Problem 37
Question
Solve each equation. $$ 4 x^{3}-x=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 0\), \(x = \frac{1}{2}\), and \(x = -\frac{1}{2}\).
1Step 1: Factor the Equation
First, factor out the common term in the equation. Notice that both terms in the equation share a factor of \(x\). Factor \(x\) out of the equation: \(x(4x^2 - 1) = 0\).
2Step 2: Apply the Zero Product Property
According to the zero product property, if a product of two factors equals zero, then at least one of the factors must be zero. Thus, set each factor equal to zero: \(x = 0\) or \(4x^2 - 1 = 0\).
3Step 3: Solve the First Equation
The first factor is \(x = 0\). This equation is already solved, giving us the solution \(x = 0\).
4Step 4: Solve the Second Equation
The second factor needs more work: \(4x^2 - 1 = 0\). Solve this equation by first adding 1 to both sides to get \(4x^2 = 1\). Then, divide both sides by 4 to isolate \(x^2\), yielding \(x^2 = \frac{1}{4}\).
5Step 5: Take the Square Root
To solve for \(x\), take the square root of both sides of the equation \(x^2 = \frac{1}{4}\). Remember the square root will yield both positive and negative solutions: \(x = \pm\frac{1}{2}\).
Key Concepts
Factoring EquationsZero Product PropertySquare Roots
Factoring Equations
Factoring equations is an essential skill in algebra that helps simplify complex mathematical expressions. In the given exercise, we have the cubic equation, \[ 4x^{3} - x = 0. \]Our aim is to break down this expression into simpler parts so we can solve it easily.
One fundamental technique is identifying common factors in each term. Here, the common factor is \(x\). By factoring out \(x\), the equation transforms into:
One fundamental technique is identifying common factors in each term. Here, the common factor is \(x\). By factoring out \(x\), the equation transforms into:
- \( x(4x^2 - 1) = 0 \)
Zero Product Property
The Zero Product Property is a foundational principle in algebra. It states that if a product of two terms equals zero, then at least one of the terms must be zero.
In our factored equation,
In our factored equation,
- \( x(4x^2 - 1) = 0 \)
- \( x = 0 \)
- \( 4x^2 - 1 = 0 \)
Square Roots
Taking the square root is a common technique in solving quadratic equations and other algebraic expressions. In our example, one of the factoring results we got was:
- \( 4x^2 - 1 = 0 \)
- Add 1 to both sides: \(4x^2 = 1 \)
- Divide by 4: \(x^2 = \frac{1}{4} \)
- \( x = \pm \frac{1}{2} \)
Other exercises in this chapter
Problem 37
Factor out the GCF from each polynomial. $$ 6 x^{3}-9 x^{2}+12 x $$
View solution Problem 37
Factor each trinomial completely. Some of these trinomials contain a greatest common factor (other than 1). Don't forget to factor out the GCF first. $$ 3 x^{2}
View solution Problem 38
Factor each completely. $$ (x-1)^{2}-z^{2} $$
View solution Problem 38
At the end of 2 years, \(P\) dollars invested at an interest rate \(r\) compounded annually increases to an amount, \(A\) dollars, given by $$ A=P(1+r)^{2} $$ F
View solution