Problem 37
Question
For the following exercises, write an explicit formula for each geometric sequence. $$ a_{n}=\\{0.8,-4,20,-100, \ldots\\} $$
Step-by-Step Solution
Verified Answer
The explicit formula is \( a_n = 0.8 \, (-5)^{n-1} \).
1Step 1: Identify the first term
The first term of the given sequence is the first element. Here, the first term, \( a_1 \), is \( 0.8 \).
2Step 2: Determine the common ratio
To find the common ratio \( r \), divide the second term by the first term: \(\frac{-4}{0.8} = -5\). So, the common ratio \( r = -5 \).
3Step 3: Write the explicit formula for the geometric sequence
The explicit formula for any geometric sequence can be written as \( a_n = a_1 \, r^{n-1} \). Substituting the known values, we get:\( a_n = 0.8 \, (-5)^{n-1} \).
Key Concepts
Understanding the Explicit FormulaDiscovering the Common RatioExploring Sequence Terms
Understanding the Explicit Formula
An explicit formula for a geometric sequence allows you to find any term in the sequence without knowing the previous one. It's like having a magic formula! For the given sequence, the explicit formula is calculated using the first term and the common ratio. The general form of an explicit formula for a geometric sequence is given by:
\[a_n = a_1 \, r^{n-1}\]
\[a_n = 0.8 \, (-5)^{n-1}\]With this formula, you can easily find any term in this geometric sequence by just plugging in the value of \(n\). This formula saves time and makes calculations straightforward!
\[a_n = a_1 \, r^{n-1}\]
- \(a_n\) represents the term you want to find.
- \(a_1\) is the first term of the sequence.
- \(r\) is the common ratio.
- \(n\) is the term number you're calculating.
\[a_n = 0.8 \, (-5)^{n-1}\]With this formula, you can easily find any term in this geometric sequence by just plugging in the value of \(n\). This formula saves time and makes calculations straightforward!
Discovering the Common Ratio
The common ratio is a fundamental component of a geometric sequence. It tells us the factor by which we multiply a term to get the next one. In simple terms, it's what makes a geometric sequence special. To find the common ratio \(r\), you simply divide any term in the sequence by its preceding term.
In the provided sequence \(\{0.8, -4, 20, -100, \ldots\}\), \(r\) was calculated by dividing the second term by the first:
\[r = \frac{-4}{0.8} = -5\]
In the provided sequence \(\{0.8, -4, 20, -100, \ldots\}\), \(r\) was calculated by dividing the second term by the first:
\[r = \frac{-4}{0.8} = -5\]
- This means that every term is -5 times the term before it.
- Notice that the sign plays a crucial role; it indicates that the sequence alternates signs with each term.
Exploring Sequence Terms
Sequence terms are the individual numbers that make up a sequence. In a geometric sequence, each term is derived from the previous one by multiplying with the common ratio. This gives the sequence its unique pattern.
Let's explore the terms in a geometric sequence:
Let's explore the terms in a geometric sequence:
- The first term \(a_1\) sets the base for the entire sequence; here it is 0.8.
- The second term \(a_2\) is calculated as \(a_1 \times r\), giving us -4.
- Similarly, the third term \(a_3\) can be found by multiplying \(a_2\) with \(r\) again, which equals 20.
- This pattern continues, resulting in a sequence that expands as \{0.8, -4, 20, -100,\ldots\}.
Other exercises in this chapter
Problem 37
Can \(C(n, r)\) ever equal \(P(n, r) ?\) Explain.
View solution Problem 37
For the following exercises, find the indicated term of each binomial without fully expanding the binomial. The ninth term of \(\left(a-3 b^{2}\right)^{11}\)
View solution Problem 37
For the following exercises, write a recursive formula for each arithmetic sequence. $$ a=\left\\{\frac{1}{6},-\frac{11}{12},-2, \ldots\right\\} $$
View solution Problem 37
Write a recursive formula for each sequence. $$35,38,41,44,47, \dots$$
View solution