Problem 37
Question
Show that $$x=a \cos t+h, \quad y=b \sin t+k ; \quad 0 \leq t \leq 2 \pi$$ are parametric equations of an ellipse with center \((h, k)\) and axes of lengths \(2 a\) and \(2 b\).
Step-by-Step Solution
Verified Answer
The parametric equations describe an ellipse centered at \((h, k)\) with axes lengths \(2a\) and \(2b\).
1Step 1: Understand the Parametric Equations
Given parametric equations are \(x = a \cos t + h\) and \(y = b \sin t + k\), with \(0 \leq t \leq 2\pi\). These equations describe a path where \(x\) and \(y\) vary with \(t\), potentially outlining a shape.
2Step 2: Eliminate Parameter t
To show the shape of the path, eliminate the parameter \(t\) by expressing \(\cos t\) and \(\sin t\) in terms of \(x\) and \(y\). Start by rearranging the equations: \(\cos t = \frac{x - h}{a}\) and \(\sin t = \frac{y - k}{b}\).
3Step 3: Apply the Pythagorean Identity
Use the identity \(\cos^2 t + \sin^2 t = 1\). Substitute the expressions for \(\cos t\) and \(\sin t\): \( \left(\frac{x - h}{a}\right)^2 + \left(\frac{y - k}{b}\right)^2 = 1 \).
4Step 4: Simplify to Ellipse Equation
Recognize that \( \left(\frac{x - h}{a}\right)^2 + \left(\frac{y - k}{b}\right)^2 = 1 \) is the equation of an ellipse centered at \((h, k)\) with semi-major axis \(a\) and semi-minor axis \(b\). The axes lengths are \(2a\) and \(2b\).
Key Concepts
Parametric EquationsAxes LengthsPythagorean Identity
Parametric Equations
In mathematics, parametric equations are used to express a set of related quantities as explicit functions of an independent parameter. For example, the equations \(x = a \cos t + h\) and \(y = b \sin t + k\) describe an ellipse.
These equations are crucial because they break down complex shapes into simple, manageable parts that change with the parameter \(t\). When \(t\) changes from \(0\) to \(2\pi\), the point \((x, y)\) moves around the ellipse's perimeter.
These equations are crucial because they break down complex shapes into simple, manageable parts that change with the parameter \(t\). When \(t\) changes from \(0\) to \(2\pi\), the point \((x, y)\) moves around the ellipse's perimeter.
- \(x = a \cos t + h\): Changes provide the horizontal position for a given \(t\)
- \(y = b \sin t + k\): Changes provide the vertical position
Axes Lengths
An ellipse has two key parameters known as the axes. The semi-major and semi-minor axes define the shape and extent of the ellipse.
In the parametric equations discussed earlier, \(a\) and \(b\) are directly tied to the lengths of these axes:
In the parametric equations discussed earlier, \(a\) and \(b\) are directly tied to the lengths of these axes:
- Semi-major axis \(a\): Determines the ellipse's largest radius, running along its longest side.
- Semi-minor axis \(b\): Represents the shortest radius, crossing the semi-major axis.
- The ellipse stretches up to \(2a\) units along the x-axis.
- It stretches up to \(2b\) units along the y-axis.
Pythagorean Identity
The Pythagorean identity is a well-known trigonometric rule stating that \(\cos^2 t + \sin^2 t = 1\). This identity is pivotal in connecting the parametric equations of an ellipse to its standard algebraic form.
When you utilize this identity with the rearranged versions of the given parametric equations, \(\cos t = \frac{x - h}{a}\) and \(\sin t = \frac{y - k}{b}\), you can derive the equation of an ellipse:
When you utilize this identity with the rearranged versions of the given parametric equations, \(\cos t = \frac{x - h}{a}\) and \(\sin t = \frac{y - k}{b}\), you can derive the equation of an ellipse:
- Substitute: \(\left(\frac{x - h}{a}\right)^2 + \left(\frac{y - k}{b}\right)^2 = 1\)
Other exercises in this chapter
Problem 36
Find an equation of the parabola that satisfies the given conditions. Vertex \(V(3,-2),\) axis parallel to the \(x\) -axis, and \(y\) -intercept 1
View solution Problem 37
Kepler's first law asserts that planets travel in elliptical orbits with the sun at one focus. To find an equation of an orbit, place the pole \(O\) at the cent
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Identify the graph of the equation as a parabola (with vertical or horizontal axis), circle, ellipse, or hyperbola. $$\frac{1}{3}(x+2)=y^{2}$$
View solution Problem 37
Find an equation in \(x\) and \(y\) that has the same graph as the polar equation. Use it to help sketch the graph in an \(r \theta\) -plane. $$r \cos \theta=5$
View solution