Problem 37
Question
Find the following products and express answers in simplest radical form. All variables represent nonnegative real numbers. \((2 \sqrt{6}+3 \sqrt{5})(\sqrt{8}-3 \sqrt{12})\)
Step-by-Step Solution
Verified Answer
The simplest radical form is \(8\sqrt{3} - 36\sqrt{2} + 6\sqrt{10} - 18\sqrt{15}\).
1Step 1: Use the Distributive Property
To find the product, we distribute each term in the first binomial with each in the second. We calculate: 1. \(2\sqrt{6} \times \sqrt{8} \)2. \(2\sqrt{6} \times (-3\sqrt{12}) \)3. \(3\sqrt{5} \times \sqrt{8} \)4. \(3\sqrt{5} \times (-3\sqrt{12}) \)
2Step 2: Calculate Each Term
Calculate each of the terms determined in Step 1:1. \(2\sqrt{6} \cdot \sqrt{8} = 2 \sqrt{48} = 2 \cdot 4\sqrt{3} = 8\sqrt{3}\)2. \(2\sqrt{6} \cdot (-3\sqrt{12}) = -6\sqrt{72} = -6 \cdot 6\sqrt{2} = -36\sqrt{2}\)3. \(3\sqrt{5} \cdot \sqrt{8} = 3\sqrt{40} = 3 \cdot 2\sqrt{10} = 6\sqrt{10}\)4. \(3\sqrt{5} \cdot (-3\sqrt{12}) = -9\sqrt{60} = -9 \cdot 2\sqrt{15} = -18\sqrt{15}\)
3Step 3: Combine Like Terms
After simplifying the terms from Step 2:1. \(8\sqrt{3}\)2. \(-36\sqrt{2}\)3. \(6\sqrt{10}\)4. \(-18\sqrt{15}\)These terms are not like terms, so they cannot be combined further. The expression in its simplest radical form is:\(8\sqrt{3} - 36\sqrt{2} + 6\sqrt{10} - 18\sqrt{15}\)
Key Concepts
Distributive PropertyBinomial MultiplicationRadical SimplificationCombining Like Terms
Distributive Property
The distributive property is a key concept in algebra that helps us to multiply terms efficiently. When you have two binomials, such as \((a + b)(c + d)\), the distributive property allows you to multiply each term in the first binomial by each term in the second binomial. This is sometimes known as expanding the expression.
To apply the distributive property, simply move through each term systematically:
To apply the distributive property, simply move through each term systematically:
- First, multiply the first term of the first binomial by each term of the second binomial.
- Second, multiply the second term of the first binomial by each term of the second binomial.
- \(2 \sqrt{6} \times \sqrt{8}\), \(2 \sqrt{6} \times (-3 \sqrt{12})\), \(3 \sqrt{5} \times \sqrt{8}\), \(3 \sqrt{5} \times (-3 \sqrt{12})\).
Binomial Multiplication
Binomial multiplication goes hand-in-hand with the distributive property. When you're working with binomials, you're essentially dealing with an expression that includes two terms.
When multiplying two binomials, like in the example with radicals, you use the distributive property to expand before simplifying. It's like unfolding a box that has two terms on each side. After expanding, each of the original terms interacts with every other term across the binomials.
For instance, after distributing \((2 \sqrt{6} + 3 \sqrt{5})(\sqrt{8} - 3 \sqrt{12})\), you will have multiple terms: \[2 \sqrt{6} \times \sqrt{8}, \quad 2 \sqrt{6} \times (-3 \sqrt{12}), \quad 3 \sqrt{5} \times \sqrt{8}, \quad 3 \sqrt{5} \times (-3 \sqrt{12}).\] This comprehensive step ensures no term is left out and sets the stage for subsequent simplification.
When multiplying two binomials, like in the example with radicals, you use the distributive property to expand before simplifying. It's like unfolding a box that has two terms on each side. After expanding, each of the original terms interacts with every other term across the binomials.
For instance, after distributing \((2 \sqrt{6} + 3 \sqrt{5})(\sqrt{8} - 3 \sqrt{12})\), you will have multiple terms: \[2 \sqrt{6} \times \sqrt{8}, \quad 2 \sqrt{6} \times (-3 \sqrt{12}), \quad 3 \sqrt{5} \times \sqrt{8}, \quad 3 \sqrt{5} \times (-3 \sqrt{12}).\] This comprehensive step ensures no term is left out and sets the stage for subsequent simplification.
Radical Simplification
Simplifying radical expressions is essential to make expressions easier to work with. A radical expression typically involves a number within a square root. To simplify it, find the largest perfect square that divides the number under the radical and rewrite it.
For example, consider \(\sqrt{72}\):
For example, consider \(\sqrt{72}\):
- The largest perfect square factor of 72 is 36.
- Rewrite \(\sqrt{72}\) as \(\sqrt{36 \times 2}\).
- This simplifies further to \(6\sqrt{2}\).
Combining Like Terms
After simplifying radical expressions, the next step is to combine like terms. However, unlike regular addition or subtraction, terms under a square root can only be combined if they contain the same radical part.
In our example, the terms \(8\sqrt{3}, -36\sqrt{2}, 6\sqrt{10},\) and \(-18\sqrt{15}\) each have different radical parts (\(\sqrt{3}\), \(\sqrt{2}\), \(\sqrt{10}\), \(\sqrt{15}\)). This means:
In our example, the terms \(8\sqrt{3}, -36\sqrt{2}, 6\sqrt{10},\) and \(-18\sqrt{15}\) each have different radical parts (\(\sqrt{3}\), \(\sqrt{2}\), \(\sqrt{10}\), \(\sqrt{15}\)). This means:
- They are not like terms, and thus, cannot be added or subtracted to yield a simpler expression directly.
Other exercises in this chapter
Problem 37
Write each of the following in radical form. For example, \(3 x^{\frac{2}{3}}=3 \sqrt[3]{x^{2}}\). \((2 x-3 y)^{\frac{1}{2}}\)
View solution Problem 37
Solve each equation. Don't forget to check each of your potential solutions. \(\sqrt{n+4}=n+4\)
View solution Problem 37
Express each of the following in simplest radical form. All variables represent positive real numbers. \(\sqrt{\frac{2 x}{5 y}}\)
View solution Problem 37
Change each radical to simplest radical form. \(-\frac{5}{6} \sqrt{28}\)
View solution