Problem 37
Question
Solve each equation. Give an exact solution and a four-decimal-place approximation. $$ \ln x=-2.3 $$
Step-by-Step Solution
Verified Answer
Exact solution: \( x = e^{-2.3} \), Approximation: \( x \approx 0.1003 \).
1Step 1: Understand the Equation
We need to solve the equation \( \ln x = -2.3 \). The \( \ln \) function (natural logarithm) is the inverse of the exponential function with base \( e \).
2Step 2: Use Inverse Operations
To solve the equation \( \ln x = -2.3 \), we use the property that if \( \ln x = a \), then \( x = e^a \). Therefore, we have \( x = e^{-2.3} \).
3Step 3: Calculate the Exact Solution
Calculating \( e^{-2.3} \) gives us the exact solution \( x = e^{-2.3} \). This describes \( x \) in terms of the mathematical constant \( e \).
4Step 4: Compute the Approximation
Using a calculator, evaluate \( e^{-2.3} \). This gives us approximately \( x \approx 0.1003 \) when rounded to four decimal places.
Key Concepts
Exponential FunctionInverse OperationsMathematical ConstantApproximations
Exponential Function
The exponential function is one of the most important concepts in mathematics. It is often represented as \( f(x) = e^x \), where \( e \) is the base of the natural logarithm. The function describes how quantities grow at a consistent relative rate, making it crucial in fields like finance, physics, and biology.
The exponential function has some key properties:
The exponential function has some key properties:
- The function is always positive for all real numbers \( x \).
- The graph of \( e^x \) is an increasing curve that starts above zero and rises sharply.
- It passes through the point \( (0,1) \) since \( e^0 = 1 \).
Inverse Operations
Inverse operations are operations that "undo" each other. In the context of logarithms and exponentials, they are particularly essential.
When we say that logarithms and exponential functions are inverses, it means that the logarithm function \( \ln x \) will undo an exponential function with base \( e \), and vice versa. This is captured by the equation: \[ \ln(e^x) = x \text{ and } e^{\ln x} = x \]
For example, solving \( \ln x = -2.3 \) requires translating this using the inverse exponential operation. Therefore, applying the inverse operation to both sides leads us to \( x = e^{-2.3} \). This enables us to "reverse" the natural logarithm function to find the exact value of \( x \).
Understanding inverse operations is crucial to solving equations involving exponential and logarithmic expressions.
When we say that logarithms and exponential functions are inverses, it means that the logarithm function \( \ln x \) will undo an exponential function with base \( e \), and vice versa. This is captured by the equation: \[ \ln(e^x) = x \text{ and } e^{\ln x} = x \]
For example, solving \( \ln x = -2.3 \) requires translating this using the inverse exponential operation. Therefore, applying the inverse operation to both sides leads us to \( x = e^{-2.3} \). This enables us to "reverse" the natural logarithm function to find the exact value of \( x \).
Understanding inverse operations is crucial to solving equations involving exponential and logarithmic expressions.
Mathematical Constant
The mathematical constant \( e \), approximately 2.71828, is fundamental to exponential and logarithmic functions. Much like the famous \( \pi \), \( e \) is an irrational number, meaning it cannot be written as a simple fraction, and its decimal representation goes on forever without repeating.
This constant emerges naturally in many areas of mathematics:
This constant emerges naturally in many areas of mathematics:
- In calculus, as the base of natural logarithms and the limit of continuous compound interest.
- In complex analysis, where \( e^{i\pi} + 1 = 0 \), known as Euler's identity, elegantly ties together fundamental constants \( e, i, \pi \).
Approximations
In mathematics, approximations are used when exact values are complex or impossible to derive in a straightforward manner. Approximations provide a way to work practically with numbers that have more precision than needed.
When you calculate \( e^{-2.3} \), it does not yield a simple rational number. Instead, the calculator shows several decimal places, such as \( 0.1002588...\). However, for practical purposes, we often round these numbers to make calculations manageable, conveying this solution as \( x \approx 0.1003 \) rounded to four decimal places.
This kind of rounding can be particularly useful in science and engineering where numbers need to be concise, yet precise enough for usage in real-world scenarios. Understanding the balance between exactness and practicality is a valuable skill in both academic and professional contexts.
When you calculate \( e^{-2.3} \), it does not yield a simple rational number. Instead, the calculator shows several decimal places, such as \( 0.1002588...\). However, for practical purposes, we often round these numbers to make calculations manageable, conveying this solution as \( x \approx 0.1003 \) rounded to four decimal places.
This kind of rounding can be particularly useful in science and engineering where numbers need to be concise, yet precise enough for usage in real-world scenarios. Understanding the balance between exactness and practicality is a valuable skill in both academic and professional contexts.
Other exercises in this chapter
Problem 37
Use the formula \(A=P\left(1+\frac{r}{n}\right)^{n t}\) to solve these compound interest problems. Round to the nearest tenth. How long does it take for a \(\$
View solution Problem 37
Find the value of each logarithmic expression. $$ \log _{6} 1 $$
View solution Problem 37
Solve each equation for \(y .\) $$ x=y+2 $$
View solution Problem 37
Find the inverse of each one-to-one function. $$ f(x)=(x+2)^{3} $$
View solution