solve for \(x\)
To solve for \(x\), multiply both sides by \(-x\) to get rid of the fraction: \[ -4 = 9x \]
5Step 5: Isolate \(x\)
Divide both sides by 9 to solve for \(x\): \[ x = \frac{-4}{9} \]
Key Concepts
Combining Like TermsFractional EquationsIsolating Variables
Combining Like Terms
In algebra, combining like terms is a fundamental skill that simplifies expressions and equations. When we combine like terms, we are essentially grouping similar items together to make the equation simpler and more manageable. In our exercise, we looked at terms \( \frac{2}{x} \) and \( \frac{6}{x} \). Both terms are fractional and share the same denominator.
To combine them, subtract the coefficients while keeping the common denominator intact. So, in this case:
To combine them, subtract the coefficients while keeping the common denominator intact. So, in this case:
- Subtract \( 6 \) from \( 2 \) to get \( -4 \).
- The expression becomes \( \frac{2}{x} - \frac{6}{x} = \frac{-4}{x} \).
Fractional Equations
Fractional equations can be a bit intimidating at first, as they involve fractions which many find tricky. However, understanding and manipulating these equations can be straightforward with the right steps.
In our exercise, the equation given is a fractional one:
In our exercise, the equation given is a fractional one:
- Original equation: \( \frac{2}{x} - 5 = \frac{6}{x} + 4 \)
- \( \frac{-4}{x} = 9 \)
Isolating Variables
Isolating variables is a key concept when solving equations. The goal is to transform the equation so that the variable is by itself on one side of the equals sign. This allows you to identify the solution directly.
In the exercise, after simplifying the fractional equation, we reached the stage where we had:
In the exercise, after simplifying the fractional equation, we reached the stage where we had:
- \( -4 = 9x \)
- \( x = \frac{-4}{9} \)
Other exercises in this chapter
Problem 37
Find all real solutions of the equation. $$ x^{2}+12 x-27=0 $$
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Evaluate the expression and write the result in the form a bi. $$ \frac{5-i}{3+4 i} $$
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