Problem 37
Question
In Exercises 29-40, plot the points and find the slope of the line passing through the pair of points. \( (\frac{11}{2}, -\frac{4}{3}) \), \( (-\frac{3}{2}, -\frac{1}{3}) \)
Step-by-Step Solution
Verified Answer
The slope of the line passing through the points \( (\frac{11}{2}, -\frac{4}{3}) \) and \( (-\frac{3}{2}, -\frac{1}{3}) \) is -\frac{1}{7}.
1Step 1: Identify coordinates
The given points are \( (\frac{11}{2}, -\frac{4}{3}) \) and \( (-\frac{3}{2}, -\frac{1}{3}) \). So, \( x_1 = \frac{11}{2}, y_1 = -\frac{4}{3}, x_2 = -\frac{3}{2}, y_2 = -\frac{1}{3} \).
2Step 2: Calculate the slope
Substitute these coordinates into the slope formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \). So, the slope \( m = \frac{-\frac{1}{3} - (-\frac{4}{3})}{-\frac{3}{2} - \frac{11}{2}} = \frac{1}{-7} = -\frac{1}{7} \).
3Step 3: Plot the points
Plot the coordinates \( (\frac{11}{2}, -\frac{4}{3}) \) and \( (-\frac{3}{2}, -\frac{1}{3}) \) on a graph where x-axis represents x-coordinates and y-axis represents y-coordinates.
Key Concepts
Plotting PointsCoordinate GeometryLinear Equations
Plotting Points
Plotting points on a graph is a fundamental skill in mathematics. To get started, you need a coordinate plane, which consists of a horizontal line called the x-axis and a vertical line called the y-axis. These axes intersect at the origin point, which is (0,0). Points are plotted by identifying their coordinates, which are typically written in the form of (x, y). The x-coordinate tells us how far to move horizontally from the origin, while the y-coordinate tells us how far to move vertically.
Here’s a step-by-step guide to plotting the points in the given exercise:
Here’s a step-by-step guide to plotting the points in the given exercise:
- Identify the first point: \( (\frac{11}{2}, -\frac{4}{3}) \).
- The x-coordinate \( \frac{11}{2} \) means you move 5.5 units to the right of the origin.
- The y-coordinate \( -\frac{4}{3} \) means you move approximately 1.33 units down from there.
- Plot the point on the graph.
- Identify the second point: \( (-\frac{3}{2}, -\frac{1}{3}) \).
- The x-coordinate \( -\frac{3}{2} \) means you move 1.5 units to the left of the origin.
- The y-coordinate \( -\frac{1}{3} \) means you move approximately 0.33 units down from there.
- Plot the second point on the graph.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, merges algebra and geometry. It provides a method to solve geometric problems through algebraic equations by using coordinate systems. Each point in coordinate geometry is represented by a pair of numbers, and these can be used to calculate distances, midpoints, and slopes.
A connection of points can form lines, curves, and other shapes, allowing complex geometric inferences to be made through simple algebraic processes. It’s crucial to understand that:
A connection of points can form lines, curves, and other shapes, allowing complex geometric inferences to be made through simple algebraic processes. It’s crucial to understand that:
- A point is represented by its coordinates \((x, y)\) on the Cartesian plane.
- A line can be described by equations, such as linear equations.
- Properties like distance and section formula can be derived using coordinates.
Linear Equations
Linear equations represent the simplest type of equation, where the highest power of the variable(s) is 1. They describe straight lines in coordinate geometry and are generally written in the form \( y = mx + c \), where:
- \( m \) is the slope of the line indicating its steepness and direction.
- \( c \) is the y-intercept, where the line crosses the y-axis.
- If \( m > 0 \), the line rises from left to right.
- If \( m < 0 \), it falls from left to right.
- If \( m = 0 \), the line is horizontal.
Other exercises in this chapter
Problem 37
In Exercises 33-38, (a) use a graphing utility to graph the function and find the zeros of the function and (b) verify your results from part (a) algebraically.
View solution Problem 37
In Exercises 37-52, evaluate the function at each specified value of the independent variable and simplify. \(f(x) = 2x - 3\) (a) \(f(1)\) (b) \(f(-3)\) (c) \(f
View solution Problem 37
In Exercises 33-40, use the algebraic tests to check for symmetry with respect to both axes and the origin. \( y = \frac{x}{x^2+1} \)
View solution Problem 37
In Exercises 27-38, find the distance between the points. \( (-4.2, 3.1) \), \( (-12.5, 4.8) \)
View solution