Problem 37
Question
For the following problems, find the products. $$ \left(x+\frac{2}{5}\right)^{2} $$
Step-by-Step Solution
Verified Answer
Question: Expand the given binomial expression: $\left(x+\frac{2}{5}\right)^{2}$
Answer: The expanded form of the given binomial expression is: $x^{2} + \frac{4}{5}x + \frac{4}{25}$.
1Step 1: Recall the binomial formula
Remember that the square of a binomial (a+b)^2 can be expanded using the formula:
$$(a+b)^{2} = a^{2} + 2ab + b^{2}$$
In our case, \(a=x\) and \(b=\frac{2}{5}\).
2Step 2: Apply the binomial formula
Using the formula, expand the given expression:
$$\left(x+\frac{2}{5}\right)^{2} = x^{2} + 2x\left(\frac{2}{5}\right) + \left(\frac{2}{5}\right)^{2}$$
3Step 3: Simplify the equation
Now, simplify the equation by performing the multiplication and squaring the terms:
$$x^{2} + 2x\left(\frac{2}{5}\right) + \left(\frac{2}{5}\right)^{2} = x^{2} + \frac{4}{5}x + \frac{4}{25}$$
4Step 4: Write the final result
The expanded and simplified expression for the given problem is:
$$\left(x+\frac{2}{5}\right)^{2} = x^{2} + \frac{4}{5}x + \frac{4}{25}$$
Key Concepts
PolynomialsAlgebraic ExpressionsQuadratic Equations
Polynomials
Polynomials are mathematical expressions that consist of variables and coefficients. They are composed of terms, each being a product of a constant and a variable raised to an integer power. In the expression \(x^2 + \frac{4}{5}x + \frac{4}{25}\), we can identify it as a polynomial with three terms. Each of these terms has its own characteristics:
- \(x^2\) is the quadratic term, with its highest degree being 2.- \(\frac{4}{5}x\) is the linear term, indicating it is of the first degree.- \(\frac{4}{25}\) is the constant term, as it doesn't have a variable associated with it.
Polynomials like this one are essential in various algebraic processes, and they form a foundational aspect of algebra that is used in solving equations and modeling real-world scenarios.
- \(x^2\) is the quadratic term, with its highest degree being 2.- \(\frac{4}{5}x\) is the linear term, indicating it is of the first degree.- \(\frac{4}{25}\) is the constant term, as it doesn't have a variable associated with it.
Polynomials like this one are essential in various algebraic processes, and they form a foundational aspect of algebra that is used in solving equations and modeling real-world scenarios.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operations like addition, subtraction, multiplication, and division. They represent values and can be simplified or manipulated according to the rules of algebra. The binomial expression \(\left(x+\frac{2}{5}\right)^2\) is a perfect example of an algebraic expression.
When working with algebraic expressions:
When working with algebraic expressions:
- Understand the order of operations to simplify or expand expressions properly.
- Apply algebraic identities, such as \((a+b)^2 = a^2 + 2ab + b^2\), to expand expressions into a polynomial form.
- Simplify as far as possible to make the expression easier to work with.
Quadratic Equations
Quadratic equations are equations of the second degree, meaning the highest power of the variable is 2. These equations can be expressed in the standard form \(ax^2 + bx + c = 0\).
The quadratic we discussed, \(x^2 + \frac{4}{5}x + \frac{4}{25}\), while currently an expression, can be transformed into a quadratic equation by setting it equal to zero: \(x^2 + \frac{4}{5}x + \frac{4}{25} = 0\). This setup allows us to solve for the variable \(x\) using methods such as factorization, completing the square, or using the quadratic formula:
The quadratic we discussed, \(x^2 + \frac{4}{5}x + \frac{4}{25}\), while currently an expression, can be transformed into a quadratic equation by setting it equal to zero: \(x^2 + \frac{4}{5}x + \frac{4}{25} = 0\). This setup allows us to solve for the variable \(x\) using methods such as factorization, completing the square, or using the quadratic formula:
- Factoring involves expressing the quadratic as a product of its linear factors.
- Completing the square rearranges the equation to reveal a perfect square trinomial.
- The quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) directly solves for \(x\), where \(a\), \(b\), and \(c\) are coefficients from the standard form.
Other exercises in this chapter
Problem 36
For the expressions in the following problems, write the number of terms that appear and then list the terms. $$ a+1+(a-1) $$
View solution Problem 36
For the following problems, classify each of the polynomials as a monomial, binomial, or trinomial. State the degree of each polynomial and write the numerical
View solution Problem 37
Classify each of the equations for the following problems by degree. If the term linear, quadratic, or cubic applies, state it. $$ y=5 s+6 $$
View solution Problem 37
For the following problems, simplify each of the algebraic expressions. $$ 21 y-15 x+40 x y-6-11 y+7-12 x-x y $$
View solution