Problem 37
Question
Determine whether the system of linear equations is inconsistent or dependent. If it is dependent, find the complete solution. $$ \left\\{\begin{array}{l}{2 x+y-2 z=12} \\ {-x-\frac{1}{2} y+z=-6} \\ {3 x+\frac{3}{2} y-3 z=18}\end{array}\right. $$
Step-by-Step Solution
Verified Answer
The system is dependent; solutions are parameterized by \((x, 12 - 2x + 2t, t)\).
1Step 1: Express System in Augmented Matrix Form
Write the given system of equations in an augmented matrix form:\[\begin{bmatrix} 2 & 1 & -2 & | & 12 \ -1 & -\frac{1}{2} & 1 & | & -6 \3 & \frac{3}{2} & -3 & | & 18\end{bmatrix}\]
2Step 2: Row Reduce to Row-Echelon Form
Use row operations to transform the matrix to row-echelon form. Start by eliminating the first column below the pivot in the first row:1. Multiply the second row by 2 and add it to the first row: \[ \begin{bmatrix} 2 & 1 & -2 & | & 12 \ 0 & 0 & 0 & | & 0 \ 3 & \frac{3}{2} & -3 & | & 18 \end{bmatrix} \]2. Eliminate the first column in the third row by multiplying the first row by -3/2 and adding it to the third row: \[ \begin{bmatrix} 2 & 1 & -2 & | & 12 \ 0 & 0 & 0 & | & 0 \ 0 & 0 & 0 & | & 0 \end{bmatrix} \]
3Step 3: Interpret Row-Echelon Form
Analyze the resulting row-echelon form. The third row is all zeros, indicating redundancy. The second row is also all zeros, confirming there are infinitely many solutions. Thus, the system is dependent.
4Step 4: Solve for Dependent Variables
Use the non-zero row to express one variable in terms of the others. From the first row \(2x + y - 2z = 12\), express: \[ y = 12 - 2x + 2z \]Thus the variables can be expressed in terms of a parameter \(z=t\):- Let \(z = t\).- Then \(x\) is any real number subject to \(2x + y - 2t = 12\).- \(y = 12 - 2x + 2t\).Thus, any solution can be written as:\[(x, y, z) = (x, 12 - 2x + 2t, t), \text{ where } x, t \in \mathbb{R}.\]
5Step 5: Conclusion
The system is dependent with solutions as parameterized linear combinations of the variable \(z\).
Key Concepts
Dependent SystemAugmented MatrixRow-Echelon FormInfinitely Many Solutions
Dependent System
In linear algebra, a system of linear equations can fall into different categories: consistent, inconsistent, or dependent. A dependent system is a set of equations where all the equations are essentially the same line in a geometric sense. This means that each equation in the system provides the same solution or can be derived from one another. This type of system doesn't have a unique solution but rather infinitely many solutions, which satisfy all the given equations in the system.
For example, if one equation in the system is a multiple or a linear combination of another, the system is dependent. This occurs because the lines represented by the equations overlap entirely. Therefore, instead of intersecting at a single point, they coincide, leading to infinitely many solutions that lie along the line they form.
For example, if one equation in the system is a multiple or a linear combination of another, the system is dependent. This occurs because the lines represented by the equations overlap entirely. Therefore, instead of intersecting at a single point, they coincide, leading to infinitely many solutions that lie along the line they form.
Augmented Matrix
An augmented matrix is a compact and organized way to represent a system of linear equations. By turning a system of equations into an augmented matrix, we can use matrix operations to solve it more efficiently. An augmented matrix is formatted to combine the coefficients of the variables and the constants from the equations.
For instance, given the linear equations:
For instance, given the linear equations:
- 2x + y - 2z = 12
- -x - \(\frac{1}{2}\)y + z = -6
- 3x + \(\frac{3}{2}\)y - 3z = 18
Row-Echelon Form
The row-echelon form is a specific arrangement of a matrix used to simplify solving linear equations. It's achieved through a series of elementary row operations: swapping rows, multiplying a row by a non-zero scalar, and adding or subtracting the multiples of rows from others.
In the row-echelon form:
In the row-echelon form:
- All rows having leading entries (the first non-zero number from the left in a row) are arranged such that they progress diagonally downwards to the right.
- Any zero rows are placed at the bottom of the matrix.
- The leading entry of a non-zero row is always to the right of the leading entry in the row above.
Infinitely Many Solutions
When a system of linear equations has infinitely many solutions, it means there are infinitely many sets of values for the variables that satisfy all the equations. This scenario typically arises in dependent systems, where the equations define overlapping lines in the solution space.
Infinitely many solutions are often found by expressing the variables in terms of free parameters (like a parameter \(t\)). In our example, we concluded that for one of the variables expressed as \(z = t\), others can be written in terms of it:
Infinitely many solutions are often found by expressing the variables in terms of free parameters (like a parameter \(t\)). In our example, we concluded that for one of the variables expressed as \(z = t\), others can be written in terms of it:
- \(x\) can be any real number, constrained by equations, \(2x + y - 2t = 12\)
- \(y = 12 - 2x + 2t\)
Other exercises in this chapter
Problem 37
Use Cramer’s Rule to solve the system. $$ \left\\{\begin{array}{l}{0.4 x+1.2 y=0.4} \\ {1.2 x+1.6 y=3.2}\end{array}\right. $$
View solution Problem 37
21-46 . Graph the solution of the system of inequalities. Find the coordinates of all vertices, and determine whether the solution set is bounded. $$ \left\\{\b
View solution Problem 37
\(33-40=\) Use the graphical method to find all solutions of the system of equations, rounded to two decimal places. $$ \left\\{\begin{array}{l}{\frac{x^{2}}{9}
View solution Problem 37
\(13-44=\) Find the partial fraction decomposition of the rational function. $$ \frac{x-3}{x^{3}+3 x} $$
View solution