Problem 37
Question
Solve each equation and check your proposed solution in Exercises. Begin your work by rewriting each equation without fractions. $$\frac{x}{3}+\frac{x}{2}=\frac{5}{6}$$
Step-by-Step Solution
Verified Answer
The solution for the equation is x = 1.
1Step 1: Rewrite the equation without fractions
The least common denominator (LCD) between 3, 2, and 6 is 6. Multiply each term by 6 to eliminate the fractions: \(6*\frac{x}{3} + 6*\frac{x}{2} = 6*\frac{5}{6}\). This simplifies to \(2x + 3x = 5\). Combining like terms gives \(5x = 5\).
2Step 2: Solve for x
Divide the entire equation by 5 to isolate x: \(x = 1\).
3Step 3: Check the solution
Substitute x = 1 back into the original equation: \( \frac{1}{3} + \frac{1}{2} = ? \). Simplifying the left side gives \(\frac{5}{6}\), which equals the right side of the equation, verifying that x = 1 is indeed the correct solution.
Key Concepts
Understanding the Least Common DenominatorCombining Like TermsChecking Solutions
Understanding the Least Common Denominator
When working with equations that involve fractions, the first step to simplifying is finding the least common denominator, often abbreviated as LCD. The LCD is the smallest number that each of the denominators in the equation can divide into without leaving a remainder. This concept helps in converting all fractions into whole numbers, making it easier to solve the equation.
For our exercise equation, \(\frac{x}{3} + \frac{x}{2} = \frac{5}{6}\), the denominators are 3, 2, and 6. Here are some steps to find the LCD:
For our exercise equation, \(\frac{x}{3} + \frac{x}{2} = \frac{5}{6}\), the denominators are 3, 2, and 6. Here are some steps to find the LCD:
- List the multiples of each denominator: 3 (3, 6, 9...), 2 (2, 4, 6...), and 6 (6, 12, 18...)
- Identify the smallest common multiple, which in this case is 6.
- Use this common denominator to rewrite each term and eliminate the fractions in the equation.
Combining Like Terms
Once you eliminate fractions from an equation, the next step is to simplify it by combining like terms. Like terms are those that have the same variable raised to the same power. Combining them helps to condense the equation further, making it easier to solve.
After rewriting our exercise equation to \(2x + 3x = 5\), we can combine the terms involving \(x\). Here are how you do it:
After rewriting our exercise equation to \(2x + 3x = 5\), we can combine the terms involving \(x\). Here are how you do it:
- Add the coefficients of the like terms together: \(2 + 3 = 5\).
- The equation therefore simplifies to \(5x = 5\).
Checking Solutions
Once you've found the solution to an equation, it's crucial to verify its correctness. This step ensures that no errors occurred during simplification or calculations.
For the equation \(\frac{x}{3} + \frac{x}{2} = \frac{5}{6}\), we found that \(x = 1\). Checking the solution involves substituting this value back into the original equation and ensuring both sides are equal.
For the equation \(\frac{x}{3} + \frac{x}{2} = \frac{5}{6}\), we found that \(x = 1\). Checking the solution involves substituting this value back into the original equation and ensuring both sides are equal.
- Replace \(x\) with 1: \(\frac{1}{3} + \frac{1}{2} = ?\)
- Find a common denominator for these fractions, which is 6.
- Convert each fraction: \(\frac{1}{3} = \frac{2}{6}\) and \(\frac{1}{2} = \frac{3}{6}\).
- Add them: \(\frac{2}{6} + \frac{3}{6} = \frac{5}{6}\).
- The resulting \(\frac{5}{6}\) matches the right side of the equation, confirming \(x = 1\) is correct.
Other exercises in this chapter
Problem 37
Solve each equation in using both the addition and multiplication properties of equality. Check proposed solutions. $$12=4 z+3$$
View solution Problem 37
Use the percent formula, \(A=P B: A\) is \(P\) percent of \(B,\) to solve. What percent of 2.5 is \(0.3 ?\)
View solution Problem 38
Solve each equation using the addition property of equality. Be sure to check your proposed solutions. $$\frac{7}{3}=-\frac{5}{2}+z$$
View solution Problem 38
Find the measure of the complement of each angle. $$41^{\circ}$$
View solution