Problem 37
Question
In Exercises \(29-34\) , construct a slope field for the differential equation. In each case, copy the graph at the right and draw tiny segments through the twelve lattice points shown in the graph. Use slope analysis, not your graphing calculator. $$\frac{d y}{d x}=x-y$$
Step-by-Step Solution
Verified Answer
The slope field helps in visualizing the solution of our differential equation at the lattice points. We calculate slope at each point and plot small line segments according to these slopes. This gives us an idea about the behavior of the solution function of the differential equation.
1Step 1: Understand Slope Fields
A slope field is a grid of segments that represent the slope of a function at specific points, which in this case are the lattice points. The differential equation \(\frac{dy}{dx} = x - y\) describes the rate of change of a quantity \(y\) that is dependent upon \(x\) and \(y\) itself.
2Step 2: Determine the Slopes at Lattice Points
Each lattice point on the graph is (x, y) coordinate. We plug these coordinates into our differential equation to get the slope at that point. For example, at the lattice point (1, 2), the slope is 1 - 2 = -1.
3Step 3: Plot the Slope Field
Once the slopes at all lattice points are found, it's time to draw tiny segments through these points according to the slopes calculated. For points with positive slope, the segment will tend upward to the right, while for negative slopes, the segment will tend downward to the right. For a slope of zero, the segment will be a horizontal line.
4Step 4: Analyze the Slope Field
After drawing the slope field, we need to analyze it in order to understand the behavior of the function defined by the differential equation. The slope field should give us a rough idea of what the solution curves of the differential equation look like.
Key Concepts
Understanding Differential EquationsConducting Slope AnalysisConstructing Slope Fields
Understanding Differential Equations
A differential equation is a mathematical equation that relates some function with its derivatives. In basic terms, it represents the relationship between a varying quantity and its rates of change. The equation \(\frac{dy}{dx} = x - y\) from our exercise is an example of a first-order differential equation because it includes only the first derivative of the function y.Differential equations are crucial in modeling real-world phenomena in physics, engineering, biology, economics, and more. Solving a differential equation typically means finding a function that satisfies the given relationship. Understanding the nature and solution of differential equations is foundational in many fields of science and engineering.
Conducting Slope Analysis
Slope analysis involves determining the direction and steepness of the slope at various points on a graph, which can help predict the behavior of the solution curves to the differential equation. In our exercise, to conduct a slope analysis, we calculate the slope at different 'lattice points' — points that lie on a grid. For instance, if we take the point (1, 2), plugging these values into the equation \(\frac{dy}{dx} = x - y\) gives us the result -1, which means at that point, the slope of the curve will be negative, and therefore, it will be declining as we move to the right.Slope analysis is essential for understanding how the solution to the differential equation will change as the variables \(x\) and \(y\) change. It's a critical step before we graph the slope field, as it gives us the directionality of tiny line segments across our coordinate plane.
Constructing Slope Fields
Slope fields, also known as direction fields, are visual representations of solutions to a differential equation at a variety of points. They consist of small line segments or vectors that represent the slope of the solution curves at grid points, making it easier to visualize the behavior of solutions even without solving the equation analytically. To construct a slope field for our differential equation \(\frac{dy}{dx} = x - y\), we calculate the slope at multiple lattice points across a grid and sketch the corresponding small line segments at those points.This graphical tool is particularly useful because it doesn't require an exact solution to the differential equation. Instead, it provides a qualitative understanding of the possible functions that could solve the differential equation. As you draw the segments in the slopes field, you’ll notice patterns that indicate the trajectories of the solution curves, showing where they increase, decrease, or remain constant.
Other exercises in this chapter
Problem 37
True or False If \(f^{\prime}(x)=g(x),\) then \(\int x^{2} g(x) d x=\) \(x^{2} f(x)-2 \int x f(x) d x .\) Justify your answer.
View solution Problem 37
In Exercises \(25-46,\) use substitution to evaluate the integral. $$\int \frac{\sin (2 t+1)}{\cos ^{2}(2 t+1)} d t$$
View solution Problem 38
Multiple Choice If \(\int x^{2} \cos x d x=h(x)-\int 2 x \sin x d x,\) then \(h(x)=\) (A) \(2 \sin x+2 x \cos x+C\) (B) \(x^{2} \sin x+C\) (C) \(2 x \cos x-x^{2
View solution Problem 38
In Exercises \(25-46,\) use substitution to evaluate the integral. $$\int \frac{6 \cos t}{(2+\sin t)^{2}} d t$$
View solution