Problem 37
Question
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$4,9,14,19, \dots$$
Step-by-Step Solution
Verified Answer
The common difference is 5. The fifth term is 24. The 100th term is 499.
1Step 1: Identify the Common Difference
In an arithmetic sequence, the common difference is the difference between any two consecutive terms. You can find it by subtracting the first term from the second term. Here, the first term is 4 and the second term is 9. So:\[ d = 9 - 4 = 5 \]The common difference of the arithmetic sequence is 5.
2Step 2: Calculate the Fifth Term
To find the fifth term of an arithmetic sequence, use the formula for the \(n\)th term, which is \(a_n = a_1 + (n-1) \, d \). Here, \(a_1 = 4\) and \(d = 5\), and you want the fifth term, so \(n = 5\):\[ a_5 = 4 + (5-1) \, 5 = 4 + 4 \, imes \, 5 = 4 + 20 = 24 \]So, the fifth term is 24.
3Step 3: Derive the General Formula for the n-th Term
The general formula for the \(n\)th term of an arithmetic sequence is given by \(a_n = a_1 + (n-1) \, d \). For this sequence, the first term \(a_1\) is 4 and the common difference \(d\) is 5. Therefore, the formula is:\[ a_n = 4 + (n-1) \, 5 \]Simplifying this, we get:\[ a_n = 4 + 5n - 5 = 5n - 1 \]
4Step 4: Find the 100th Term Using the General Formula
Now that we have the general formula \(a_n = 5n - 1\), substitute \(n = 100\) to find the 100th term:\[ a_{100} = 5(100) - 1 = 500 - 1 = 499 \]Thus, the 100th term of the sequence is 499.
Key Concepts
Common DifferenceGeneral Term FormulaNth Term Calculation
Common Difference
In an arithmetic sequence, the common difference is the constant amount that each term increases by to get to the next term. It's like stepping up a staircase where each step is the same height. To find the common difference, you subtract the preceding term from the succeeding term.
Let's look at an example:
Let's look at an example:
- The sequence given is 4, 9, 14, 19, ...
- To find the common difference, subtract the first term from the second term:
- \[ d = 9 - 4 = 5 \]
General Term Formula
The general term formula allows us to find any term in an arithmetic sequence without listing all previous terms. This formula is a useful tool since it provides a quick way to jump directly to any term position we want.
The formula for the general term of an arithmetic sequence is:
\[ a_n = 4 + (n-1) \, 5 \]
Simplify it:
\[ a_n = 5n - 1 \]
This simplified formula helps you find the \( n \)-th term directly.
The formula for the general term of an arithmetic sequence is:
- \[ a_n = a_1 + (n-1) \, d \]
- Where:
- \( a_n \) is the term you're looking to find.
- \( a_1 \) is the first term of the sequence.
- \( d \) is the common difference.
- \( n \) is the term’s position in the sequence.
\[ a_n = 4 + (n-1) \, 5 \]
Simplify it:
\[ a_n = 5n - 1 \]
This simplified formula helps you find the \( n \)-th term directly.
Nth Term Calculation
Calculating the \( n \)-th term of an arithmetic sequence is straightforward with the help of the general term formula. Let's see how to find the 5th term and even the 100th with the earlier formula.
- Start by using the formula: \[ a_n = 5n - 1 \]
- For the 5th term (\( n = 5 \)):
- \[ a_5 = 5(5) - 1 = 25 - 1 = 24 \]
- Plug \( n = 100 \) into the formula:
- \[ a_{100} = 5(100) - 1 = 500 - 1 = 499 \]
Other exercises in this chapter
Problem 36
Find the indicated terms in the expansion of the given binomial. The 28 th term in the expansion of \((A-B)^{30}\).
View solution Problem 36
Find the \(n\)th term of a sequence whose first several terms are given. \(\frac{3}{4}, \frac{4}{5}, \frac{5}{6}, \frac{6}{7}, \dots\)
View solution Problem 37
Determine whether each statement is true or false. If you think the statement is true, prove it. If you think it is false, give an example in which it fails. (a
View solution Problem 37
Find the \(n\)th term of a sequence whose first several terms are given. \(0,2,0,2,0,2, \dots\)
View solution