Problem 37
Question
Solve each inequality. Graph the solution set and write the answer in interval notation. $$|8 k+5| \geq 0$$
Step-by-Step Solution
Verified Answer
In this inequality, since an absolute value is always non-negative, the inequality \(|8k + 5| \geq 0\) is true for all k. The solution is \(k \geq -\frac{5}{8}\), and in interval notation, the solution set is \([- \frac{5}{8}, \infty)\].
1Step 1: Case 1: The expression inside the absolute value is non-negative
We first consider the case where the expression inside the absolute value is non-negative, i.e., \(8k + 5 \geq 0\). In this case, the inequality becomes:
$$|8k + 5| \geq 0 \Rightarrow 8k + 5 \geq 0$$
To solve for k, we just need to isolate k:
$$8k \geq -5$$
Divide both sides by 8:
$$k \geq -\frac{5}{8}$$
2Step 2: Case 2: The expression inside the absolute value is negative
Now we consider the case where the expression inside the absolute value is negative, i.e., \(8k + 5 < 0\). In this case, the inequality becomes:
$$|- (8k + 5)| \geq 0 \Rightarrow -(8k + 5) \geq 0$$
We solve for k:
$$-8k - 5 \geq 0$$
$$-8k \geq 5$$
Divide both sides by -8 and remember to reverse the inequality sign:
$$k \leq -\frac{5}{8}$$
3Step 3: Combining the solutions
Notice that both cases lead us to the same inequality, \(k \geq -\frac{5}{8}\). Since an absolute value is always non-negative, the inequality \(|8k + 5| \geq 0\) is true for all k because the absolute value of a number is always greater than or equal to 0.
4Step 4: Graph the solution set
To graph this solution, we draw a number line with k on the horizontal axis. Since k is greater than or equal to -5/8, we place a solid dot at -5/8 and then shade the number line to the right of -5/8 to indicate that k can be any number greater than or equal to -5/8.
5Step 5: Write the answer in interval notation
Since the inequality includes all values of k greater than or equal to -5/8, the interval notation for the solution is:
\[[-\frac{5}{8}, \infty)\]
Key Concepts
Understanding Absolute Value InequalitiesGraphing Absolute Value InequalitiesInterval Notation Simplified
Understanding Absolute Value Inequalities
Absolute value inequalities involve finding the set of values that satisfy an inequality containing an absolute value expression. In this case, the expression is \(|8k + 5| \geq 0\). The absolute value \(|x|\) represents the distance of \(x\) from zero on the number line, so it's never negative. This means any expression, when within absolute value brackets, is always zero or positive.
- When solving inequalities like \(|8k + 5| \geq 0\), we realize it's always true, because absolute values are always zero or greater.
- The solution involves checking the conditions when the expression inside the absolute value is positive, zero, or negative to see their impact on the inequality.
- For such cases, the entire real number set often becomes a solution since the condition itself always holds true in all instances.
Graphing Absolute Value Inequalities
Graphing the solution of an inequality gives a visual way to understand all possible values that satisfy the inequality. Here, we look at \(8k + 5\) and determine the values of \(k\) that make \(|8k + 5| \geq 0\) true.
- Once you identify the inequalities for \(k\), depict these on a number line.
- In this example, since the inequality holds for all \(k\), the number line will be entirely shaded to indicate every number satisfies the condition.
- A closed dot at the starting point \(-\frac{5}{8}\) will show inclusivity in the solution, representing \(k\) can be equal to \(-\frac{5}{8}\) and any number greater.
Interval Notation Simplified
Interval notation is a concise way to represent sets of solutions or subsets of the number line. In solving \(|8k + 5| \geq 0\), interval notation efficiently captures the solution.
- Intervals are shown using brackets. A square bracket \([\) or \(]\) indicates the number is included in the set, while a parenthesis \((\) or \()\) indicates it's not included.
- For this inequality, all real numbers satisfy the inequality, starting from \(-\frac{5}{8}\), inclusive, to infinity.
- In interval notation, this is captured as \([-\frac{5}{8}, \infty)\), where \(-\frac{5}{8}\) is included, and infinity is never included, as it represents an idea, not a specific number.
Other exercises in this chapter
Problem 36
Graph using either the test point or slope-intercept method. \(y \leq 4\)
View solution Problem 36
Solve the following equations containing two absolute values. $$|j-8|=|4 j-7|$$
View solution Problem 37
Graph using either the test point or slope-intercept method. \(3 x-4 y>12\)
View solution Problem 37
Solve the following equations containing two absolute values. $$|3 z+2|=|6-5 z|$$
View solution