Problem 37
Question
Simplify each rational expression. If the rational expression cannot be simplified, so state. $$\frac{x+1}{x^{2}-2 x-3}$$
Step-by-Step Solution
Verified Answer
The simplified form of the given rational expression \(\frac{x + 1}{x^{2} - 2x - 3}\) is \(\frac{1}{x - 3}\)
1Step 1: Factorize the denominator
Our first task is to factorize the quadratic trinomial in the denominator, \(x^{2} - 2x - 3\). The quadratic trinomial can be written as \((x - a)(x - b)\) where \(a\) and \(b\) are the roots of the equation. For a quadratic expression in the form \(ax^{2} + bx + c\), the roots can be found using the formula \(\frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\). In this case, the roots can be found by factoring the equation to \((x - 3)(x + 1)\).
2Step 2: Cancel out common factors
Once the trinomial is fully factored, look for common factors that appear in both the numerator and the denominator. In this case, \(x + 1\) is a common factor that we can cancel out. The final simplified expression is thus \(\frac{1}{x - 3}\)
3Step 3: Check your work
To verify the solution, cross-multiply to get back to the original expression. If the original expression is regained, it confirms that the simplification is correct.
Other exercises in this chapter
Problem 37
What is a proportion? Give an example with your description.
View solution Problem 37
Factor: \(6 x^{3}-6 x^{2}-120 x\)
View solution Problem 37
Simplify complex rational expression by the method of your choice. \(\frac{\frac{3}{x y^{2}}+\frac{2}{x^{2} y}}{\frac{1}{x^{2} y}+\frac{2}{x y^{3}}}\)
View solution Problem 37
Solve each rational equation. $$\frac{1}{x}+\frac{1}{x-3}=\frac{x-2}{x-3}$$
View solution