Problem 37
Question
Factor completely. Identify any prime polynomials. $$ 3 d^{2}+3 d-5 $$
Step-by-Step Solution
Verified Answer
The polynomial 3d^2 + 3d - 5 is a prime polynomial.
1Step 1: Identify and write down the polynomial
The given polynomial is: \[3d^2 + 3d - 5\].
2Step 2: Calculate the discriminant
Use the discriminant formula for a quadratic polynomial, which is given by: \[ \text{Discriminant} = b^2 - 4ac \]. For the polynomial \[3d^2 + 3d - 5\], the coefficients are: \( a = 3 \), \( b = 3 \), and \( c = -5 \). Calculating the discriminant: \[ 3^2 - 4 \times 3 \times (-5) = 9 + 60 = 69 \].
3Step 3: Analyze the discriminant
Since the discriminant \(69\) is not a perfect square, the quadratic does not factorize nicely with integer coefficients.
4Step 4: Conclusion on factorization
Given that the discriminant is not a perfect square, it can be concluded that the polynomial \[3d^2 + 3d - 5\] does not factorize further and is therefore a prime polynomial.
Key Concepts
discriminantquadratic polynomialprime polynomial
discriminant
The discriminant is a special number that you can calculate from the coefficients of a quadratic polynomial to determine several key properties of the polynomial. The formula for the discriminant is given by: discriminant = b^2 - 4ac To put it simply, the discriminant helps us decide if a quadratic equation can be factorized into real numbers (numbers you can plot on a regular number line). Let's look at the polynomial 3d^2 + 3d - 5. to understand the discriminant's role better. Here, a is 3, b is 3, and c is -5. When we plug these into the formula, we get: discriminant = 3^2 - 4 ⋅ 3 ⋅ -5 = 9 + 60 = 69. Since 69 is not a perfect square, the quadratic polynomial does not factorize into nice integers. This leads us directly to the prime polynomial concept, because the discriminant tells us a lot about how the polynomial behaves.
When the discriminant is a
When the discriminant is a
- positive perfect square, the polynomial factorizes nicely,
- positive but not a perfect square, factorizing into irrational numbers,
- zero, it simplifies to a squared binomial,
- negative, it has no real roots but complex ones instead.
quadratic polynomial
A quadratic polynomial is one where the highest power of the variable (often labeled x or d) is 2. The standard form is written as ax^2 + bx + c, where a, b, and c are coefficients. You encounter quadratic polynomials in many areas of math, including algebra, geometry, and calculus.
For the quadratic polynomial 3d^2 + 3d - 5, here's the breakdown:
For the quadratic polynomial 3d^2 + 3d - 5, here's the breakdown:
- a = 3 (the coefficient in front of d^2),
- b = 3 (the coefficient in front of d),
- c = -5 (the constant term).
prime polynomial
A prime polynomial is much like a prime number in arithmetic. It cannot be factored into the product of two lower-degree polynomials with integer coefficients. In the case of integer coefficients, a prime polynomial does not break down into simpler polynomials that multiply to give the original polynomial.
For 3d^2 + 3d - 5, the discriminant calculation showed that 69 is not a perfect square. This means we can't factor the polynomial into simpler factors with integer coefficients. Therefore, the polynomial is considered a prime polynomial.
Understanding prime polynomials helps you identify when you can no longer break down an equation, simplifying the problem-solving process. When dealing with prime polynomials, remember:
For 3d^2 + 3d - 5, the discriminant calculation showed that 69 is not a perfect square. This means we can't factor the polynomial into simpler factors with integer coefficients. Therefore, the polynomial is considered a prime polynomial.
Understanding prime polynomials helps you identify when you can no longer break down an equation, simplifying the problem-solving process. When dealing with prime polynomials, remember:
- The discriminant helps decide factorability,
- If factorable, the breakdown will give us simpler binomials,
- If not factorable (like 3d^2 + 3d - 5), it remains prime.
Other exercises in this chapter
Problem 36
(a) factor out the greatest common factor. Identify any prime polynomials. (b) check. $$ 48 v^{3}+56 v^{2}+32 v $$
View solution Problem 37
(a) solve. (b) check. $$ y^{2}+8 y+12=0 $$
View solution Problem 37
For exercises 37-46, use a pattern to factor. Check. Identify any prime polynomials. $$ x^{3}+125 $$
View solution Problem 37
Use the \(a c\) method to factor. Check the factoring. Identify any prime polynomials. $$ 9 w^{2}-18 w+5 $$
View solution