Problem 37
Question
Factor each trinomial, or state that the trinomial is prime. $$6 x^{2}-5 x y-6 y^{2}$$
Step-by-Step Solution
Verified Answer
The factored form of \(6x^2 - 5xy - 6y^2\) is \((x - y)(6x + y)\)
1Step 1: Checking If the Trinomial Can Be Factored
Find two numbers that multiply to -36 and add to -5. The numbers -6 and 6 satisfy these conditions. Thus, the trinomial can be factored.
2Step 2: Apply Grouping
Rewrite the middle term of the trinomial as \(-6xy + xy\). Now, the expression becomes \(6x^2 - 6xy + xy - 6y^2\). Group the terms two by two, giving two groups \(6x^2 - 6xy\) and \(+ xy - 6y^2\).
3Step 3: Factor Common Factors from Each Group
From the first group: \(6x^2 - 6xy = 6x(x - y)\). From the second group: \(xy - 6y^2 = y(x - y)\). So the original trinomial becomes \(6x(x - y) + y(x - y)\).
4Step 4: Factor Common Factors Again
In the expression \(6x(x - y) + y(x - y)\), notice that we have a common factor of \(x - y\). Factor this out, giving \((x - y)(6x + y)\), which are the two binomials.
Other exercises in this chapter
Problem 36
List all numbers from the given set that are a. natural numbers, b. whole numbers, c. integers, d. rational numbers, e. irrational numbers, f. real numbers. $$\
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add or subtract as indicated. $$ \frac{4 x-10}{x-2}-\frac{x-4}{x-2} $$
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Add or subtract terms whenever possible. $$ \sqrt{8}+3 \sqrt{2} $$
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In Exercises 15–58, find each product. $$ \left(4 x^{2}+5 x\right)\left(4 x^{2}-5 x\right) $$
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