Problem 37
Question
Exercises \(33-38:\) Write a formula for a linear function f whose graph satisfies the conditions. Slope 0.5, passing through \((1,4.5)\)
Step-by-Step Solution
Verified Answer
The linear function is \( f(x) = 0.5x + 4 \).
1Step 1: Understand the Linear Function Formula
A linear function can be expressed in the slope-intercept form: \( f(x) = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
2Step 2: Identify Given Information
From the problem, we are given that the slope \( m = 0.5 \) and the line passes through the point \((1, 4.5)\).
3Step 3: Substitute the Slope Into the Formula
We first substitute the slope into the formula, giving us \( f(x) = 0.5x + b \).
4Step 4: Solve for the Y-Intercept (b)
Use the point \((1, 4.5)\) to find \( b \). Substitute \( x = 1 \) and \( f(x) = 4.5 \) into the equation: \[ 4.5 = 0.5 imes 1 + b \]Solving this gives:\[ 4.5 = 0.5 + b \]\[ b = 4.5 - 0.5 = 4 \]
5Step 5: Write the Final Linear Function
Now with \( b = 4 \), we can write the linear function as:\[ f(x) = 0.5x + 4 \]
Key Concepts
Slope-Intercept FormGraphing Linear EquationsSolving for Y-Intercept
Slope-Intercept Form
The slope-intercept form is a way of expressing linear equations using a simple and standardized formula. It's written as \( f(x) = mx + b \). Here, \( m \) represents the slope of the line, which indicates how steep the line is. The slope tells us how much the value of \( y \) changes when \( x \) increases by one unit.
The \( b \) in the formula signifies the y-intercept. The y-intercept is the point where the line crosses the y-axis. This point is vital because it gives us a starting position when sketching the graph of the line.
This form is beneficial because it provides direct insight into the characteristics of a line. It easily shows both how steep the line is and exactly where it begins on the y-axis. It is often used when quickly sketching graphs or analyzing linear equations.
The \( b \) in the formula signifies the y-intercept. The y-intercept is the point where the line crosses the y-axis. This point is vital because it gives us a starting position when sketching the graph of the line.
This form is beneficial because it provides direct insight into the characteristics of a line. It easily shows both how steep the line is and exactly where it begins on the y-axis. It is often used when quickly sketching graphs or analyzing linear equations.
Graphing Linear Equations
Graphing linear equations can be straightforward once you understand the slope-intercept form \( f(x) = mx + b \). The formula gives us all the information needed to plot a line accurately.
First, identify the y-intercept \( b \). This point is plotted directly on the y-axis. From this starting point, use the slope \( m \) to determine the next point. The slope is a ratio often expressed as a fraction \( \frac{rise}{run} \).
First, identify the y-intercept \( b \). This point is plotted directly on the y-axis. From this starting point, use the slope \( m \) to determine the next point. The slope is a ratio often expressed as a fraction \( \frac{rise}{run} \).
- If \( m = 0.5 \), interpret this as \( \frac{1}{2} \). For every 2 units you move along the x-axis, go up 1 unit on the y-axis.
- Plot the second point using this method.
Solving for Y-Intercept
Solving for the y-intercept is an important step in determining the full equation of a line. When you have the slope \( m \) and a single point such as \((1, 4.5)\) through which the line passes, the y-intercept \( b \) can be determined using the formula \( f(x) = mx + b \).
To find \( b \), substitute the given point into the equation. Place \( x = 1 \) and \( f(x) = 4.5 \) into the equation: \[ 4.5 = 0.5 \times 1 + b \]
From here, solve the equation by isolating \( b \).
To find \( b \), substitute the given point into the equation. Place \( x = 1 \) and \( f(x) = 4.5 \) into the equation: \[ 4.5 = 0.5 \times 1 + b \]
From here, solve the equation by isolating \( b \).
- Calculate \( 0.5 \times 1 \), which equals 0.5.
- Subtract 0.5 from 4.5 to solve for \( b \).
- Therefore, \( b = 4 \).
Other exercises in this chapter
Problem 37
Find the slope-intercept form for the line satisfying the conditions. Perpendicular to the line \(y=-\frac{2}{3}(x-1980)+5\) passing through \((1980,10)\)
View solution Problem 37
Solve the inequality symbolically. Express the solution set in set-builder or interval notation. $$ \frac{1}{2} z+\frac{2}{3}(3-z)-\frac{5}{4} z \geq \frac{3}{4
View solution Problem 38
Solve the absolute value equation. $$\left|\frac{1}{2} x+\frac{3}{2}\right|=\left|\frac{3}{2} x-\frac{7}{2}\right|$$
View solution Problem 38
Solve the equation and check your answer. $$ 0.35 t+0.65(10-t)=0.55(10) $$
View solution