Problem 37
Question
Show that the function \(f(z)=-(2 x y+5 x)+i\left(x^{2}-5 y-y^{2}\right)\) is analytic for all \(z\). Find \(f^{\prime}(z)\).
Step-by-Step Solution
Verified Answer
The function is analytic for all \(z\) and \(f'(z) = (-2y - 5) + i(2x)\).
1Step 1: Identify Real and Imaginary Parts
The function given is \(f(z)=u(x,y) + iv(x,y)\) where \(u(x,y) = -(2xy + 5x)\) and \(v(x,y) = x^{2} - 5y - y^{2}\). These represent the real and imaginary parts of \(f\).
2Step 2: Verify the Cauchy-Riemann Equations
The function \(f(z)\) is analytic if the Cauchy-Riemann equations are satisfied. The equations are \(\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y}\) and \(\frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x}\). Calculate these partial derivatives: \(\frac{\partial u}{\partial x} = -2y - 5\), \(\frac{\partial u}{\partial y} = -2x\), \(\frac{\partial v}{\partial x} = 2x\), \(\frac{\partial v}{\partial y} = -5 - 2y\). Compare them to check if the equations hold.
3Step 3: Check the First Cauchy-Riemann Equation
Compare \(\frac{\partial u}{\partial x} = -2y - 5\) with \(\frac{\partial v}{\partial y} = -5 - 2y\). They are equal, so the first Cauchy-Riemann equation is satisfied.
4Step 4: Check the Second Cauchy-Riemann Equation
Compare \(\frac{\partial u}{\partial y} = -2x\) with \(-\frac{\partial v}{\partial x} = -2x\). They are equal, so the second Cauchy-Riemann equation is satisfied.
5Step 5: Conclude Analyticity
Since both Cauchy-Riemann equations are satisfied, \(f(z)\) is analytic for all \(z\).
6Step 6: Compute the Derivative
The derivative \(f'(z)\) is given by \(\frac{\partial u}{\partial x} + i\frac{\partial v}{\partial x}\). From Step 2, we calculated \(\frac{\partial u}{\partial x} = -2y - 5\) and \(\frac{\partial v}{\partial x} = 2x\). Therefore, \(f'(z) = (-2y - 5) + i(2x)\).
Key Concepts
Cauchy-Riemann EquationsAnalytic FunctionsPartial Derivatives
Cauchy-Riemann Equations
In complex analysis, the Cauchy-Riemann equations are vital to determine whether a complex function is analytic. A complex function \(f(z)\), where \(z = x + iy\), is expressed as \(u(x, y) + iv(x, y)\). These equations provide conditions that help confirm if the function is differentiable in a complex sense.
The Cauchy-Riemann equations state that for \(f(z)\) to be analytic, the following must hold:
\[\begin{align*}\frac{\partial u}{\partial x} &= -2y - 5, \\frac{\partial v}{\partial y} &= -5 - 2y \\end{align*}\]The equations are equal, thus confirming part of the function's analyticity. When \(\frac{\partial u}{\partial y} = -2x\) is compared with \(-\frac{\partial v}{\partial x} = -2x\), the continuity of satisfying the Cauchy-Riemann equations is upheld. This step is crucial; if the equations do not hold, the function is not analytic.
The Cauchy-Riemann equations state that for \(f(z)\) to be analytic, the following must hold:
- \(\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y}\)
- \(\frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x}\)
\[\begin{align*}\frac{\partial u}{\partial x} &= -2y - 5, \\frac{\partial v}{\partial y} &= -5 - 2y \\end{align*}\]The equations are equal, thus confirming part of the function's analyticity. When \(\frac{\partial u}{\partial y} = -2x\) is compared with \(-\frac{\partial v}{\partial x} = -2x\), the continuity of satisfying the Cauchy-Riemann equations is upheld. This step is crucial; if the equations do not hold, the function is not analytic.
Analytic Functions
An analytic function is a complex function that is differentiable at every point in its domain. Analyticity is a strong condition, as differentiation implies continuity. In the context of our example, once we have confirmed the Cauchy-Riemann equations, we affirm that \(f(z)\) is analytic for all complex numbers \(z\).
If a function is analytic, it can be infinitely differentiated, and it satisfies the conditions of complex differentiability. This means there is one unique derivative at each point in the domain of \(f(z)\). The achieved derivative can be found through the formula
If a function is analytic, it can be infinitely differentiated, and it satisfies the conditions of complex differentiability. This means there is one unique derivative at each point in the domain of \(f(z)\). The achieved derivative can be found through the formula
- \(f'(z) = \frac{\partial u}{\partial x} + i\frac{\partial v}{\partial x}\).
Partial Derivatives
Partial derivatives, denoted as \(\frac{\partial}{\partial x}\) and \(\frac{\partial}{\partial y}\), are derivatives taken with respect to one variable while holding other variables constant. They are essential in bridging real-valued functions and complex functions through the Cauchy-Riemann equations.
When dealing with a complex function's analytic nature,
partial derivatives describe how the function behaves along the real \((x)\) and imaginary \((y)\) axes:
When dealing with a complex function's analytic nature,
partial derivatives describe how the function behaves along the real \((x)\) and imaginary \((y)\) axes:
- \(\frac{\partial u}{\partial x}\) indicates the variation of the real part \(u\) in the \(x\) direction.
- \(\frac{\partial u}{\partial y}\) represents the change of \(u\) in the \(y\) direction.
- \(\frac{\partial v}{\partial x}\) and \(\frac{\partial v}{\partial y}\) similarly affect the imaginary part \(v\).
Other exercises in this chapter
Problem 37
Find all values of \(z\) satisfying the given equation. \(e^{z-1}=-i e^{2}\)
View solution Problem 37
Give the points at which the given function will not be analytic. $$ f(z)=\frac{z^{3}+z}{z^{2}+4} $$
View solution Problem 37
In Problems 35-38, find all values of \(z\) satisfying the given equation. $$ e^{z-1}=-i e^{2} $$
View solution Problem 37
In Problems 35-38, give the points at which the given function will not be analytic. $$ f(z)=\frac{z^{3}+z}{z^{2}+4} $$
View solution