Problem 37
Question
Does the graph of $$f(x)=\left\\{\begin{aligned}-1, & x<0 \\\0, & x=0 \\\1, & x>0\end{aligned}\right.$$ have a vertical tangent at the origin? Give reasons for your answer.
Step-by-Step Solution
Verified Answer
No, the graph does not have a vertical tangent at the origin because the derivative is zero on both sides and doesn't exist at the origin.
1Step 1: Understanding the Problem
We need to determine if the piecewise function \(f(x)\) has a vertical tangent at the origin \((0,0)\). A vertical tangent occurs when the derivative approaches infinity or negative infinity at that point.
2Step 2: Analyzing the Function
The given function \( f(x) \) is defined as a piecewise function: \(-1\) for \( x < 0 \), \(0\) for \( x = 0 \), and \(1\) for \( x > 0 \). The function makes a jump at \( x = 0 \).
3Step 3: Considering Derivatives
Since the function has a different constant value on either side of zero (-1 for \( x < 0 \) and 1 for \( x > 0 \)), its derivative does not exist at \( x = 0 \). For \( x < 0 \) and \( x > 0 \), the derivative of a constant is zero.
4Step 4: Conclusion
Because the derivative of the function is zero for \( x < 0 \) and \( x > 0 \) and the function is not differentiable at \( x = 0 \) due to the jump from -1 to 1, there is no vertical tangent at the origin.
Key Concepts
Piecewise FunctionVertical TangentDerivative
Piecewise Function
A piecewise function is a type of function that has different expressions or "pieces" for different intervals of its domain. This means that the rule for computing the function value changes depending on the input. For the function given in the exercise:
- When the input \( x \) is less than 0, the function value is -1.
- At exactly 0, the function value is 0.
- For anything greater than 0, it changes to 1.
Vertical Tangent
A vertical tangent is a special type of tangent line to a curve at a point where the curve becomes vertical. In mathematical terms, this occurs when the slope of the tangent line approaches infinity or negative infinity at that point.
For finding a vertical tangent in a function:
- The first step is to compute the derivative of the function.
- Check for points where the derivative doesn't exist or tends towards infinity.
Derivative
A derivative represents the rate of change or the slope of a function at a specific point. It provides valuable information about the function's behavior and is fundamental in calculus.For piecewise functions, derivatives need special attention because the function is defined by different rules in different intervals. Here are key points to remember:
- The derivative of a constant function is zero.
- At points of discontinuity, like with the given exercise, the derivative may not exist.
- Analyzing each specific piece and its limits can reveal important behavior trends.
Other exercises in this chapter
Problem 37
Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given point. $$2 x y+\pi \sin y=2 \pi, \q
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Graph the curves over the given intervals, together with their tangents at the given values of \(x\). Label each curve and tangent with its equation. $$\begin{a
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Find the derivatives of the function. $$y=\sqrt[7]{x^{2}}-x^{e}$$
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Find the derivative of \(y\) with respect to the appropriate variable. $$y=\sqrt{s^{2}-1}-\sec ^{-1} s$$
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