Problem 37
Question
Decide how many solutions the equation has. $$x^{2}-2 x-15=0$$
Step-by-Step Solution
Verified Answer
The equation \(x^{2}-2x-15=0\) has two solutions.
1Step 1: Identify the coefficients
The quadratic equation is in the form \(ax^{2}+bx+c=0\). For our equation, \(x^{2}-2x-15=0\), the coefficients are \(a=1, b=-2,\) and \(c=-15\).
2Step 2: Compute the discriminant
Compute the discriminant D using the formula \(D=b^{2}-4ac\). In our case, D is \((-2)^{2} - 4*1*(-15)\) which simplifies to \(4+60=64\).
3Step 3: Find the number of solutions
Because our discriminant D is positive, this means our equation \(x^{2}-2x-15=0\) has two distinct solutions.
Key Concepts
Understanding the DiscriminantRole of CoefficientsDetermining the Number of Solutions
Understanding the Discriminant
A discriminant is a very important part of solving quadratic equations. It is denoted by the letter \( D \) and reveals the nature of the roots of the equation. To compute the discriminant, use the formula:
- \( D = b^2 - 4ac \)
- \( D = (-2)^2 - 4 \times 1 \times (-15) = 4 + 60 = 64 \)
Role of Coefficients
Coefficients are the numbers in front of the variables in the quadratic equation \( ax^2 + bx + c = 0 \). These numbers define the shape and position of the parabola represented by the equation. Let's break down the coefficients in our equation \( x^2 - 2x - 15 = 0 \):
- \( a = 1 \), the coefficient of \( x^2 \), determines the direction of the parabola. Since \( a \) is positive, the parabola opens upwards.
- \( b = -2 \), the coefficient of \( x \), affects the position of the vertex and the axis of symmetry.
- \( c = -15 \), the constant term, indicates the y-intercept. This is the point where the parabola crosses the y-axis.
Determining the Number of Solutions
The number of solutions for a quadratic equation depends directly on the discriminant value (\( D \)). The discriminant helps determine the nature of the solutions:
- If \( D > 0 \), the equation has two distinct real solutions.
- If \( D = 0 \), there is exactly one real solution, also known as a repeated or double root.
- If \( D < 0 \), the equation has no real solutions and results in two complex solutions.
Other exercises in this chapter
Problem 37
Solve the equation. Check for extraneous solutions. $$x=\sqrt{-4 x-4}$$
View solution Problem 37
Find the midpoint between the two points \((-1,2),(7,4)\)
View solution Problem 37
SUBTRACTING VERTICALLY Use a vertical format to subtract the second polynomial from the first polynomial. $$4 x^{3}+3 x^{2}+8 x+6,2 x^{3}-3 x^{2}-7 x$$
View solution Problem 37
Find the domain of the function. $$y=4 \sqrt{x}$$
View solution