Problem 37
Question
Sketch the graph of the line satisfying the given conditions. Passing through \((2,1)\) with slope \(\frac{3}{2}\)
Step-by-Step Solution
Verified Answer
The equation of the line is \( y = \frac{3}{2}x - 2 \).
1Step 1: Identify the slope-intercept form
The slope-intercept form of a line's equation is given by: \[ y = mx + c \] where \( m \) is the slope and \( c \) is the y-intercept.
2Step 2: Substitute the slope
Given the slope \( m = \frac{3}{2} \), substitute it into the slope-intercept form equation: \[ y = \frac{3}{2}x + c \]
3Step 3: Substitute the given point
The line passes through the point \( (2,1) \). Substitute \( x = 2 \) and \( y = 1 \) into the equation to find the value of \( c \): \[ 1 = \frac{3}{2}(2) + c \]
4Step 4: Solve for the y-intercept
Solve the equation from the previous step to find \( c \): \[ 1 = 3 + c \] \[ c = 1 - 3 \] \[ c = -2 \]
5Step 5: Write the final equation
Substitute \( c = -2 \) back into the slope-intercept form equation: \[ y = \frac{3}{2}x - 2 \]
6Step 6: Sketch the graph
To sketch the line, start by plotting the y-intercept \( (0, -2) \) and then use the slope to find another point. From \( (0, -2) \), move up 3 units and right 2 units to locate another point.
Key Concepts
slope-intercept formfinding y-interceptplotting points
slope-intercept form
The slope-intercept form of a linear equation is a very efficient way to describe a straight line. It's given by the formula: \[ y = mx + c \] Here, m is the slope of the line, which tells us how steep the line is. The c is the y-intercept, which represents the point where the line crosses the y-axis. Understanding this form is crucial because it simplifies plotting and sketching linear equations. You can quickly identify the steepness and where the line begins on the y-axis. It's the go-to method for representing lines in both mathematical problems and real-world applications.
finding y-intercept
To sketch a line, we often need to find the y-intercept, especially when given a specific point and slope. Let's revisit the problem: we are given the point \((2,1)\) and the slope \(m = \frac{3}{2} \) Start by plugging the slope into the slope-intercept form: \[ y = \frac{3}{2}x + c \] Substitute the given point \( (2,1) \) into the equation: \[ 1 = \frac{3}{2}(2) + c \] This equation allows us to solve for c: \[ 1 = 3 + c \] \[ c = 1 - 3 \] \[ c = -2 \] Now we have the full equation of the line, including the y-intercept: \[ y = \frac{3}{2}x - 2 \] The y-intercept c is \( -2 \) This step is critical as it completes the line equation, allowing us to easily sketch it.
plotting points
With our line equation \[ y = \frac{3}{2}x - 2 \] we can now sketch the line. Start by plotting the y-intercept: \( (0, -2) \). This is the point where the line crosses the y-axis. From there, use the slope, which is \( \frac{3}{2} \) to find more points. Slope is described as 'rise over run,' meaning for every 3 units you move up, you move 2 units to the right. Starting from \( (0, -2) \), move 3 units up and 2 units right, which lands us at \( (2,1) \) From these two points, you can draw a straight line, sketching out the entire graph. You can always plot more points if necessary, following the same slope guideline to ensure accuracy. This method effectively visualizes the linear equation, providing a clear representation of the line.
Other exercises in this chapter
Problem 36
In Exercises \(35-46,\) determine which, if any, of the ordered pairs listed satisfy the given equation. $$5 x-3 y=-2 ; \quad(2,4),(1,-1),(-1,1)$$
View solution Problem 37
Determine the slope of the line from its equation. $$y=5 x+7$$
View solution Problem 37
Sketch the graph of the given equation. Label the intercepts. $$x=-4$$
View solution Problem 37
In Exercises \(35-46,\) determine which, if any, of the ordered pairs listed satisfy the given equation. $$y=4 x-1 ; \quad(8,7),(7,8),(0,-1)$$
View solution