Problem 37
Question
For the following exercises, use this scenario: A tumor is injected with 0.5 grams of Iodine-125, which has a decay rate of \(1.15 \%\) per day. A research student is working with a culture of bacteria that doubles in size every twenty minutes. The initial population count was 1350 bacteria. Rounding to five signifi ant digits, write an exponential equation representing this situation. To the nearest whole number, what is the population size after 3 hours?
Step-by-Step Solution
Verified Answer
Approximately 332783 bacteria after 3 hours.
1Step 1: Understand the Growth Model
We are dealing with exponential growth. The population of bacteria doubles every twenty minutes, which means the growth factor over each time period is 2. Since growth is continuous, we can write an equation for the population count at any time.
2Step 2: Determine the Growth Rate per Minute
Since the population doubles every 20 minutes, we need to find the equivalent growth rate for one minute. The growth factor for 20 minutes is 2, so for 1 minute, it is \( \sqrt[20]{2} \). This approximates to \(1.03526\).
3Step 3: Setup the Exponential Growth Equation
Using the initial population of 1350 bacteria and the growth factor per minute, the equation becomes: \( P(t) = 1350 \times 1.03526^t \), where \( t \) is the time in minutes.
4Step 4: Convert 3 Hours into Minutes
Convert 3 hours into minutes, since our growth model is minute-based. 3 hours equals 180 minutes.
5Step 5: Calculate Population After 3 Hours
To find the population after 3 hours, substitute \( t = 180 \) minutes into the growth equation: \( P(180) = 1350 \times 1.03526^{180} \).
6Step 6: Compute the Solution
Calculate \( 1.03526^{180} \), which approximately equals \(246.5061\). Then, multiply by the initial population: \( P(180) = 1350 \times 246.5061 \approx 332783 \).
7Step 7: Round to the Nearest Whole Number
Round the population size to the nearest whole number. Thus, the population size after 3 hours is approximately 332783 bacteria.
Key Concepts
Bacteria PopulationGrowth RateExponential EquationPopulation Doubling Time
Bacteria Population
When studying bacteria, understanding their population dynamics is crucial. Bacteria often reproduce at a rapid pace, allowing their population sizes to increase significantly over short periods. For example, in our scenario, the bacteria culture started with an initial population of 1350. This number serves as the baseline from which we observe changes.
- This initial count is fundamental as it sets the ground for predicting future population sizes.
- In biological studies, these counts are typically estimated using various culturing and counting techniques.
Growth Rate
The growth rate is an essential variable in population studies, especially when dealing with bacteria. It allows us to understand how quickly a population is expanding.
- A growth rate expresses how many times the population increases in a specific unit of time.
- In exponential growth, the growth rate is often given as a multiplier, meaning the factor by which the population increases per unit time.
Exponential Equation
Constructing an exponential equation is a method to mathematically express the growth of populations such as the one for bacteria. It provides a framework for predicting future population sizes based on current data.
- An exponential equation takes the form: \( P(t) = P_0 \times (growth\ factor)^t \), where \( P_0 \) is the initial population, and \( t \) is time.
- In our case, the equation becomes \( P(t) = 1350 \times 1.03526^t \).
Population Doubling Time
Population doubling time refers to how long it takes for a population to double in size. This concept is integral to understanding exponential growth’s speed and intensity.
- Doubling time offers a quick insight into the pace of population explosion.
- For the bacteria culture, the doubling time is 20 minutes, which means every 20 minutes, the quantity of bacteria doubles.
Other exercises in this chapter
Problem 37
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For the following exercises. use the one-to-one pronerty of logarithms to solve. $$ \log _{13}(5 n-2)=\log _{13}(8-5 n) $$
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For the following exercises, start with the graph of \(f(x)=4^{x}\). Then write a function that results from the given transformation. Refl \(\operatorname{ct}
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For the following exercises, refer to Table 9. $$\begin{array}{ccccccc}{x} & {1} & {2} & {3} & {4} & {5} & {6} \\ {f(x)} & {5.1} & {6.3} & {7.3} & {7.7} & {8.1}
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