Problem 37
Question
Solve each inequality using a graph, a table, or algebraically. $$ x^{2}+12 x<-36 $$
Step-by-Step Solution
Verified Answer
No solution exists, as the quadratic never falls below zero.
1Step 1: Set the Inequality as a Quadratic Equation
First, we need to transform the inequality into a quadratic equation by replacing the inequality sign with an equality. So we have: \( x^{2} + 12x + 36 = 0 \). This will help us to find the boundary values.
2Step 2: Solve the Quadratic Equation
We solve \( x^{2} + 12x + 36 = 0 \) to find the roots. First, we recognize this as a perfect square trinomial: \( (x + 6)^2 = 0 \). Therefore, the root is \( x = -6 \). This tells us that the graph of the quadratic touches the x-axis at this point.
3Step 3: Determine the Nature of the Inequality
The inequality \( x^{2} + 12x + 36 < 0 \) implies the parabola is below the x-axis. Since \( (x + 6)^2 \) is only zero at \( x = -6 \) and positive otherwise, there is no solution where \( x^{2} + 12x + 36 < 0 \).
4Step 4: Check the Solution
Re-evaluate to ensure the steps are correct. Observing the nature of \( (x + 6)^2 \), it's evident that \( x^{2} + 12x + 36 \) cannot be less than zero, confirming no solution exists for \( x^{2} + 12x + 36 < 0 \).
Key Concepts
Graphing InequalitiesQuadratic Equation RootsPerfect Square Trinomial
Graphing Inequalities
Exploring quadratic inequalities through graphing can make them more approachable. When graphing a quadratic inequality like \(x^{2} + 12x < -36\), it involves visualizing where the quadratic expression is above or below the x-axis.
The inequality is first converted into an equation format: \(x^{2} + 12x + 36 = 0\). By plotting the graph of \(y = x^{2} + 12x + 36\), we get a parabola. The orientation of this parabola is upwards since the coefficient of \(x^2\) is positive.
The inequality is first converted into an equation format: \(x^{2} + 12x + 36 = 0\). By plotting the graph of \(y = x^{2} + 12x + 36\), we get a parabola. The orientation of this parabola is upwards since the coefficient of \(x^2\) is positive.
- The vertex represents the maximum or minimum point of the parabola.
- The x-intercepts are the points where the parabola crosses the x-axis.
Quadratic Equation Roots
Finding the roots of a quadratic equation is essential when analyzing inequalities. Roots indicate where the parabola crosses the x-axis, marking crucial points for solving the inequality.
The inequality \(x^{2} + 12x < -36\) translates to \(x^{2} + 12x + 36 = 0\). Identifying the roots involves solving \(x^{2} + 12x + 36 = 0\).
The inequality \(x^{2} + 12x < -36\) translates to \(x^{2} + 12x + 36 = 0\). Identifying the roots involves solving \(x^{2} + 12x + 36 = 0\).
- This quadratic is recognized as a perfect square trinomial, \((x + 6)^2\).
- Simplifying \((x + 6)^2 = 0\) yields a double root: \(x = -6\).
Perfect Square Trinomial
A perfect square trinomial is a quadratic that can be factored into identical binomials squared. Recognizing such trinomials simplifies solving processes for quadratic inequalities.
In the exercise \(x^{2} + 12x + 36 < 0\), converting to an equation we get \(x^{2} + 12x + 36 = 0\). We identify \((x + 6)^2 = 0\) as a perfect square trinomial. This means:
In the exercise \(x^{2} + 12x + 36 < 0\), converting to an equation we get \(x^{2} + 12x + 36 = 0\). We identify \((x + 6)^2 = 0\) as a perfect square trinomial. This means:
- The quadratic is the square of a binomial \((x + 6)\).
- It expands to \(x^{2} + 12x + 36\).
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