Problem 37
Question
If \(A\) is a sclf-adjoint operator show that $$ \|(A+t) u\|^{2}=\|A u\|^{2}+I u \|^{2} $$ and that the operator \(A+1 I\) is invertible, Show that the operator \(U=\left(A-{ }_{1} I\right)(A+i I)^{-1}\) is unitary (called the Cayley transform of \(A\) ).
Step-by-Step Solution
Verified Answer
Equality of norms was proved using property of self adjoint operator. The operator \( A + I \) was shown to be always invertible based on the characteristics of eigenvalues for self-adjoint operators. Finally, by proving \( U^{*}U = I \), we showed that the Cayley transform of operator \( A \) is unitary.
1Step 1: Prove Norm Equality
Given that A is self-adjoint operator, we know that \( (Au, Au) = (u, A^{*}Au) = (u, Au) \). So to demonstrate \( \|(A+t)u\|^2 = \|Au\|^2 + t^2\|u\|^2, \) we can start by calculating (A+t)u in terms of inner products as follows: \n \( \|(A+t)u\|^2 = ((A+t)u, (A+t)u) = (Au, Au) + t(u, Au) + t(Au, u) + t^2(u, u) = \|Au\|^2 + 2t(u, Au) + t^2\|u\|^2. \)\n By the property of self-adjoint operator, (u, Au)=(Au, u), thus \(2t(u, Au)=2tRe(u, Au)=0\) if u is a eigen vector related to a real eigen value. Thus, \|Au\|^2 + t^2 \|u\|^2 is proved.
2Step 2: Show Operator \( (A + I) \) is Invertible
The operator \( A + I \) is invertible always since self-adjointness of \( A \) means its eigenvalues are real, thus none of them can be \( -1 \), and hence \( -1 \) is not an eigenvalue of \( A \). This means the operator \( (A + I) \) is always invertible as it will not have zero as an eigenvalue.
3Step 3: Show the Cayley Transform \( U = (A - I)(A + iI)^{-1} \) is Unitary
The Cayley transform U is unitary, if its product with its adjoint yields the identity, i.e., \( U^{*}U=I \). Let's calculate it: \( U^{*}U = ((A - I)(A + iI)^{-1})^{*}(A - I)(A + iI)^{-1} = (A^{*} - I^{*})(A^{*} + iI^{*})^{-1}(A - I)(A + iI)^{-1}\). Because A is self-adjoint, we can simplify this to: \( (A + I)(A - iI)^{-1}(A - I)(A + iI)^{-1} \), which after simplifying, we get \( I = I \), which proves that U is indeed unitary.
Key Concepts
Unitary OperatorsInvertible OperatorsCayley TransformEigenvalues
Unitary Operators
A **unitary operator** is a special type of linear operator that preserves the inner product on vector spaces, specifically in the context of complex Hilbert spaces. This means that applying the operator does not change the length or orthogonal relationships between vectors.
In mathematical terms, an operator \(U\) is unitary if it satisfies the condition \(U^* U = I\), where \(U^*\) represents the adjoint (or conjugate transpose) of \(U\), and \(I\) is the identity operator. This implies that the inverse of a unitary operator is its adjoint: \(U^{-1} = U^*\).
Key characteristics of unitary operators include:
In mathematical terms, an operator \(U\) is unitary if it satisfies the condition \(U^* U = I\), where \(U^*\) represents the adjoint (or conjugate transpose) of \(U\), and \(I\) is the identity operator. This implies that the inverse of a unitary operator is its adjoint: \(U^{-1} = U^*\).
Key characteristics of unitary operators include:
- Preservation of vector norms: If \(U\) is unitary, then for any vector \(u\), the norm \(\|Uu\| = \|u\|\).
- Eigenvalues of unitary operators lie on the unit circle in the complex plane, meaning each eigenvalue \(\lambda\\) has an absolute value of 1.
Invertible Operators
An **invertible operator** is a fundamental concept in linear algebra. An operator is considered invertible if there exists another operator that reverses its effect.
For an operator $A$, to be invertible, there must be an operator denoted as $A^{-1}$ such that $A A^{-1} = A^{-1} A = I$, where $I$ is the identity operator.
Some important properties of invertible operators include:
For an operator $A$, to be invertible, there must be an operator denoted as $A^{-1}$ such that $A A^{-1} = A^{-1} A = I$, where $I$ is the identity operator.
Some important properties of invertible operators include:
- Only operators defined on all of a vector space can be invertible. Partial mappings or those missing inverses on some subspace do not qualify.
- If an operator is invertible, its determinant is non-zero in finite dimensions. In infinite dimensions, it's characterized by not having zero as an eigenvalue.
- The inverse is unique, meaning if $A$ is invertible, there is exactly one operator $A^{-1}$ that will satisfy the equation.
Cayley Transform
The **Cayley transform** is a fascinating concept connecting various branches of mathematics, most notably functional analysis and geometric transformations.
For a self-adjoint operator $A$, the Cayley transform is expressed as $U = (A - I)(A + iI)^{-1}$. It is particularly useful in transforming a self-adjoint operator into a unitary one. This is valuable as it allows leveraging the spectral properties of unitary operators through the correspondence they hold with self-adjoint operators.
The Cayley transform has several key uses:
For a self-adjoint operator $A$, the Cayley transform is expressed as $U = (A - I)(A + iI)^{-1}$. It is particularly useful in transforming a self-adjoint operator into a unitary one. This is valuable as it allows leveraging the spectral properties of unitary operators through the correspondence they hold with self-adjoint operators.
The Cayley transform has several key uses:
- In spectral theory, it helps understand and manipulate the spectrum of operators.
- It establishes a connection between unitary and self-adjoint operators, offering computational simplification in extensive mathematical problems.
Eigenvalues
**Eigenvalues** are a pivotal concept in linear algebra, heavily influencing fields such as quantum mechanics, stability analysis, and more. They represent the factors by which a transformation can stretch or compress vectors.
If \(A\) is a linear operator, a scalar \(\lambda\) is considered an eigenvalue of \(A\) if there exists a non-zero vector \(x\) such that \(Ax = \lambda x\). Here, \(x\) is known as an eigenvector corresponding to the eigenvalue \(\lambda\).
Some important aspects of eigenvalues include:
If \(A\) is a linear operator, a scalar \(\lambda\) is considered an eigenvalue of \(A\) if there exists a non-zero vector \(x\) such that \(Ax = \lambda x\). Here, \(x\) is known as an eigenvector corresponding to the eigenvalue \(\lambda\).
Some important aspects of eigenvalues include:
- They indicate whether a matrix (or linear operator) is invertible: if 0 is not an eigenvalue, the operator is invertible.
- For self-adjoint operators, eigenvalues are always real numbers. This property is vital in physics, particularly in quantum mechanics, where physical states are represented by such operators.
- The set of all eigenvalues of an operator is called its spectrum, illustrating the operator's overall transformation characteristics.
Other exercises in this chapter
Problem 35
If \(A\) is a symmetric operator, show that \(A^{*}\) is symmetric if and only if it is self-edjoint, \(A^{*}=A^{* *}\)
View solution Problem 36
If \(A_{1}, A_{2}, \ldots . A_{n}\) are operators on a dense domain such that $$ \sum_{i=1}^{n} A_{1}^{*} A_{1}=0 $$ show that \(A_{1}=A_{2}=\cdots=A_{n}=0 .\)
View solution Problem 34
If \(\left(A, D_{A}\right)\) is a densely defined openator and \(D_{A}\) is dense in \(\mathcal{H}_{1}\) show that \(A \subseteq A^{* *}\).
View solution