Problem 37
Question
Solve each compound inequality and graph the solution sets. Express the solution sets in interval notation. \(x+2<-3\) or \(x+2>3\)
Step-by-Step Solution
Verified Answer
\((-\infty, -5)\) or \((1, \infty)\)
1Step 1: Solve the first inequality
First, isolate the variable in the inequality \( x + 2 < -3 \). Subtract 2 from both sides to solve for \( x \):\[x + 2 - 2 < -3 - 2 \x < -5\]This gives us one of the solutions: \( x < -5 \).
2Step 2: Solve the second inequality
Next, solve the other part of the compound inequality \( x + 2 > 3 \). Again, subtract 2 from both sides to get:\[x + 2 - 2 > 3 - 2 \x > 1\]This gives us the second solution: \( x > 1 \).
3Step 3: Combine solutions for the compound inequality
The compound inequality is represented by the word 'or,' which means we combine the two solutions. The solution set is all \( x \) such that \( x < -5 \) or \( x > 1 \).
4Step 4: Express in interval notation
To express the solution set \( x < -5 \) or \( x > 1 \) in interval notation:\[x < -5 \Rightarrow (-\infty, -5) \x > 1 \Rightarrow (1, \infty)\]Thus, the interval notation for the solution set is:\[(-\infty, -5) \, \text{or} \, (1, \infty)\]
5Step 5: Graph the solution sets
On a number line, graph the solutions \( x < -5 \) and \( x > 1 \):1. \((-\infty, -5)\) is represented by a line starting from the left going to -5 with an open circle at -5.2. \((1, \infty)\) is represented by a line starting at 1 with an open circle and going to the right.Both intervals are graphed separately, indicating that no numbers between -5 and 1 are part of the solution.
Key Concepts
Graphing InequalitiesInterval NotationSolving Inequalities
Graphing Inequalities
Understanding how to graph inequalities is essential for visualizing solution sets on a number line. When graphing inequalities like \( x < -5 \) or \( x > 1 \), follow these simple steps:
- First, determine whether to use open or filled circles. For strict inequalities like \( < \) or \( > \), use open circles to indicate that the boundary point is not included.
- Next, draw a line on the number line to represent all the numbers that are part of the solution. For \( x < -5 \), the line starts at the open circle on -5 and extends indefinitely to the left.
- Similarly, for \( x > 1 \), place an open circle on 1 and draw the line extending to the right, showing that all numbers greater than 1 are included.
Interval Notation
Interval notation is a compact way of describing a set of numbers along the real line. It is effective for expressing solutions to inequalities. Here's how it works:
- Use parentheses \( () \) for numbers that are not included in the solution set, relating to open circles on a graph.
- Use square brackets \( [] \) if a number is included, but in the case of our exercise, both solutions \( (-\infty, -5) \) or \( (1, \infty) \) use parentheses.
- The symbol \( -\infty \) or \( \infty \) is always accompanied by a parenthesis, because infinity is a concept, not a specific point you can reach or include.
Solving Inequalities
Solving inequalities involves isolating the variable of interest. When working with compound inequalities, tackle each part separately. Here's how you can solve a simple linear inequality:
- First, focus on isolating the variable. In \( x + 2 < -3 \), subtract 2 from both sides to get \( x < -5 \). Repeat this for each part of the compound inequality.
- Remember the special rule about multiplication or division by negative numbers in inequalities, though it doesn’t apply here: reverse the inequality sign.
- Pay attention to whether the inequality involves "or" or "and". "Or" means any solution that satisfies at least one part is acceptable, expanding the possible solutions.
Other exercises in this chapter
Problem 36
Solve each equation. \(3(2 x-1)=2(4 x+7)\)
View solution Problem 37
Solve each equation and inequality. \(\left|x-\frac{3}{4}\right|=\frac{2}{3}\)
View solution Problem 37
For Problems 37-46, solve each equation for the indicated variable. \(2 x-5 y=7\) for \(x\)
View solution Problem 37
Solve each equation. If a pair of shoes costs a retailer \(\$ 24\), and he sells them for \(\$ 39.60\), what is his rate of profit based on the cost?
View solution