Problem 37
Question
Sound Wave A note produced by a certain musical instrument results in a sound wave described by $$ f(t)=0.03 \sin 500 \pi t+0.03 \sin 1000 \pi t $$ where \(f(t)\) is the difference between atmospheric pressure and air pressure in dynes per square centimeter at the eardrum after \(t\) seconds. Express \(f\) as the product of a sine and a cosine function.
Step-by-Step Solution
Verified Answer
\( f(t) = 0.06 \sin(750\pi t) \cos(250\pi t) \).
1Step 1: Identify the Trigonometric Identity
The goal is to express the given function as a product of a sine and a cosine function. Observing both sinusoidal expressions \( \sin 500 \pi t \) and \( \sin 1000 \pi t \), we can employ the sum-to-product identity: \( \sin A + \sin B = 2 \sin \left( \frac{A + B}{2} \right) \cos \left( \frac{A - B}{2} \right) \).
2Step 2: Apply the Sum-to-Product Identity
We have \( A = 1000\pi t \) and \( B = 500\pi t \). Substitute these values into the identity: \[ f(t) = 0.03 \left( \sin(1000\pi t) + \sin(500\pi t) \right) = 0.03 \cdot 2 \sin \left( \frac{1000\pi t + 500\pi t}{2} \right) \cos \left( \frac{1000\pi t - 500\pi t}{2} \right). \]
3Step 3: Simplify the Expression
Calculate \( \frac{1000\pi t + 500\pi t}{2} = 750\pi t \) and \( \frac{1000\pi t - 500\pi t}{2} = 250\pi t \). Substitute these into the expression: \[ f(t) = 0.06 \sin(750\pi t) \cos(250\pi t). \]
4Step 4: Final Expression
Now, we express \( f(t) \) as desired: \( f(t) = 0.06 \sin(750\pi t) \cos(250\pi t) \). This is the equivalent expression of the sound wave in product form.
Key Concepts
Sum-to-Product IdentityProduct-to-Sum IdentitiesSound WavesSinusoidal Functions
Sum-to-Product Identity
The sum-to-product identity is a useful tool in trigonometry. It helps us convert the sum of two sinusoidal functions into a product form. This is particularly valuable when dealing with wave interference and beat frequencies. For sine functions, the identity is expressed as:
For example, in a sound wave context, this identity allows us to understand how different frequency components interact. It is particularly valuable when trying to see how different pitches mix and create what we perceive as harmonics.
- \( \sin A + \sin B = 2 \sin \left( \frac{A+B}{2} \right) \cos \left( \frac{A-B}{2} \right) \)
For example, in a sound wave context, this identity allows us to understand how different frequency components interact. It is particularly valuable when trying to see how different pitches mix and create what we perceive as harmonics.
Product-to-Sum Identities
Just as the sum-to-product identity helps simplify the sum of trigonometric functions into a product, the product-to-sum identities reverse the process. These identities are:
By converting products to sums, we can analyze how two different frequencies interact. This can be essential in understanding phenomena like modulation and beat frequencies in sound engineering.
- \( \sin A \cos B = \frac{1}{2} \left( \sin(A+B) + \sin(A-B) \right) \)
- \( \cos A \sin B = \frac{1}{2} \left( \sin(A+B) - \sin(A-B) \right) \)
- \( \cos A \cos B = \frac{1}{2} \left( \cos(A+B) + \cos(A-B) \right) \)
- \( \sin A \sin B = \frac{1}{2} \left( \cos(A-B) - \cos(A+B) \right) \)
By converting products to sums, we can analyze how two different frequencies interact. This can be essential in understanding phenomena like modulation and beat frequencies in sound engineering.
Sound Waves
Sound waves are a type of pressure wave traveling through a medium such as air. They consist of compressions and rarefactions, which we perceive as sound. In mathematics, sound waves are often expressed using sinusoidal functions due to their oscillatory nature.
When instruments produce sound, they generate waves that can be described by trigonometric functions like sine and cosine. Each wave corresponds to different sound properties such as frequency (pitch) and amplitude (loudness).
The study of sound waves involves looking at how these waves combine and interact. This is where trigonometric identities become useful, simplifying complex expressions. By using these identities, we gain insight into harmonics and resonance.
Understanding sound waves through trigonometry helps in various applications, from music technology to acoustics engineering.
When instruments produce sound, they generate waves that can be described by trigonometric functions like sine and cosine. Each wave corresponds to different sound properties such as frequency (pitch) and amplitude (loudness).
The study of sound waves involves looking at how these waves combine and interact. This is where trigonometric identities become useful, simplifying complex expressions. By using these identities, we gain insight into harmonics and resonance.
Understanding sound waves through trigonometry helps in various applications, from music technology to acoustics engineering.
Sinusoidal Functions
Sinusoidal functions, which include sine and cosine functions, are fundamental in modeling periodic phenomena. These functions accurately depict how variables oscillate over time, making them essential in studies of waves, particularly sound waves.
Key characteristics of sinusoidal functions include their amplitude, frequency, and phase shift:
By examining sinusoidal functions, we can break down complex sound signals into simpler wave components, analyze them individually, and understand how different wavelengths contribute to the resulting waveforms we hear.
Key characteristics of sinusoidal functions include their amplitude, frequency, and phase shift:
- **Amplitude** represents the wave's height and is related to the volume in sound waves.
- **Frequency** determines how rapidly the wave oscillates, corresponding with the pitch of a sound.
- **Phase Shift** indicates how the wave aligns relative to the origin of time.
By examining sinusoidal functions, we can break down complex sound signals into simpler wave components, analyze them individually, and understand how different wavelengths contribute to the resulting waveforms we hear.
Other exercises in this chapter
Problem 36
Justify the given statement with one of the properties of the trigonometric functions. $$ \cos 16.8 \pi=\cos 14.8 \pi $$
View solution Problem 36
Use a half-angle formula to find the exact value of the given trigonometric function. Do not use a calculator. $$ \sin (\pi / 8) $$
View solution Problem 37
Find the period and the vertical asymptotes of the given function. Sketch at least one cycle of the graph. $$ y=-\sec x $$
View solution Problem 37
Verify the given identity. $$ \frac{\tan ^{2} \beta}{1+\cos \beta}=\frac{\sec \beta-1}{\cos \beta} $$
View solution