Problem 37
Question
Solve each equation. If a solution is extraneous, so indicate. \(4-\frac{3 x}{x-9}=\frac{5 x-72}{x-9}\)
Step-by-Step Solution
Verified Answer
The equation has an extraneous solution: \(x = 9\).
1Step 1: Set the Denominators to Be the Same
The denominators on both sides of the equation are already the same: \(x-9\). This allows us to multiply each term by \(x-9\) to remove the denominators.
2Step 2: Remove the Denominators
Multiply each term by \(x-9\) to eliminate the fractions: \[ (4 - \frac{3x}{x-9}) \cdot (x-9) = \frac{5x-72}{x-9} \cdot (x-9) \]This simplifies to:\[ 4(x-9) - 3x = 5x - 72 \]
3Step 3: Simplify the Equation
Distribute and simplify the terms:\[ 4x - 36 - 3x = 5x - 72 \]Combine like terms:\[ x - 36 = 5x - 72 \]
4Step 4: Isolate the Variable
Rearrange the equation to isolate \(x\) on one side:\[ x - 5x = -72 + 36 \]Simplify both sides:\[ -4x = -36 \]
5Step 5: Solve for x
Divide both sides by -4:\[ x = \frac{-36}{-4} \]\[ x = 9 \]
6Step 6: Check for Extraneous Solutions
Substitute \(x = 9\) back into the original equation to check for validity.The original denominators \(x-9\) become 0 when \(x = 9\), which makes the equation undefined. Thus, \(x = 9\) is an extraneous solution.
Key Concepts
Rational EquationsFractions in AlgebraSimplifying Equations
Rational Equations
Rational equations are equations that involve fractions in which the numerator, the denominator, or both contain polynomials. Solving rational equations is all about finding the value of the variable that makes the equation true. In these equations, the key is to eliminate the fractions by finding a common denominator or appropriately multiplying both sides to clear out the fractions.
Let's break it down:
Let's break it down:
- Identify Rational Equation: Recognize that if the equation has fractions involving variables, it's a rational equation. For example, in our original exercise, the equation \(4-\frac{3x}{x-9}=\frac{5x-72}{x-9}\) is a rational equation.
- Clear the Denominator: To solve such equations, eliminate the fractions by multiplying every term by the least common denominator. This leaves you with a simpler equation to solve.
Fractions in Algebra
Fractions in algebra can make solving equations look much more complicated. However, understanding how to manage and simplify fractions is crucial. Here’s how to approach fractions within algebraic equations:
- Find the Common Denominator: It's important to consider the least common denominator when you want to add or subtract fractions. This step is essential in combining fractions into a single expression.
- Elimination of Fractions: In the original exercise, fractions were removed by multiplying the entire equation by the common denominator \(x-9\) simplifying the equation substantially.
- Consider Operations on Fractions: When you multiply or divide fractions, remember to apply the fundamental rules such as multiplying across the numerators and denominators or flipping the fraction and multiplying it when dividing by a fraction.
Simplifying Equations
Simplifying equations is a crucial step toward finding the solution. It allows you to strip down an equation to its simplest form, making it easier to handle:
- Distribute and Simplify: Once the fractions are removed, distribute any multipliers through the parentheses to clean up the equation. In the exercise, the step from \[4(x-9) - 3x = 5x - 72\] to \[x - 36 = 5x - 72\] involved simple distribution and combining like terms.
- Isolate the Variable: Aim to have the variable on one side of the equation. Rearrange terms by using operations such as addition or subtraction until it's isolated. This involves keeping the balance by doing the same operation to both sides of the equation.
- Combine and Solve: After isolating the variable, solve the simplified form of the equation. Do the arithmetic to find the value of the variable, as in solving \[-4x = -36\] which led to \(x = 9\).
Other exercises in this chapter
Problem 36
Simplify each rational expression. $$ \frac{15 y^{2}}{5 y^{3}+15 y^{2}} $$
View solution Problem 37
Simplify each complex fraction. See Example 6. $$ \frac{\frac{2}{x+3}-\frac{1}{x-3}}{\frac{3}{x^{2}-9}} $$
View solution Problem 37
Express each verbal model in symbols. See Objectives 5 and 6. \(A\) varies directly as the square of \(p\)
View solution Problem 37
Perform each division. \(\frac{6 x^{3}+11 x^{2}-19 x-2}{3 x-2}\)
View solution