Problem 37
Question
Polar coordinates of a point are given. Find the rectangular coordinates of each point. $$ \left(-4, \frac{\pi}{2}\right) $$
Step-by-Step Solution
Verified Answer
The rectangular coordinates of the polar point (-4, pi/2) are (0, -4).
1Step 1: Understanding the conversion formulas
The conversion from polar coordinates \((r,\theta)\) to rectangular coordinates \((x,y)\) involves the use of trigonometric functions. The formulas are defined as \(x=r\cos(\theta)\) and \(y=r\sin(\theta)\).
2Step 2: Application of the formulas
Replace r with -4 and \(\theta\) with \(\pi/2\) in the formulas \(x=r\cos(\theta)\) and \(y=r\sin(\theta)\). This gives us \(x=-4\cos(\pi/2)\) and \(y=-4\sin(\pi/2)\).
3Step 3: Simplification of the equations
The cosine of \(\pi/2\) is 0 and the sine of \(\pi/2\) is 1. Thus, \(x=-4*0\) and \(y=-4*1\), this simplifies to \(x=0\) and \(y=-4\). So, the rectangular coordinates of the given polar point are (0, -4).
Key Concepts
Rectangular CoordinatesTrigonometric FunctionsConversion Formulas
Rectangular Coordinates
Rectangular coordinates, often referred to as Cartesian coordinates, are a way to define a point in a plane using two numerical values. These values determine the position of the point along two perpendicular axes: the horizontal axis (x-axis) and the vertical axis (y-axis).
The combination of these two values defines the position of any point on the plane. For example, the point (2,3) is found by starting at the origin (0,0), moving two units in the direction of the x-axis, and then three units upwards along the y-axis.
Rectangular coordinates are useful because they provide a straightforward way to plot points and visualize shapes and patterns on a graph.
- The first value, known as the x-coordinate, tells us how far a point is from the y-axis.
- The second value, called the y-coordinate, indicates how far the point is from the x-axis.
The combination of these two values defines the position of any point on the plane. For example, the point (2,3) is found by starting at the origin (0,0), moving two units in the direction of the x-axis, and then three units upwards along the y-axis.
Rectangular coordinates are useful because they provide a straightforward way to plot points and visualize shapes and patterns on a graph.
Trigonometric Functions
Trigonometric functions are mathematical functions of an angle and are key to understanding relationships in triangles. The most commonly used trigonometric functions in coordinate conversions are sine and cosine.
For example, to convert polar coordinates like (\(r=3, \theta= \frac{\pi}{4}\)) to rectangular, you calculate:
- Cosine (\(\cos\)) helps find the horizontal component of an angle's reach. For an angle \(\theta\), the formula is \(\cos(\theta)\), yielding values between -1 and 1.
- Sine (\(\sin\)) provides the vertical component. Similarly, \(\sin(\theta)\) also ranges from -1 to 1, depending on the angle.
For example, to convert polar coordinates like (\(r=3, \theta= \frac{\pi}{4}\)) to rectangular, you calculate:
- \(x = r \cdot \cos(\theta) = 3 \cdot \cos(\frac{\pi}{4})\)
- \(y = r \cdot \sin(\theta) = 3 \cdot \sin(\frac{\pi}{4})\)
Conversion Formulas
Conversion formulas are essential in mathematics for switching between different types of coordinate systems, particularly between polar and rectangular coordinates. Here's how the conversion works:
Polar coordinates give point locations with a radius and an angle \((r, \theta)\). To find their rectangular coordinates \((x, y)\), we use the formulas:
When given a point like \((-4, \frac{\pi}{2})\), use:
Polar coordinates give point locations with a radius and an angle \((r, \theta)\). To find their rectangular coordinates \((x, y)\), we use the formulas:
- \(x = r \cdot \cos(\theta)\)
- \(y = r \cdot \sin(\theta)\)
When given a point like \((-4, \frac{\pi}{2})\), use:
- \(x = -4 \cdot \cos(\frac{\pi}{2}) = -4 \cdot 0 = 0\)
- \(y = -4 \cdot \sin(\frac{\pi}{2}) = -4 \cdot 1 = -4\)
Other exercises in this chapter
Problem 37
In Exercises \(21-38,\) let $$\mathbf{u}=2 \mathbf{i}-5 \mathbf{j}, \mathbf{v}=-3 \mathbf{i}+7 \mathbf{j}, \text { and } \mathbf{w}=-\mathbf{i}-6 \mathbf{j}$$ F
View solution Problem 37
In Exercises \(37-44,\) find the product of the complex numbers. Leave answers in polar form. $$ \begin{array}{l} {z_{1}=6\left(\cos 20^{\circ}+i \sin 20^{\circ
View solution Problem 37
In Exercises 33–38, find the area of the triangle having the given measurements. Round to the nearest square unit. $$ C=124^{\circ}, a=4 \text { meters, } b=6 \
View solution Problem 38
Test for symmetry and then graph each polar equation. $$r=4 \cos \theta+4 \sin \theta$$
View solution