Problem 37
Question
In Exercises \(31-38,\) use the given information about the geometric sequence \(\left\\{a_{n}\right\\}\) to find as and a formula for \(a_{n}\). $$\left.a_{1}=5, a_{7}=20 \quad \text { (assume that } r>0\right)$$
Step-by-Step Solution
Verified Answer
Answer: The formula for the n-th term of the given geometric sequence is a_n = 5 * (\sqrt[6]{4})^(n-1).
1Step 1: Identify the geometric sequence and given terms
We are given the first term of the geometric sequence, a₁ = 5, and the seventh term a₇ = 20. We know that the common ratio (r) is greater than 0. Recall that the formula for the n-th term of a geometric sequence is:
a_n = a₁ * r^(n-1)
2Step 2: Find the common ratio r using the given terms
Using the formula for the n-th term of a geometric sequence, we can write the equation for the seventh term:
a₇ = a₁ * r^(7-1)
We know that a₇ = 20 and a₁ = 5, so we can plug in these values:
20 = 5 * r^6
Now, we will solve for r:
r^6 = 20/5
r^6 = 4
Taking the 6th root of both sides, we get:
r = \sqrt[6]{4}
Since r > 0, we only consider the positive root.
3Step 3: Find the formula for a_n
Now that we have found the common ratio r = \sqrt[6]{4}, we can write the formula for the n-th term of the geometric sequence:
a_n = a₁ * r^(n-1)
Substitute the values for a₁ and r:
a_n = 5 * (\sqrt[6]{4})^(n-1)
This is the formula for the n-th term of the given geometric sequence.
Key Concepts
Common Ration-th Term FormulaSequences and Series
Common Ratio
In a geometric sequence, the common ratio is a crucial component that determines how each term relates to the one before it. The common ratio, often represented by \( r \), is found by dividing any term of the sequence by its preceding term. In our exercise, we were given the first term, \( a_1 = 5 \), and the seventh term, \( a_7 = 20 \). To find \( r \), we used the formula for the \( n \)-th term:
- \( a_n = a_1 \cdot r^{(n-1)} \)
n-th Term Formula
The \( n \)-th term formula in a geometric sequence allows us to find any term in the sequence without having to write out all the previous terms. This formula is particularly useful for sequences with many terms. The general formula is:
- \( a_n = a_1 \cdot r^{(n-1)} \)
- \( a_n = 5 \cdot (\sqrt[6]{4})^{(n-1)} \)
Sequences and Series
Sequences and series are mathematical concepts used to understand patterns and sums in numbers. A sequence, in particular, is an ordered list of numbers, following a specific rule. In the case of geometric sequences, each term is derived by multiplying the previous term by a fixed number known as the common ratio.
Geometric sequences are defined by their exponential nature, which makes them powerful models for various real-world phenomena, like population growth and investment compounding.
A series, on the other hand, involves summing the terms of a sequence. While our current focus is on sequences, understanding both concepts is vital for higher-level math, as they provide foundational knowledge for calculus and higher algebra.
Geometric sequences are defined by their exponential nature, which makes them powerful models for various real-world phenomena, like population growth and investment compounding.
A series, on the other hand, involves summing the terms of a sequence. While our current focus is on sequences, understanding both concepts is vital for higher-level math, as they provide foundational knowledge for calculus and higher algebra.
- Geometric Sequence Example: \( 5, 5\sqrt[6]{4}, 5(\sqrt[6]{4})^2, \ldots \)
- Series Example: \( 5 + 5\sqrt[6]{4} + 5(\sqrt[6]{4})^2 + \ldots \)
Other exercises in this chapter
Problem 36
Express the sum in \(\Sigma\) notation. $$1^{1}+2^{2}+3^{3}+4^{4}+5^{5}$$
View solution Problem 36
Use the given information about the arithmetic sequence with common difference d to find a and a formula for \(a_{n}\). $$a_{4}=-5, d=-5$$
View solution Problem 37
Use induction to prove DeMoivre's Theorem: For any complex number \(z=r(\cos \theta+i \sin \theta)\) and any positive integer \(n\) $$ z^{n}=r^{n}[\cos (n \thet
View solution Problem 37
Expand and (where possible) simplify the expression. $$(1+i)^{6}, \text { where } i^{2}=-1$$
View solution