Problem 37
Question
$$\text { Solve each equation analytically. Check it analytically, and then support your solution graphically.}$$ $$\frac{5}{6} x-2 x+\frac{1}{3}=\frac{1}{3}$$
Step-by-Step Solution
Verified Answer
The solution is \( x = 0 \).
1Step 1: Simplify the Equation
Start by combining like terms on the left side of the equation. The equation given is \( \frac{5}{6}x - 2x + \frac{1}{3} = \frac{1}{3} \). Combine \( \frac{5}{6}x \) and \( -2x \). This simplifies to \(-\frac{7}{6}x + \frac{1}{3} = \frac{1}{3} \).
2Step 2: Isolate the Variable Term
Subtract \( \frac{1}{3} \) from both sides to isolate the term involving \( x \). This gives \(-\frac{7}{6}x = \frac{1}{3} - \frac{1}{3} \). Simplifying this results in \(-\frac{7}{6}x = 0 \).
3Step 3: Solve for \( x \)
To solve for \( x \), divide both sides of the equation by \(-\frac{7}{6} \). This results in \( x = 0 \). Such division confirms that \( x = 0 \) is indeed the solution.
4Step 4: Check the Solution
Substitute \( x = 0 \) back into the original equation to verify correctness. The original equation is \( \frac{5}{6}x - 2x + \frac{1}{3} = \frac{1}{3} \). Substitute \( 0 \) for \( x \) to get \( 0 - 0 + \frac{1}{3} = \frac{1}{3} \). This equality is true, confirming our solution is correct.
5Step 5: Graphical Support
Graph the expression \( y = \frac{5}{6}x - 2x + \frac{1}{3} \) and \( y = \frac{1}{3} \) as two separate lines on the same coordinate plane. The solution \( x = 0 \) matches the point where these two lines intersect, as both expressions yield \( y = \frac{1}{3} \) when \( x = 0 \).
Key Concepts
Equation SolvingGraphical VerificationAlgebraic Simplification
Equation Solving
Solving equations analytically involves performing algebraic operations to isolate the variable. In this case, the given equation can seem a bit tricky at first due to the presence of fractions. Let’s break it down step by step.
Here’s what was done in the solution:
Here’s what was done in the solution:
- **Combine Like Terms:** Starting with the equation \( \frac{5}{6}x - 2x + \frac{1}{3} = \frac{1}{3} \), the first step is to combine like terms, which are the terms involving \( x \): \( \frac{5}{6}x - 2x \) simplifies to \( -\frac{7}{6}x \).
- **Isolate the Variable Term:** Next, subtract \( \frac{1}{3} \) from both sides to get rid of the constant term on the left. This simplifies the equation to \( -\frac{7}{6}x = 0 \).
- **Solve for \( x \):** Finally, to solve for \( x \), divide both sides by \( -\frac{7}{6} \). This results in \( x = 0 \).
Graphical Verification
Graphical verification is a technique used to visually confirm the solution of an equation by plotting graphs. This method not only serves as a confirmation but also helps in understanding how equations behave visually.
In our case, the equation \( \frac{5}{6}x - 2x + \frac{1}{3} = \frac{1}{3} \) was represented by the lines:
In our case, the equation \( \frac{5}{6}x - 2x + \frac{1}{3} = \frac{1}{3} \) was represented by the lines:
- **First line:** \( y = \frac{5}{6}x - 2x + \frac{1}{3} \)
- **Second line:** \( y = \frac{1}{3} \)
Algebraic Simplification
Algebraic simplification is an essential part of solving equations. It involves reducing an expression to its simplest form to make calculations more straightforward.
### Steps of Simplification
### Steps of Simplification
- **Identify Like Terms:** Combine terms that involve the same variables. This is crucial as it reduces the complexity of the expression.
- **Eliminate Fractions:** Adjust the terms involving fractions, such as \( \frac{5}{6}x \) in our example, by common denominators or direct calculations to simplify the equation further.
- **Simplify Constants:** Deal with constant terms independently, as seen with \( \frac{1}{3} \), ensuring their smooth transition from one side of the equation to the other.
Other exercises in this chapter
Problem 37
Graph each linear function on a graphing calculator, using the two different windows given. State which window gives a comprehensive graph. $$f(x)=3 x+10$$ Wind
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In Exercises \(37-40,\) find the constant of variation \(k\) and the undetermined value in the table if \(y\) is directly proportional to \(x\). $$\begin{array}
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Name the possible quadrants in which the point ( \(x, y\) ) can lie if the given condition is true. $$\frac{x}{y}
View solution Problem 38
Write equation in the form \(y=m x+b .\) (A suggested window for a comprehensive graph of the equation is given. \(6 x+5 y=9\) \([-10,10]\) by \([-10,10]\)
View solution