Problem 37
Question
Find the sum of the convergent series. $$ \sum_{n=0}^{\infty}\left(-\frac{1}{2}\right)^{n} $$
Step-by-Step Solution
Verified Answer
The sum of the provided convergent series is \(\frac{2}{3}\).
1Step 1: Identify the First Term and Common Ratio
In the given series \(\sum_{n=0}^{\infty}\left(-\frac{1}{2}\right)^{n}\), the first term \(a\) is when \(n = 0\) which gives \(a = (-\frac{1}{2})^{0} = 1\). The common ratio \(r\) is \(-\frac{1}{2}\).
2Step 2: Check if the Series is Convergent
For a series to be convergent, the absolute value of the common ratio must be less than 1. In this case: \(|-1/2| = 1/2 < 1\). Hence, the series is convergent.
3Step 3: Calculate the Sum of the Convergent Series
Using the formula for the sum of an infinite geometric series \(S = \frac{a}{1-r}\), substitute the found values for \(a\) and \(r\). The sum \(S\) of the series then is \(S = \frac{1}{1--1/2} = \frac{1}{1+1/2} = \frac{1}{1.5} = \frac{2}{3}\).
Key Concepts
Geometric SeriesInfinite SeriesCommon Ratio
Geometric Series
A Geometric Series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. In our case, the series is represented by \(\sum_{n=0}^{\infty}\left(-\frac{1}{2}\right)^{n}\). This means:
- The first term is 1 when \(n = 0\).
- Each subsequent term is obtained by multiplying the previous term by \(-\frac{1}{2}\).
Infinite Series
An Infinite Series is a sum of infinitely many terms. It starts adding terms from a sequence and continues indefinitely. These series can be daunting, but under certain conditions, they have finite sums. This depends on how the terms behave as they continue. In the given exercise:
- The series \(\sum_{n=0}^{\infty}\left(-\frac{1}{2}\right)^{n}\) continues without end, aiming to find a sum.
- To convert this to a finite sum, we need to determine if the series is convergent.
Common Ratio
The Common Ratio is a key component of a geometric series. It dictates the constant factor between any two consecutive terms. In the exercise, the common ratio is \(-\frac{1}{2}\). This tells us:
- Each term is half the previous one, and negative, which alternates the sign.
- The absolute value of the common ratio, \(\left| -\frac{1}{2} \right| = \frac{1}{2}\), is less than 1.
Other exercises in this chapter
Problem 36
Use a power series and the fact that \(i^{2}=-1\) to verify the formula. $$ g(x)=\frac{1}{2}\left(e^{i x}+e^{-i x}\right)=\cos x $$
View solution Problem 36
Determine whether the series converges conditionally or absolutely, or diverges. $$ \sum_{n=0}^{\infty}(-1)^{n} e^{-n^{2}} $$
View solution Problem 37
Determine the convergence or divergence of the sequence with the given \(n\) th term. If the sequence converges, find its limit. \(a_{n}=\frac{1 \cdot 3 \cdot 5
View solution Problem 37
In Exercises \(35-38,\) write an equivalent series with the index of summation beginning at \(n=1\). $$ \sum_{n=0}^{\infty} \frac{x^{2 n+1}}{(2 n+1) !} $$
View solution